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Chắc sai đề ? Phải là:
3x2 + 2y2 + 7xy
= 3x2 + 2y2 + 6xy + xy
= ( 3x2 + 6xy ) + ( 2y2 + xy )
= 3x ( x + 2y ) + y ( 2y + x )
= ( 3x + y ) ( x + 2y )
\(2x^2-4xy-xy+2y^2=2x\left(x-2y\right)-y\left(x-2y\right)=\left(x-2y\right)\left(2x-y\right)\)
a) -7x2 + 5xy +12y2
=-7x2-7xy+12xy+12y2
=-7x(x+y)+12y(x+y)
=(x+y)(12y-7x)
b) x8 + 3x4 + 4
=x8+4x4+4-x4
=(x4+2)2-x4
=(x4-x2+2)(x4+x2+2)
=(x4+x2-2x2+2)(x4+x2+2)
=[x2(x+1)-2(x+1)](x4+x2+1)
=(x+1)(x2-2)(x4+x2+1)
a) 5x2 - 5xy - 3x + 3y
= 5x.(x - y) - 3.(x - y)
= (x - y).(5x - 3)
b) x3 - 2x2 - x + 2
= x2.(x - 2) - (x - 2)
= (x - 2).(x2 - 1)
= (x - 2).(x - 1).(x + 1)
a/ 5x2-5xy-3x+3y
=5x.(x-y)-3(x-y)
=(5x-3).(x-y)
b/ x3-2x2-x+2
=x2.(x-2)-(x-2)
=(x2-1).(x-2)
=(x-1).(x+1).(x-2)
a) 6x2 - 11x + 3
= 6x2 - 9x - 2x + 3
= 3x ( 2x - 3 ) - ( 2x - 3 )
= ( 2x - 3 ) ( 3x - 1 )
b ) 2x2 + 3x - 27
= 2x2 - 6x + 9x - 27
= 2x ( x - 3 ) + 9 ( x - 3 )
= ( x - 3 ) ( 2x + 9 )
c ) 2x2 - 5xy - 3y2
= 2x2 - 2xy - 3xy - 3y2
= 2x ( x - y ) - 3y ( x - y )
= ( x - y ) ( 2x - 3y )
Ta có:
a) 6x2 - 11x +3 = 2x(3x-1)-3(3x-1)=(2x-3)(3x-1)
b) 2x2 +3x - 27= x(2x+9)-3(2x+9)=(x-3)(2x+9)
c) 2x2 -5xy-3y2 = 2x(x-3y)+y(x-3y)=(2x+y)(x-3y)
\(3x^2+2y^2=5xy\)
\(\Rightarrow3x^2+2y^2-5xy=0\)
\(\Rightarrow3x^2-3xy-2xy+2y^2=0\)
\(\Rightarrow3x\left(x-y\right)-2y\left(x-y\right)=0\)
\(\Rightarrow\left(x-y\right)\left(3x-2y\right)=0\)
\(3x^2+2y^2=5xy\)
\(\Rightarrow3x^2-5xy+2y^2=0\)
\(\Rightarrow3x^2-3xy-2xy+2y^2=0\)
\(\Rightarrow3x\left(x-y\right)-2y\left(x-y\right)=0\)
\(\Rightarrow\left(x-y\right)\left(3x-2y\right)=0\)