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a) \(\left(x-7\right)\left(x+2\right)\)
b) \(\left(2x-3\right)\left(x+2\right)\)
\(x^2-5x+6\)
\(=x^2-5x+\frac{25}{4}-\frac{1}{4}\)
\(=\left(x-\frac{5}{2}\right)^2-\left(\frac{1}{2}\right)^2\)
\(=\left(x-\frac{5}{2}-\frac{1}{2}\right)\left(x-\frac{5}{2}+\frac{1}{2}\right)\)
\(=\left(x-3\right)\left(x-2\right)\)
\(x^2-5x+6 \)
= \(x^2-2x-3x+6\)
= \(\left(x^2-2x\right)-\left(3x-6\right)\)
= \(x\left(x-2\right)-3\left(x-2\right)\)
= \(\left(x-2\right)\left(x-3\right)\)
a) \(x^2-5x+6=x^2-2x-3x+6=x\left(x-2\right)-3\left(x-2\right)=\left(x-2\right)\left(x-3\right)\)
b) \(x^2+x-12=x^2+4x-3x-12=x.\left(x+4\right)-3.\left(x+4\right)=\left(x+4\right)\left(x-3\right)\)
a, x2 - 2x + 1 - y2
= ( x - 1)2 - y2
= (x - 1 - y)(x - 1 + y )
b, x2 - 5x + 6
= x2 -2x - 3x + 6
= x ( x - 2) - 3( x-2)
= (x - 2)(x - 3)
( x^2-2x )+ (1- y^2)
= x (x - 2 ) + (1-y ) (1+y)
B.
= x^2-2x-3x+6
=x (x -2 ) - 3 (x-2 )
=(x-3) (x-2)
\(=x^2+x-6x+6\\ =x\left(x+1\right)-6\left(x+1\right)\\ =\left(x+1\right)\left(x+6\right)\)