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câu nào mình biết mình trl trc nha:
\(\left(x^2+1\right)^2-4x^2\)
\(=x^4+2x^2+1-4x^2\)
\(=x^4-2x^2+1\)
\(\left(x^2-1\right)^2\)
\(a^2-8a+15\)
\(=\left(a^2-2.4a+4^2\right)-1^2\)
\(=\left(a-4\right)^2-1^2\)
\(=\left(a-4-1\right)\left(a-4+1\right)\)
\(=\left(a-3\right).\left(a-5\right)\)
\(a^2-8a+15\)
\(=a^2-2.a.4+16-1\)
\(=\left(a-4\right)^2-1\)
\(=\left(a-4-1\right)\left(a-4+1\right)\)
\(=\left(a-5\right)\left(a-3\right)\)
\(3x^2-10x-8\)
\(=3x^2-12x+2x-8\)
\(=3x\left(x-4\right)+2\left(x-4\right)\)
\(=\left(3x+2\right)\left(x-4\right)\)
\(-6x^3+18x^2+60x\)
\(=\)\(-6x^3+30x^2-12x^2+60x\)
\(=-6x^2\left(x-5\right)-12x\left(x-5\right)\)
\(=\)\(\left(-6x^2-12x\right)\left(x-5\right)\)
\(=-6x\left(x+2\right)\left(x-5\right)\)
a, \(\left(x+1\right)^2-2\left(x+1\right)\left(y-3\right)+\left(y-3\right)^2=\left[\left(x+1\right)-\left(y-3\right)\right]^2\)
\(=\left(x+1-y+3\right)^2=\left(x-y+4\right)^2\)
b, \(a^2+b^2+2a-2b-2ab=\left(a^2-2ab+b^2\right)+\left(2a-2b\right)\)
\(=\left(a-b\right)^2+2\left(a-b\right)=\left(a-b\right)\left[\left(a-b\right)+2\right]=\left(a-b\right)\left(a-b+2\right)\)
Trả lời:
a, \(27a^2b^2-18ab+3=3\left(9a^2b^2-6ab+1\right)=3\left(3ab-1\right)^2\)
b, \(x^2+2xy+y^2-xz-yz\)
\(=\left(x^2+2xy+y^2\right)-z\left(x+y\right)\)
\(=\left(x+y\right)^2-z\left(x+y\right)\)
\(=\left(x+y\right)\left(x+y-z\right)\)
c, \(a^4+a^3-a^2-a\)
\(=\left(a^4+a^3\right)-\left(a^2+a\right)\)
\(=a^3\left(a+1\right)-a\left(a+1\right)\)
\(=a\left(a+1\right)\left(a^2-1\right)\)
\(=a\left(a+1\right)\left(a-1\right)\left(a+1\right)\)
\(=a\left(a+1\right)^2\left(a-1\right)\)
d, \(a^3-b^3+2b-2a\)
\(=\left(a^3-b^3\right)-\left(2a-2b\right)\)
\(=\left(a-b\right)\left(a^2+ab+b^2\right)-2\left(a-b\right)\)
\(=\left(a-b\right)\left(a^2+ab+b^2-2\right)\)