Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\left(2x^2+4xz-6xy\right)-\left(xy+2yz-3y^2\right)+\left(2z^2+xz-3yz\right)\)
\(2x\left(x+2z-3y\right)-y\left(x+2z-3y\right)+z\left(2z+x-3y\right)\)
\(\left(x+2z-3y\right)\left(2x-y+z\right)\)
\(2x^2-7xy+3y^2+5xz+2z^2-5yz\)
\(=\left(2x^2+4xz-6xy\right)-\left(xy+2yz-3y^2\right)+\left(2z^2+xz-3yz\right)\)
\(=2x\left(x-3y+2z\right)-y\left(x-3y+2z\right)+z\left(x-3y+2z\right)\)
\(=\left(2x-y+z\right)\left(x-3y+2z\right)\)
g: \(=x^4+12x^2+36-25x^2\)
\(=\left(x^2+6\right)^2-25x^2\)
\(=\left(x^2+5x+6\right)\left(x^2-5x+6\right)\)
\(=\left(x-2\right)\left(x-3\right)\left(x+2\right)\left(x+3\right)\)
i: \(x^4+3x^2-2x+3\)
\(=x^4-x^3+x^2+x^3-x^2+x+3x^2-3x+3\)
\(=\left(x^2-x+1\right)\left(x^2+x+3\right)\)
\(b,x^2+y^2-2x-2y-2xy\)
\(=\left(x-y\right)^2-2\left(x-y\right)\)
\(=\left(x-y\right)\left(x-y-2\right)\)
a. \(2a^2+5ab-3b^2-7b-2\)
\(=\left(2a^2+6ab+2a\right)-\left(ab+3b^2+b\right)-\left(2a+6b+2\right)\)
\(=2a\left(a+3b+1\right)-b\left(a+3b+1\right)-2\left(a+3b+1\right)\)
\(=\left(2a-b-2\right)\left(a+3b+1\right)\)
b. \(2x^2-7xy+x+3y^2-3y\)
\(=\left(2x^2-xy\right)-\left(6xy-3y^2\right)+\left(x-3y\right)\)
\(=x\left(2x-y\right)-3y\left(2x-y\right)+\left(x-3y\right)\)
\(=\left(x-3y\right)\left(2x-y\right)+\left(x-3y\right)\)
\(=\left(x-3y\right)\left(2x-y+1\right)\)
c. \(6x^2-xy-2y^2+3x-2y\)
\(=\left(6x^2+3xy\right)-\left(4xy-2y^2\right)+\left(3x-2y\right)\)
\(=3x\left(2x+y\right)-2y\left(2x+y\right)+\left(3x-2y\right)\)
\(=\left(3x-2y\right)\left(2x+y\right)+\left(3x-2y\right)\)
\(=\left(3x-2y\right)\left(2x+y+1\right)\)
a)\(x^2-25y^2-xz-5yz\)
\(=\left(x-5y\right)\left(x+5y\right)-z\left(x+5y\right)\)
\(=\left(x-5y-z\right)\left(x+5y\right)\)
b)\(x^3-2x^2-4x+8\)
\(=x^2\left(x-2\right)-4\left(x-2\right)\)
\(=\left(x-2\right)\left(x^2-4\right)\)
\(=\left(x-2\right)^2\left(x+2\right)\)
a) \(x^2-25y^2-xz-5yz=\left(x^2-25y^2\right)-\left(xz+5yz\right)\)
\(=\left(x+5y\right)\left(x-5y\right)-z\left(x+5y\right)\)
\(=\left(x+5y\right)\left(x-5y-z\right)\)
b)\(x^3-2x^2-4x+8=\left(x^3+8\right)-\left(2x^2+4x\right)\)
\(=\left(x+2\right)\left(x^2-2x+4\right)-2x\left(x+2\right)\)
\(=\left(x+2\right)\left(x^2-4x+4\right)\)
\(=\left(x+2\right)\left(x-2\right)^2\)