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7 tháng 10 2021

\(a,=5\left(x-2y\right)\\ b,=3xy\left(x-2y\right)\\ c,=\left(x-y\right)\left(x+3\right)\\ d,=\left(x-1\right)\left(2x-4x^2\right)=2x\left(1-2x\right)\left(x-1\right)\\ e,=\left(x-2y\right)^2\\ f,=\left(3x-4y\right)\left(3x+4y\right)\\ g,=\left(x-3\right)\left(x^2+3x+9\right)\)

7 tháng 10 2021

a. 5x - 10y 

= 5(x - 2y)

b. 3x2y - 6xy2

= 3xy(x - 2y)

c. x(x - y) - 3(y - x)

= x(x - y) + 3(x - y)

= (x + 3)(x - y)

d. 2x(x - 1) + 4x2(1 - x)

= 2x(x - 1) - 4x2(x - 1)

= (2x - 4x2)(x - 1)

= 2x(1 - 2x)(x - 1)

e. x2 - 4xy + 4y2

= (x - 2y)2

f. 9x2 - 16y2

= (3x - 4y)(3x + 4y)

g. x3 - 27

= (x - 3)(x2 + 3x + 9)

6 tháng 12 2017

a) \(=\left(x-2y\right)\left(x^2+5x\right)\)

b) \(=\left(x-1\right)\left(x^2+2x+1\right)=\left(x-1\right)\left(x+1\right)^2\)

c) \(=\left(x^2+1-2x\right)\left(x^2+1+2x\right)\)

    \(=\left(x^2-2x+1\right)\left(x^2+2x+1\right)\)

    \(=\left(x-1\right)^2\left(x+1\right)^2\)

d) \(=3\left(x+3\right)-\left(x-3\right)\left(x+3\right)\)

     \(=\left(x+3\right)\left(3-x+3\right)\)

     \(=\left(x+3\right)\left(6-x\right)\)

e) \(=\left(x^2-\frac{1}{3}x\right)\left(x^2+\frac{1}{3}x\right)\)

f) \(=2x\left(x-y\right)-16\left(x-y\right)\)

    \(=2\left(x-y\right)\left(x-8\right)\)

  

Bài 7: Phân tích đa thức thành nhân tử

a) Ta có: \(a^2-b^2-2a+2b\)

\(=\left(a-b\right)\left(a+b\right)-2\left(a-b\right)\)

\(=\left(a-b\right)\left(a+b-2\right)\)

b) Ta có: \(3x-3y-5x\left(y-x\right)\)

\(=3\left(x-y\right)+5x\left(x-y\right)\)

\(=\left(x-y\right)\left(3+5x\right)\)

c) Ta có: \(16-x^2+4xy-4y^2\)

\(=16-\left(x^2-4xy+4y^2\right)\)

\(=16-\left(x-2y\right)^2\)

\(=\left(4-x+2y\right)\left(4+x-2y\right)\)

d) Ta có: \(\left(x-y+4\right)^2-\left(2x+3y-1\right)^2\)

\(=\left(x-y+4-2x-3y+1\right)\left(x-y+4+2x+3y-1\right)\)

\(=\left(5-x-4y\right)\left(3x+2y+3\right)\)

e) Ta có: \(x^4+x^3+2x^2+x+1\)

\(=\left(x^4+2x^2+1\right)+\left(x^3+x\right)\)

\(=\left(x^2+1\right)^2+x\left(x^2+1\right)\)

\(=\left(x^2+1\right)\left(x^2+1+x\right)\)

f) Ta có: \(\left(x+3\right)^3+\left(x-3\right)^3\)

\(=\left(x+3+x-3\right)\left[\left(x+3\right)^2-\left(x+3\right)\left(x-3\right)+\left(x-3\right)^2\right]\)

\(=2x\cdot\left[x^2+6x+9-\left(x^2-9\right)+x^2-6x+9\right]\)

\(=2x\cdot\left(2x^2+18-x^2+9\right)\)

\(=2x\cdot\left(x^2+27\right)\)

g) Ta có: \(9x^2-3xy+y-6x+1\)

\(=\left(9x^2-6x+1\right)-y\left(3x-1\right)\)

\(=\left(3x-1\right)^2-y\left(3x-1\right)\)

\(=\left(3x-1\right)\left(3x-1-y\right)\)

h) Ta có: \(x^3-4x^2+12x-27\)

\(=x^3-3x^2-x^2+3x+9x-27\)

\(=x^2\left(x-3\right)-x\left(x-3\right)+9\left(x-3\right)\)

\(=\left(x-3\right)\left(x^2-x+9\right)\)

Bài làm

a) 4x2 - 6x 

= 2x( 2x - 3 )

b) 9x4y3 + 3x2y

= 3x2y3( 3x2 + y )

c) x- 2x+ 5x

= x( x2 - 2x + 5 )

d) 3x( x - 1 ) + 5( x - 1 )

= ( x - 1 )( 3x + 5 )

e) 2x2( x + 1 ) + 4( x + 1 )

= ( x + 1 )( 2x2 + 4 )

= ( x + 1 )2( x2 + 2 )

= 2( x + 1 )( x2 + 2 )

f) -3x - 6xy + 9xz

= -( 3x + 6xy - 9xz )

= -3x( 1 + 2y - 3z )

# Học tốt #

8 tháng 6 2017

a) \(=x^2+2xy+y^2-x^2+y^2=2xy+2y^2=2y\left(x+y\right)\)

b) \(=\left(x^2-4y^2\right)-\left(2x+4y\right)=\left(x-2y\right)\left(x+2y\right)-2\left(x+2y\right)=\left(x+2y\right)\left(x-2y-2\right)\)

c) \(=3\left[\left(x^2+2xy+y^2\right)-z^2\right]=3\left[\left(x+y\right)^2-z^2\right]=3\left(x+y+z\right)\left(x+y-z\right)\)

d) \(=\left(2xy+1+2x+y\right)\left(2xy+1-2x-y\right)\)

e) \(=\left(x-3\right)\left(x^2+3x+9\right)-2x\left(x-3\right)=\left(x-3\right)\left(x^2+x+9\right)\)

f) \(=\left(x+5\right)\left(x^2-5x+25\right)-x\left(x+5\right)=\left(x+5\right)\left(x^2-6x+25\right)\)

8 tháng 6 2017

a) \(\left(x+y\right)^2-\left(x^2-y^2\right)\)

\(=x^2+2xy+y^2-x^2+y^2\)

\(=2y^2+2xy\)

\(=2y\left(x+y\right)\)

c) \(3x^2+6xy+3y^2-3z^2\)

\(=3\left(x^2+2xy+y^2-x^2\right)\)

\(=3\left[\left(x+y\right)^2-z^2\right]\)

\(=3\left(x+y+z\right)\left(x+y-z\right)\)

d) \(\left(2xy+1\right)^2-\left(2x+y\right)^2\)

\(=\left(2xy+1+2x+y\right)\left(2xy+1-2x-y\right)\)

\(=\left[\left(2xy+2x\right)+\left(y+1\right)\right]\left[\left(2xy-2x\right)-\left(y-1\right)\right]\)

\(=\left[2x\left(y+1\right)+\left(y+1\right)\right]\left[2x\left(y-1\right)-\left(y-1\right)\right]\)

\(=\left(2x+1\right)\left(y+1\right)\left(2x-1\right)\left(y-1\right)\)

\(=\left(4x^2-1\right)\left(y^2-1\right)\)

12 tháng 7 2019

a,\(xy+3x-7y-21\)

\(=x\left(y+3\right)-7\left(y+3\right)\)

\(=\left(y+3\right)\left(x-7\right)\)

12 tháng 7 2019

\(b,2xy-15-6x+5y\)

\(=\left(2xy-6x\right)+\left(-15+5y\right)\)

\(=2x\left(y-3\right)-5\left(3-y\right)\)

\(=2x\left(y-3\right)+5\left(y-3\right)\)

\(=\left(y-3\right)\left(2x+5\right)\)

12 tháng 8 2015

a) x^4 - x^3 - x + 1 

= x^3 ( x - 1 ) - ( x- 1 )

= ( x^3 - 1 )(x - 1)

= ( x- 1 )^2 (x^2 + x +  1 )

 

12 tháng 8 2015

a)x4-x3-x+1

=x3(x-1)-(x-1)

=(x-1)(x3-1)

=(x-1)(x-1)(x2+x+1)

=(x-1)2(x2+x+1)

b)5x2-4x+20xy-8y

(sai đề)

 

1 tháng 10 2020

a) \(5ax-15ay+20a\)

\(=5a\left(x-3y+4\right)\)

b) \(6xy-12x-8y\)

\(=6\left(xy-2x-3y\right)\)

c) \(3ab\left(x-y\right)+3a\left(y-x\right)\)

\(=3a\left(x-y\right)\left(b-1\right)\)

d) \(x^2-xy+2x-2y\)

\(=\left(x+2\right)\left(x-y\right)\)

1 tháng 10 2020

e) \(ax^2-5x^2-ax+5x+a-5\)

\(=\left(a-5\right)\left(x^2-x+1\right)\)

1 tháng 10 2020

a, \(5ax-15ay+20a=5a\left(x-5y+4\right)\)

b, sai 

c, \(3ab\left(x+y\right)+3a\left(y-x\right)=3ab\left(x+y\right)-3a\left(x+y\right)=\left(3ab-3a\right)\left(x+y\right)\)

d, \(x^2-xy+2x-2y=x\left(x+2\right)-y\left(x+2\right)=\left(x-y\right)\left(x+2\right)\)

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