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3 tháng 7 2017

bn chép lại đề nhé

a/ \(=\left(x+y\right)^2-4x^2y^2=\left(x+y+2xy\right)\left(x+y-2xy\right)\)

b/ \(=\left(2bc+b^2+c^2-a^2\right)\left(2bc-b^2-c^2+a^2\right)\)

\(=\left[\left(b+c\right)^2-a^2\right]\left[-\left(b+c\right)^2+a^2\right]\)

\(=\left(b+c-a\right)\left(b+c+a\right)^2\left(a-b-c\right)\)

c/ \(=2a^2+2b^2-2c^2+4ab=2\left[\left(a^2+b^2+2ab\right)-c^2\right]\)

\(=2\left(a+b-c\right)\left(a+b+c\right)\)

d/ \(=\left(4x^2-25\right)^2-9\left(4x^2-20x+25\right)\)

\(=\left(4x^2-25\right)^2-9\left(4x^2+25\right)+180x\)

tới đây bạn đặt a= 4x^2 -25 rồi làm típ nha, mình lười quá >< 

e/ tương tự câu d nha bạn

f/ \(=a^4\left(a^2-1\right)+2a^2\left(a+1\right)\)

\(=a^4\left(a-1\right)\left(a+1\right)+2a^2\left(a+1\right)\)

\(=a^2\left(a+1\right)\left(a^2+2\right)\)

g/   đặt \(a=3x^2+3x+2\) khi đó biểu thức trở thành

\(a^2-\left(a+4\right)^2=a^2-a^2-8a-16\)

\(=-8a-16=-8\left(3x^2+3x+2-8\right)=-8\left(3x^2+3x-6\right)\)

\(=-24\left(x^2+x-2\right)=-24\left(x-1\right)\left(x+2\right)\)

xong rùi nha bn. Chúc bn hc tốt (xin lỗi tại có mấy câu mình lười nha)

3 tháng 9 2018

\(x^2-4x^2y^2+y^2+2xy\)

\(=\left(x^2+2xy+y^2\right)-4x^2y^2\)

\(=\left(x+y\right)^2-4x^2y^2\)

\(=\left(x-2xy+y\right)\left(x+2xy+y\right)\)

31 tháng 10 2020

a) 2x3 + 8x2 - 8x

= 2x(x2 + 4x - 4)

= 2x(x2 + 4x + 4 - 8)

= 2x[(x + 2)2 - 8]

\(2x\left(x+2-\sqrt{8}\right)\left(x+2+\sqrt{8}\right)\)

b) a2 - b2 + 4a + 4b

= (a - b)(a + b) + 4(a + b)

= (a + b)(a - b + 4)

c) x2 - 2x - 3

= x2 + x - 3x - 3

= x(x + 1) - 3(x + 1)

= (x + 1)(x - 3)

d) x2 - 4x - 3

= x2 - 4x + 4 - 7

= (x + 2)2 - 7

\(\left(x+2-\sqrt{7}\right)\left(x+2+\sqrt{7}\right)\)

22 tháng 1 2021

a) a3 - a2c + a2b - abc

= a( a2 - ac + ab - bc )

= a[ a( a - c ) + b( a - c ) ]

= a( a - c )( a + b )

b) ( x2 + 1 )2 - 4x2

= ( x2 + 1 )2 - ( 2x )2

= ( x2 - 2x + 1 )( x2 + 2x + 1 )

= ( x - 1 )2( x + 1 )2

c) x2 - 10x - 9y2 + 25

= ( x2 - 10x + 25 ) - 9y2

= ( x - 5 )2 - ( 3y )2

= ( x - 3y - 5 )( x + 3y - 5 )

d) 4x2 - 36x + 56

= 4( x2 - 9x + 14 )

= 4( x2 - 7x - 2x + 14 )

= 4[ x( x - 7 ) - 2( x - 7 ) ]

= 4( x - 7 )( x - 2 )

22 tháng 1 2021

a,\(a^3-a^2c+a^2b-abc\)

\(=a\left(a^2-ac+ab-bc\right)\)

\(=a\left[a\left(a-c\right)+b\left(a-c\right)\right]\)

\(=a\left(a-b\right)\left(a-c\right)\)

b,\(\left(x^2+1\right)^2-4x^2\)

\(=\left(x^2+1-2x\right)\left(x^2+1+2x\right)\)

\(=\left(x-1\right)^2\left(x+1\right)^2\)

c,\(x^2-10x-9y^2+25\)

\(=\left(x^2-10x+25\right)-9y^2\)

\(=\left(x-5\right)^2-\left(3y\right)^2\)

\(=\left(x-5-3y\right)\left(x-5+3y\right)\)

d,\(4x^2-36x+56\)

\(=4\left(x^2-9x+14\right)\)

\(=4\left(x^2-7x-2x+14\right)\)

\(=4\left(x-7\right)\left(x-2\right)\)

d,=(2bc+b2+c2−a2)(2bc−b2−c2+a2)

=[(b+c)2−a2][−(b+c)2+a2]

=(b+c−a)(b+c+a)2(a−b−c)

23 tháng 9 2018

\(a^2-b^2+4bc-4c^2\)

\(=a^2-\left(b^2-4bc+4c^2\right)\)

\(=a^2-\left(b-2c\right)^2\)

\(=\left(a-b+2c\right)\left(a+b-2c\right)\)

7 tháng 10 2019

a) \(x^3+6x^2+12x+8\)

\(=\left(x+2\right)^3\)

b) \(x^3-3x^2+3x-1\)

\(=\left(x-1\right)^3\)

c) \(1-9x+27x^2-27x^3\)

\(=-\left(27x^3-27x^2+9x-1\right)\)

\(=-\left(3x-1\right)^3\)

7 tháng 10 2019

d) \(x^3+\frac{3}{2}x^2+\frac{3}{4}x+\frac{1}{8}\)

\(=\left(x+\frac{1}{2}\right)^3\)

e) \(27x^3-54x^2y+36xy^2-8y^3\)

\(=\left(3x-2y\right)^3\)

5 tháng 7 2017

c) \(\left(2x+5\right)^2-\left(x-9\right)^2\)

\(=\left(2x+5+x-9\right)\left(2x+5-x+9\right)\)

\(=\left(3x-4\right)\left(x+14\right)\)

d) \(\left(3x+1\right)^2-4\left(x-2\right)^2\)

\(=\left(3x+2\right)^2-\left[2\left(x-2\right)\right]^2\)

\(=\left[3x+2+2\left(x-2\right)\right]\left[3x+2-2\left(x-2\right)\right]\)

\(=\left(3x+2+2x-4\right)\left(3x+2-2x+4\right)\)

\(=\left(5x-2\right)\left(x+6\right)\)

e) \(9\left(2x+3\right)^2-4\left(x+1\right)^2\)

\(=\left[3\left(2x+3\right)\right]^2-\left[2\left(x+1\right)\right]^2\)

\(=\left[3\left(2x+3\right)+2\left(x+1\right)\right]\left[3\left(2x+3\right)-2\left(x+1\right)\right]\)

\(=\left(6x+9+2x+2\right)\left(6x+9-2x-2\right)\)

\(=\left(8x+11\right)\left(4x+7\right)\)

f) \(4b^2c^2-\left(b^2+c^2-a^2\right)^2\)

\(=\left(2bc\right)^2-\left(b^2+c^2-a^2\right)^2\)

\(=\left(2bc+b^2+c^2-a^2\right)\left(2bc-b^2-c^2+a^2\right)\)

\(=\left[\left(b+c\right)^2-a^2\right]\left[a^2-\left(b-c\right)^2\right]\)

\(=\left(a+b+c\right)\left(b+c-a\right)\left(a-b+c\right)\left(a+b-c\right)\)

5 tháng 7 2017

Ta có : \(\left(2x+5\right)^2-\left(x-9\right)^2\)

\(=\left(4x^2+20x+25\right)-\left(x^2-18x+81\right)\)

\(=4x^2+20x+25-x^2+18x-81\)

\(=3x^2+38x-56\)

\(=3x^2+42x-4x-56\)

\(=3x\left(x+14\right)-\left(4x+56\right)\)

\(=3x\left(x+14\right)-4\left(x+14\right)\)

\(=\left(x+14\right)\left(3x-4\right)\)