Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(x^3+x^2+9x-10x^2-10x+25x+25\)
\(=x^2\left(x+1\right)-10x\left(x+1\right)+25\left(x+1\right)\)
\(=\left(x+1\right)\left(x^2-10x+25\right)=\left(x+1\right)\left(x-5\right)^2\)
1.2x^2+x-6=2x^2+4x-3x+6=(2x^2+4x)-(3x+6)=2x(x+2)-3(x+2)=(x+2)(2x-3)
2.x^3-9x^2+14x
=x*(x^2-9x+14)
=x*(x^2-7x-2x+14)
=x*((x^2-7x)-(2x-14))
=x*(x(x-7)-2(x-7))
=x*((x--7)(x-2))
=x*(x-7)(x-2)
1.2x^2+x-6=2x^2+4x-3x+6=(2x^2+4x)-(3x+6)=2x(x+2)-3(x+2)=(x+2)(2x-3)
2.x^3-9x^2+14x
=x*(x^2-9x+14)
=x*(x^2-7x-2x+14)
=x*((x^2-7x)-(2x-14))
=x*(x(x-7)-2(x-7))
=x*((x--7)(x-2))
=x*(x-7)(x-2)
1)
\(=\left(x-7\right)^2-4a^2\)
\(=\left(x-7+2a\right)\left(x-7-2a\right)\)
2)
\(=\left(3x+1\right)^2-5^2\)
\(=\left(3x+1+5\right)\left(3x+1-5\right)\)
\(=\left(3x+6\right)\left(3x-4\right)\)
\(=3\left(x+2\right)\left(3x-4\right)\)
1)x^2-14x+49-4a^2
=x^2-2x7+7^2-4a^2
=\(\left(x-7\right)^2-4a^2\)
=\(\left(x-7\right)^2-\left(2a\right)^2\)
=\(\left(\left(x-7\right)-\left(2a\right)\right).\left(\left(x-7\right)+\left(2a\right)\right)\)
=\(\left(x-7-2a\right).\left(x-7+2a\right)\)
b)
\(9x^2+6x+1-25\\ =\left(3x\right)^2-5^2+6x+1\\ =\left(\left(3x\right)-5\right).\left(\left(3x\right)+5\right)+6x+1\)
\(=\left(3x-5\right).\left(3x+5\right)+6x+1\)
p/ x4 - 9x3 + 22x2 - 9x + 1
= (x4 - 5x3 + x2) + (- 4x3 + 20x2 - 4x) + (x2 - 5x + 1)
= (x2 - 5x + 1)(x2 - 4x + 1)
q) x4 - 6x3 + 14x2 - 22x + 5
= (x4 - 4x3 + x2) + (- 2x3 + 8x2 - 2x) + (5x2 - 20x + 5)
= (x2 - 4x + 1)(x2 - 2x + 5)