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\(-12\left(x-5\right)+7\left(3-x\right)=5\)
\(\Leftrightarrow-12x-\left(-60\right)+21-7x=5\)
\(\Leftrightarrow-12x+60+21-7x=5\)
\(\Rightarrow\left(-12x-7x\right)+\left(60+21\right)=5\)
\(\Rightarrow-19x+81=5\)
\(\Rightarrow-19x=5-81\)
\(\Rightarrow-19x=-76\)
\(\Rightarrow x=-76:\left(-19\right)\)
\(\Rightarrow x=4\)
Vậy x=4
\(\left(x-2\right).\left(x-3\right)=0\)
\(x=2\)
\(x=3\)
\(\left|\frac{2}{3}x-\frac{3}{4}\right|-\frac{1}{4}=0\)
\(\Rightarrow\left|\frac{2}{3}x-\frac{3}{4}\right|=0+\frac{1}{4}\)
\(\Rightarrow\left|\frac{2}{3}x-\frac{3}{4}\right|=\frac{1}{4}\)
\(\Rightarrow\hept{\begin{cases}\frac{2}{3}x-\frac{3}{4}=\frac{1}{4}\\\frac{2}{3}x-\frac{3}{4}=-\frac{1}{4}\end{cases}}\Rightarrow\hept{\begin{cases}x=\frac{3}{2}\\x=\frac{3}{4}\end{cases}}\)
Vậy : \(x\in\left\{\frac{3}{2};\frac{3}{4}\right\}\)
x=30,6
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a)\(x-15\%x=\frac{1}{3}\)
\(x.\left(1-15\%\right)=\frac{1}{3}\)
\(x.\frac{-280}{3}=\frac{1}{3}\)
\(x=\frac{1}{3}:\frac{-280}{3}\)
\(x=\frac{-1}{280}\)
Vậy \(x=\frac{-1}{280}\)
b)\(\frac{4}{5}x-x-\frac{3}{2}x+\frac{6}{5}=\frac{1}{2}-\frac{4}{3}\)
\(-\frac{17}{10}x+\frac{6}{5}=\frac{-5}{6}\)
\(-\frac{17}{10}x=-\frac{5}{6}-\frac{6}{5}\)
\(-\frac{17}{10}x=\frac{-61}{30}\)
\(x=\frac{-61}{30}:\frac{-17}{10}\)
\(x=\frac{61}{51}\)
Vậy \(x=\frac{61}{51}\)
\(3+\left(x\cdot4\right)-15=5\)
\(\Leftrightarrow4x=5+15-3=17\)
\(\Leftrightarrow x=\frac{17}{4}\)
\(3+\left(x\cdot4\right)-15=1\)
\(\Leftrightarrow4x=1+15-3=13\)
\(\Leftrightarrow x=\frac{13}{4}\)
3 + (x × 4) - 15 = 1
3 + (x × 4) = 1 + 15
3 + (x × 4) = 16
(x × 4) = 16 - 3
(x × 4) = 13
x = 13 : 4