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\(\frac{3}{2}+\frac{3}{8}+\frac{3}{32}+\frac{3}{128}+\frac{3}{512}\)
\(=3.\left(\frac{1}{2}+\frac{1}{2^3}+\frac{1}{2^5}+\frac{1}{2^7}+\frac{1}{2^9}\right)\)
\(=3.A\)với \(A=\frac{1}{2}+\frac{1}{2^3}+\frac{1}{2^5}+\frac{1}{2^7}+\frac{1}{2^9}\)
\(\Rightarrow2^2A=\left(2+\frac{1}{2}+\frac{1}{2^3}+\frac{1}{2^5}+\frac{1}{2^7}\right)\)
\(\Rightarrow2^2A-A=\left(2+\frac{1}{2}+\frac{1}{2^3}+\frac{1}{2^5}+\frac{1}{2^7}\right)-\left(\frac{1}{2}+\frac{1}{2^3}+\frac{1}{2^5}+\frac{1}{2^7}+\frac{1}{2^9}\right)\)
\(\Rightarrow4A-A=2-\frac{1}{2^9}\)
\(\Rightarrow3A=2-\frac{1}{512}=\frac{1023}{512}\Rightarrow A=\frac{1023}{512}:3\)
\(\Rightarrow\frac{3}{2}+\frac{3}{8}+\frac{3}{32}+\frac{3}{128}+\frac{3}{512}=3.\left(\frac{1023}{512}:3\right)=\frac{1023}{512}\)
a) 8.427.3 + 6.573.4
= 8.3.427 + 6.4.573
= 24.427 + 24.573
= 24.(427 + 573)
= 24.1000
= 24000
b) 6.1235.20 - 5.235.24
= 6.20.1235 - 5.24.235
= 120.1235 - 120.235
= 120.(1235 - 235)
= 120.1000
= 120000
c) 3457 - 27.48 - 48.73 + 6543
= (3457 + 6543) - (27.48 + 48.73)
= 10000 - 48.(27 + 73)
= 10000 - 48.100
= 10000 - 4800
= 5200
Ủng hộ mk nha ^_-
Bài 1
( 4+ 36)+(8+32)+(12+28)+(16+24)+20
= 40 + 40+40 +40 +20 = 40 x 4 + 20 = 180
Bài 2
a.25 + x +43 =156
25+x = 156 - 43
25 + x = 113
x = 113 - 25
x = 88
b.124 - x +14 =87
124 -x =87 -14
124 - x = 73
x =124 - 73
x =51
Bài 1
=(4+36)+(8+32)+(12+28)+(16+24)+20
=40+40+40+40+20
=180
Bài2
a)25+x+43=156
25+x =156-43
25+x =113
x =113-25
x =88
b)
124-x+14=87
124-x =87-14
124-x =73
x =124-73
x =51
\(\frac{2}{9}\)Và \(\frac{1}{6}\)
\(\frac{2}{9}=\frac{2\times2}{9\times2}=\frac{4}{18}\)
\(\frac{1}{6}=\frac{1\times3}{6\times3}=\frac{3}{18}\)
\(\frac{7}{6}\)Và \(\frac{3}{8}\)
\(\frac{7}{6}=\frac{7\times4}{6\times4}=\frac{28}{24}\)
\(\frac{3}{8}=\frac{3\times3}{8\times3}=\frac{9}{24}\)
\(\frac{1}{12}\)Và \(\frac{1}{9}\)
\(\frac{1}{12}=\frac{1\times3}{12\times3}=\frac{3}{36}\)
\(\frac{1}{9}=\frac{1\times4}{9\times4}=\frac{4}{36}\)
ừ
cách trình bày là thế đây , mình cũng trình bày thế với những dạng bài này
a) \(A=\frac{27\text{x}45+27\text{x}25}{2+4+6+8+...+18}=\frac{27\left(45+25\right)}{\left(18+2\right)\text{x}\left(\frac{18-2}{2}+1\right)}\)
\(A=\frac{27\text{x}70}{20\text{x}9}=\frac{3\text{x}9\text{x}10\text{x}7}{10\text{x}2\text{x}9}\)
\(A=\frac{21}{2}\)
b) \(B=\frac{28\text{x}108-52\text{x}12}{32-28+24-20+16-12+8-4}\)
\(B=\frac{28\text{x}12\text{x}9\text{}\text{}-52\text{x}12}{\left(32-28\right)+\left(24-20\right)+\left(16-12\right)+\left(8-4\right)}\)
\(B=\frac{12\left(28\text{x}9-52\right)}{4+4+4+4}=\frac{12\text{x}200}{4\text{x}4}\)
\(B=\frac{4\text{x}3\text{x}4\text{x}50}{4\text{x}4}=150\)
9999999999999999999999999999999x4444444444444444446666666666666666666644444444444444=888888000099977766655544443332211
1/2+6/7= 7/14+12/14=19/14
8/27+24/32=113/108