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c ) \(3x^3-7x^2+17x-5\)
\(=3x^3-x^2-6x^2+2x+15x-5\)
\(=\left(3x^3-x^2\right)-\left(6x^2-2x\right)+\left(15x-5\right)\)
\(=x^2\left(3x-1\right)-2x\left(3x-1\right)+5\left(3x-1\right)\)
\(=\left(3x-1\right)\left(x^2-2x+5\right)\)
a ) \(3x^3-7x^2+17x-5\)
\(=\left(3x^2-x^2\right)-\left(6x^2-2x\right)+\left(15x-5\right)\)
\(=x^2\left(3x-1\right)-2x\left(3x-1\right)+5\left(3x-1\right)\)
\(=\left(x^2-2x+5\right)\left(3x-1\right)\)
b \(x^4+2011x^2+2010x+2011\)
\(=x^4-x+2011x^2+2011x+2011\)
\(=x\left(x^3-1\right)+2011\left(x^2+x+1\right)\)
\(=x\left(x-1\right)\left(x^2+x+1\right)+2011\left(x^2+x+1\right)\)
\(=\left(x^2+x+1\right)\left(x^2-x+2011\right)\)
\(x^3-x^2-4\)
\(=x^3-2x^2+x^2-4\)
\(=\left(x^3-2x^2\right)+\left(x^2-4\right)\)
\(=x^2\left(x-2\right)+\left(x-2\right)\left(x+2\right)\)
\(=\left(x^2+x+2\right)\left(x-2\right)\)
Đề đúng :
\(x^3-5x^2+8x-4\)
\(=x^3-x^2-4x^2+4x+4x-4\)
\(=\left(x^3-x^2\right)-\left(4x^2-4x\right)+\left(4x-4\right)\)
\(=x^2\left(x-1\right)-4x\left(x-1\right)+4\left(x-1\right)\)
\(=\left(x^2-4x+4\right)\left(x-1\right)\)
\(=\left(x^2-2.2.x+2^2\right)\left(x-1\right)\)
\(=\left(x-2\right)^2\left(x-1\right)\)
\(3x^3-7x^2+17x-5\)
\(=3x^3-6x^2-x^2+15x+2x-5\)
\(=\left(3x^3-6x^2+15x\right)-\left(x^2-2x+5\right)\)
\(=3x\left(x^2-2x+5\right)-\left(x^2-2x+5\right)\)
\(=\left(3x-1\right)\left(x^2-2x+5\right)\)
a.) 2x2 - 7xy + 6y2 + 9x - 13y + 5
= (2x -3y)(x-2y) + 5(2x - 3y) -x +2y -5
= (2x - 3y)(x-2y + 5) - (x - 2y + 5)
=(x-2y+5)(2x-3y-1)
Ta có:
\(2x^2-5xy+3y^2\)
\(=2x^2-2xy-3xy+3y^2=2x\left(x-y\right)-3y\left(x-y\right)\)
\(=\left(x-y\right)\left(2x-3y\right)\)
\(x^3-7x-6=x^3+1-7x-7\)
\(=\left(x+1\right)\left(x^2-x+1\right)-7\left(x+1\right)=\left(x+1\right)\left(x^2-x-6\right)\)
\(=\left(x+1\right)\left(x-3\right)\left(x+2\right)\)
\(\Rightarrow3x^2-10x+3x-10\)
\(\Rightarrow x\left(3x-10\right)+\left(3x-10\right)\)
\(\Rightarrow\left(3x-10\right)\left(x+1\right)\)
T I C K nha cảm ơn rất nhìu
\(3x^3-7x^2+17x-5\)
\(=3x^3-x^2-6x^2+2x+15x-5\)
\(=x^2\left(3x-1\right)-2x\left(3x-1\right)+5\left(3x-1\right)\)
\(=\left(3x-1\right)\left(x^2-2x+5\right)\)
3x^3-7x^2+17x-5
= (3x^3-x^2)-(6x^2-2x)+(15x-5)
= (3x-1).(x^2-6x+15)
Tk mk nha