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a: \(3x^3-75x\)

\(=3x\left(x^2-25\right)\)

\(=3x\left(x-5\right)\left(x+5\right)\)

b: \(x^4y^2-12x^3y^2+48x^2y^2-64xy^2\)

\(=xy^2\left(x^3-12x^2+48x-64\right)\)

\(=xy^2\cdot\left(x-4\right)^3\)

c) Ta có: \(C=4x^2+y^2-4xy+8x-4y+4\)

\(=\left(2x-y\right)^2+2\cdot\left(2x-y\right)\cdot2+2^2\)

\(=\left(2x-y+2\right)^2\)

8 tháng 8 2021

Cho mình xin đáp án câu a và b được không?

a: \(x^4-4x^3-8x^2+8x\)

\(=x\left(x^3-4x^2-8x+8\right)\)

\(=x\left[\left(x+2\right)\left(x^2-2x+4\right)-4x\left(x+2\right)\right]\)

\(=x\left(x+2\right)\left(x^2-6x+4\right)\)

b: \(x^2-1-xy+y\)

\(=\left(x-1\right)\left(x+1\right)-y\left(x-1\right)\)

\(=\left(x-1\right)\left(x-y+1\right)\)

c: Ta có: \(\left(x-1\right)\left(x-2\right)\left(x-3\right)+\left(x-1\right)^2\cdot\left(x-2\right)\)

\(=\left(x-1\right)\cdot\left(x-2\right)\cdot\left(x-3-x-1\right)\)

\(=2\cdot\left(x-1\right)\cdot\left(x-2\right)^2\)

28 tháng 7 2021

a. `6x(x-2015)-x+2015=6x(x-2015)-(x-2015)=(x-2015)(6x-1)`

b. `x^4+4x^2+4=(x^2)^2+2.x^2 .2 +2^2=(x^2+2)^2`

a) \(6x\left(x-2015\right)-x+2015\)

\(=6x\left(x-2015\right)-\left(x-2015\right)\)

\(=\left(x-2015\right)\left(6x-1\right)\)

b) \(x^4+4x^2+4\)

\(=x^4+2\cdot x^2\cdot2+2^2\)

\(=\left(x^2+2\right)^2\)

a: \(A=x^3y-12xy-x^2y\)

\(=xy\cdot x^2-xy\cdot12-xy\cdot x\)

\(=xy\left(x^2-x-12\right)\)

\(=xy\left(x^2-4x+3x-12\right)\)

\(=xy\left[x\left(x-4\right)+3\left(x-4\right)\right]\)

\(=xy\left(x-4\right)\left(x+3\right)\)

c: \(C=\left(x+1\right)\left(x+2\right)\left(x+3\right)\left(x+4\right)-120\)

=(x+1)(x+4)(x+2)(x+3)-120

\(=\left(x^2+5x+4\right)\left(x^2+5x+6\right)-120\)

\(=\left(x^2+5x\right)^2+10\left(x^2+5x\right)+24-120\)

\(=\left(x^2+5x\right)^2+10\left(x^2+5x\right)-96\)

\(=\left(x^2+5x+16\right)\left(x^2+5x-6\right)\)

\(=\left(x^2+5x+16\right)\left(x+6\right)\left(x-1\right)\)

d: \(D=x^5-x^4+x^2-1\)

\(=\left(x^5-x^4\right)+\left(x^2-1\right)\)

\(=x^4\left(x-1\right)+\left(x-1\right)\left(x+1\right)\)

\(=\left(x-1\right)\left(x^4+x+1\right)\)

s không có câu b ạ

 

a: \(=x\left(x+y\right)-\left(x+y\right)=\left(x+y\right)\left(x-1\right)\)

b: \(=25-\left(x-2y\right)^2\)

\(=\left(5-x+2y\right)\left(5+x-2y\right)\)

27 tháng 9 2023

a) \(x^4-y^4\)

\(=\left(x^2\right)^2-\left(y^2\right)^2\)

\(=\left(x^2-y^2\right)\left(x^2+y^2\right)\)

\(=\left(x+y\right)\left(x-y\right)\left(x^2+y^2\right)\)

b) \(x^2-3y^2\)

\(=x^2-\left(y\sqrt{3}\right)^2\)

\(=\left(x-y\sqrt{3}\right)\left(x+y\sqrt{3}\right)\)

c) \(\left(3x-2y\right)^2-\left(2x-3y\right)^2\)

\(=\left(3x-2y+2x-3y\right)\left(3x-2y-3x+2y\right)\)

\(=0\cdot0\)

\(=0\)

d) \(9\left(x-y\right)^2-4\left(x+y\right)^2\)

\(=\left(3x-3y\right)^2-\left(2x+2y\right)^2\)

\(=\left(3x-3y-2x-2y\right)\left(3x-3y+2x+2y\right)\)

\(=\left(x-5y\right)\left(5x-y\right)\)

e) \(\left(4x^2-4x+1\right)-\left(x+1\right)^2\)

\(=\left(2x-1\right)^2-\left(x+1\right)^2\)

\(=\left(2x-1+x+1\right)\left(2x-1-x-1\right)\)

\(=3x\left(x-2\right)\)

f) \(x^3+27\)

\(=x^3+3^3\)

\(=\left(x+3\right)\left(x^2-3x+9\right)\)

g) \(27x^3-0,001\)

\(=\left(3x\right)^3-\left(0,1\right)^3\)

\(=\left(3x-0,1\right)\left(9x^2+0,3x+0,01\right)\)

h) \(125x^3-1\)

\(=\left(5x\right)^3-1^3\)

\(=\left(5x-1\right)\left(25x^2+5x+1\right)\)

27 tháng 9 2023

c) \(\left(3x-2y\right)^2-\left(2x-3y\right)^2\)

\(=\left(3x-2y+2x-3y\right)\left(3x-2y-2x+3y\right)\)

\(=\left(5x-5y\right)\left(x+y\right)\)

\(=5\left(x+y\right)\left(x-y\right)\)

a: \(x^4+4=\left(x^2-2x+2\right)\left(x^2+2x+2\right)\)

b: \(x^8+x^7+1\)

\(=x^8+x^7+x^6-x^6-x^5-x^4+x^5+x^4+x^3-x^3-x^2-x+x^2+x+1\)

\(=\left(x^2+x+1\right)\left(x^6-x^4+x^3-x+1\right)\)

c: \(x^8+x^4+1\)

\(=\left(x^8+2x^4+1\right)-x^4\)

\(=\left(x^4-x^2+1\right)\cdot\left(x^4+x^2+1\right)\)

\(=\left(x^4-x^2+1\right)\left(x^2+1-x\right)\left(x^2+1+x\right)\)

 

26 tháng 8 2021

a)\(x^4+4\\ =\left(x^2\right)^2+4x^2+4-4x^2\\ =\left[\left(x^2\right)^2+4x^2+4\right]-\left(2x\right)^2\\ =\left(x^2+2\right)^2-\left(2x\right)^2\\ =\left(x^2+2+2x\right)\left(x^2+2-2x\right)\)

 

11 tháng 10 2021

a: \(x^2-y^2-x-y\)

\(=\left(x-y\right)\left(x+y\right)-\left(x+y\right)\)

\(=\left(x+y\right)\left(x-y-1\right)\)

f: \(x^3-5x^2-5x+1\)

\(=\left(x+1\right)\left(x^2-x+1\right)-5x\left(x+1\right)\)

\(=\left(x+1\right)\left(x^2-6x+1\right)\)