Question

[Nguyễn Thành Nam]

Phân tích đa thức thành nhân tử:

1,3x+9y

2,4x^2-16xy

3,x^2-6x+9

4,4y^2-36

5,4y^2-4

6,5a^2-9

7,x^3-2x^2+x

8,5xy^3-10xy^2+5xy

9,12x^2y+12xy+3y

10,5x-5y+y^2-xy

Answer 1

[๒ạςђ ภђเêภ♕]

a) 3x+9y

=3(x+3y)

b) 4x²-16xy

=4x(x-4y)

c) x²-6x+9

=(x-3)²

d) 4y²-36

=(2y-6)(2y+6)

e) 4y²-4

=(2y-2)(2y+2)

f) 5a²-9

=\(\left(\sqrt{5}a-3\right)\left(\sqrt{5}a+3\right)\)

g) x³-2x²+x

=x(x²-2x+1)

=x(x-1)²

h) 5xy³-10xy²+5xy

=5xy(y²-2y+1)

=5xy(y-1)²

i) 12x²y+12xy+3y

=3y(4x²+4x+1)

=3y(2x+1)²

k) 5x-5y+y²-xy

=(5x-5y)+(y²-xy)

=5(x-y)-y(x-y)

=(x-y)(5-y)

#H