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18 tháng 7 2021

x2-xy+2x-2y
= (x2-xy)+(2x-2y)
= x(x-y)+2(x-y)
= (x-y)(x+2)

ax+ay-2x-2y
= (ax+ay)-(2x+2y)
= a(x+y)-2(x+y)
=(x+y)(a-2)

ax2-3axy+bx-3by
= (ax2+bx)-(3axy+3by)
= x(ax+b)-3y(ax+b)
= (ax+b)(x-3y)

2a2-5by-5a2y+2bx
= (2a2-5a2y)+(2bx-5by)
= a2(2-5y)+b(2x-5y)

16 tháng 10 2019

a, x(a - b) + (a - b)

= (x + 1)(a - b)

b, x(a + b) - a - b

= x(a + b) - (a + b)

= (x - 1)(a + b)

c, 10ax - 5ay - 2x + y

=  5a(2x - y) - (2x - y)

= (5a - 1)(2x - y)

d, 2a^2x - 5by - 5a^2y + 2bx

= 2x(a^2 + b) - 5y(b + a^2)

= (2a - 5y)(a^2 + b)

làm tiếp:

2ax2 - bx2 - 2ax +bx +4a-2b

= x2(2a-b) - x(2a-b) +2(2a-b)

=(2a-b)(x2-x+2)

18 tháng 8 2020

Bn viet bây à

18 tháng 8 2020

Giúp mik đi

10 tháng 9 2018

1 ) \(x\left(a-b\right)+a-b=\left(x+1\right)\left(a-b\right)\)

2 ) \(2x\left(b-a\right)+a-b=2x\left(b-a\right)-\left(b-a\right)=\left(2x-1\right)\left(b-a\right)\)

3 ) \(-2x-2y+ax+ay=-2\left(x+y\right)+a\left(x+y\right)=\left(a-2\right)\left(x+y\right)\)

4 ) \(x^2-xy-2x+2y=x\left(x-y\right)-2\left(x-y\right)=\left(x-2\right)\left(x-y\right)\)

5 ) \(5x^2y+5xy^2+a^2x+a^2y\)

\(=5xy\left(x+y\right)+a^2\left(x+y\right)\)

\(=\left(5xy+a^2\right)\left(x+y\right)\)

6 ) \(2x^2-6xy+5x-15y\)

\(=2x\left(x-3y\right)+5\left(x-3y\right)\)

\(=\left(2x+5\right)\left(x-3y\right)\)

7 ) \(ax^2-3axy+bx-3by\)

\(=\left(ax^2+bx\right)-\left(3axy+3by\right)\)

\(=x\left(ax+b\right)-3y\left(ax+b\right)\)

\(=\left(x-3y\right)\left(ax+b\right)\)

8 ) \(x^2+4x-5x-20=0\)

\(\Leftrightarrow x\left(x+4\right)-5\left(x+4\right)=0\)

\(\Leftrightarrow\left(x-5\right)\left(x+4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-5=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=-4\end{matrix}\right.\)

9 ) \(x^2+10x-2x-20=0\)

\(\Leftrightarrow x\left(x+10\right)-2\left(x+10\right)=0\)

\(\Leftrightarrow\left(x-2\right)\left(x+10\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+10=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-10\end{matrix}\right.\)

10 ) \(x^2-6x-4x+24=0\)

\(\Leftrightarrow x\left(x-6\right)-4\left(x-6\right)=0\)

\(\Leftrightarrow\left(x-4\right)\left(x-6\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-4=0\\x-6=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=6\end{matrix}\right.\)

:D

a) Ta có: \(x^2-2xy+y^2-2x+2y\)

\(=\left(x-y\right)^2-2\left(x-y\right)\)

\(=\left(x-y\right)\left(x-y-2\right)\)

b) Ta có: \(x^2-4x+4-x^2y+2xy\)

\(=\left(x-2\right)^2-xy\left(x-2\right)\)

\(=\left(x-2\right)\left(x-2-xy\right)\)

13 tháng 8 2017

bn post nhiều nên mình ghi đáp án thôi nhé phần nào sai đề mình cho qua

b)\(\left(x+1\right)\left(xy+1\right)\)

c)\(\left(a+b\right)\left(x+y\right)\)

d)\(\left(x-a\right)\left(x-b\right)\)

e)\(\left(x+y\right)\left(xy-1\right)\)

f)\(\left(a-b\right)\left(x^2+y\right)\)

2 tháng 7 2018

\(1,2x^2-6xy+5x-15y\)

\(=2x\left(x-3y\right)+5\left(x-3y\right)\)

\(=\left(x-3y\right)\left(2x+5\right)\)

\(2,ax^{2\:}-3axy+bx-3by\)

\(=ax\left(x-3y\right)+b\left(x-3y\right)\)

\(=\left(x-3y\right)\left(ax+b\right)\)

\(3,5ax^2-3axy+3ay^2-3axy\) ( Đề sai )

Sửa : \(3ax^2-3axy+3ay^2-3axy\)

\(=3ax\left(x-y\right)+3ay\left(y-x\right)\)

\(=3ax\left(x-y\right)-3ay\left(x-y\right)\)

\(=3a\left(x-y\right)^2\)

\(4,4acx+4bcx+4ax+4bx\)

\(=4cx\left(a+b\right)+4x\left(a+b\right)\)

\(=4x\left(a+b\right)\left(c+1\right)\)

\(6,ax^{2\:}y-bx^2y-ax+bx+2a-2b\)

\(=x^2y\left(a-b\right)-x\left(a-b\right)+2\left(a-b\right)\)

\(=\left(a-b\right)\left(x^2y-x+2\right)\)

\(7,ax^{2\:}-bx^2-2ax+2bx-3a+3b\)

\(=x^2\left(a-b\right)-2x\left(a-b\right)-3\left(a-b\right)\)

\(=\left(a-b\right)\left(x^2-2x-3\right)\)

\(8,ax^{2\:}-5x^2-ax+5x+a-5\)

\(=x^2\left(a-5\right)-x\left(a-5\right)+\left(a-5\right)\)

\(=\left(a-5\right)\left(x^2-x+1\right)\)

\(9,ax+bx+cx-2a-2b+2c\) Đề sai

Sửa :\(ax+bx+cx-2a-2b-2c\)

\(=x\left(a+b+c\right)-2\left(a+b+c\right)\)

\(=\left(a+b+c\right)\left(x-2\right)\)

\(10,2ax-bx+3cx-2a+b-3c\)

\(=\left(2ax-2a\right)-\left(bx-b\right)+\left(3cx-3c\right)\)

\(=2a\left(x-1\right)-b\left(x-1\right)+3c\left(x-1\right)\)

\(=\left(x-1\right)\left(2a-b+3c\right)\)

Mấy câu đề sai mk sửa chỗ nào ko đúng thì nói mk nha !