Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(=7x\left(1-x\right)+y\left(1-x\right)\\ =\left(7x+y\right)\left(1-x\right)\)
\(-2x^4-7x^3-x^2+7x+3\)
\(=-2x^3\left(x+1\right)-5x^2\left(x+1\right)+4x\left(x+1\right)+3\left(x+1\right)\)
\(=-\left(x+1\right)\left(2x^3+5x^2-4x-3\right)\)
\(=-\left(x+1\right)\left[2x^2\left(x-1\right)+7x\left(x-1\right)+3\left(x-1\right)\right]\)
\(=-\left(x+1\right)\left(x-1\right)\left(2x^2+7x+3\right)\)
\(=-\left(x+1\right)\left(x-1\right)\left(x+3\right)\left(2x+1\right)\)
Ta có `:`
`x^3 - 7x-6`
`= x^3 - 9x + 2x - 6`
`= x( x^2 - 9 ) + 2( x-3 )`
`= x( x-3 )( x + 3 ) + 2( x-3 )`
`= [ x( x + 3 )+2]( x-3 )`
`= ( x^2 + 3x + 2 )( x-3 )`
`= ( x^2 + 2x + x + 2 )( x-3 )`
`= [x( x+2 ) + ( x + 2 )]( x-3 )`
`= ( x+1)(x+2)(x-3)`
Ta có:x(3x2+4x-7)=x[(3x2-3x)+(7x-7)]=x[3x(x-1)+7(x-1)]=x(x-1)(3x+7)
x3 - 7x2 + 10x
=x3 - 2x2 - 5x2 + 10x
=(x3 -2x2) - (5x2 - 10x)
= x2( x - 2) - 5x( x - 2)
= (x - 2) (x2 - 5x)
Gõ trên máy tính nên hơi lâu
Cảm ơn mình đê
\(a,5x^3y-10x^2y^2\\=5x^2y(x-2y)\\b,x^4-y^4\\=(x^2)^2-(y^2)^2\\=(x^2-y^2)(x^2+y^2)\\=(x-y)(x+y)(x^2+y^2)\)
\(c,(x+5)^2-16\\=(x+5)^2-4^2\\=(x+5-4)(x+5+4)\\=(x+1)(x+9)\\d,7x(y-3)-14(3-y)\\=7x(y-3)+14(y-3)\\=(7x+14)(y-3)\\=7(x+2)(y-3)\\Toru\)
(2x2 + 6x) + (x + 3) = 2x(x + 3) + (x + 3) = (x + 3)(2x + 1)
\(4x^4-8x^3+4x^3-8x^2+x^2-2x-2x+4\\ =4x^3\left(x-2\right)+4x^2\left(x-2\right)+x\left(x-2\right)-2\left(x-2\right)\\ =\left(x-2\right)\left(4x^3+4x^2+x-2\right)\\ =\left(x-2\right)\left(4x^3-2x^2+6x^2-3x+4x-2\right)\\ =\left(x-2\right)\left[2x^2\left(2x-1\right)+3x\left(2x-1\right)+2\left(2x-1\right)\right]\\ =\left(x-2\right)\left(2x-1\right)\left(2x^2+3x-2\right)\)