K
Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

11 tháng 10 2018

1.

x4y4+4=[(x2y2)2+2.x2y2.2+22]-4x2y2

=(x2y2+2)2-(2xy)2

bạn tính nốt đi, câu 2, 4, 6 tương tự

câu 4 khá dài bạn lấy số đấy chia cho (x+1) ra nháp rồi tính ngược lại sẽ ra

10 tháng 10 2022

1: \(=x^4y^4+4+4x^2y^2-4x^2y^2\)

\(=\left(x^2y^2+2\right)^2-4x^2y^2\)

\(=\left(x^2y^2+2xy+2\right)\left(x^2y^2-2xy+2\right)\)

2: \(=x^4y^4+16x^2y^2+64-16x^2y^2\)

\(=\left(x^2y^2+8\right)^2-16x^2y^2\)

\(=\left(x^2y^2+8-4xy\right)\left(x^2y^2+8+4xy\right)\)

3: \(=x^4+4x^2+4-x^2\)

\(=\left(x^2+2\right)^2-x^2\)

\(=\left(x^2+x+2\right)\left(x^2-x+2\right)\)

4: \(=4x^4y^4+1+4x^2y^2-4x^2y^2\)

\(=\left(2x^2y^2+1\right)^2-\left(2xy\right)^2\)

\(=\left(2x^2y^2+1-2xy\right)\left(2x^2y^2+1+2xy\right)\)

6: \(=x^4+4y^4+4x^2y^2-4x^2y^2\)

\(=\left(x^2+2y^2\right)^2-\left(2xy\right)^2\)

\(=\left(x^2+2y^2+2xy\right)\left(x^2+2y^2-2xy\right)\) 

31 tháng 7 2017

b. (x^2)^2 + (2y^2)^2=(x^2)^2 + 4x^2y^2 + (2y^2)^2 - 4x^2y^2=(x^2+2y^2)^2-(2xy)^2=(x^2+2y^2-2xy)(x^2+2y^2+2xy)

7 tháng 8 2018

y^4+64

=(y^2)^2+16y^2+64-16y^2

=(y^2+8-4x)(x^2+8+4x)

x^2+4

=x^2+2x^2+4-2x^2

=(x+2)^2-2x^2

=(x^2+2-2x)(x^2+2+2x)

x^4+16

=(x^2)^2+4x^2+16-4x^2

=(x+4)^2-4x^2

=(x^2+4-4x)(x^2+4+4x)

x^4y^4+4

=x^4y^4+4x^4+2^2-4x^4

=(x^4y^4+2)^2-(2x^2)^2

=(x^4y^4+2+2x^2)(x^4y^4+2-2x^2)

4x^4y^4+1

=4x^4y^4+x^4+1-x^4

=(2x^4y^4+1)^2-(x^2)^2

=(2x^4y^4+1-x^2)(2x^4y^4+1+x^2)

Mình ko bt câu D đúng hay sai nữa. Mà lỡ sai bạn đừng giận mình nha!

3 tháng 7 2021

Giúp tớ với ạ:33

3 tháng 7 2021

\(1,\)

\(x^2-2x-4y^2-4y\)

\(=\left(x-2y\right)\left(x+2y\right)-2\left(x+2y\right)\)

\(=\left(x+2y\right)\left(x-2y-2\right)\)

\(2,\)

\(x^4+2x^3-4x-4\)

\(=\left(x^2-2\right)\left(x^2+2\right)+2x\left(x^2-2\right)\)

\(=\left(x^2-2\right)\left(x^2+2x+2\right)\)

\(3,\)

\(3x^2-3y^2-2\left(x-y\right)^2\)

\(=3\left(x^2-y^2\right)-2\left(x-y\right)^2\)

\(=3\left(x-y\right)\left(x+y\right)-2\left(x-y\right)\)

\(=\left(x-y\right)[3\left(x+y\right)-2\left(x-y\right)]\)

\(=\left(x-y\right)\left(3x+3y-2x+2y\right)\)

\(=\left(x-y\right)\left(x+5y\right)\)

\(4,\)

\(x^2-y^2-2x+2y\)

\(=x^2-y^2-2x+2y\)

\(=\left(x-y\right)\left(x+y\right)-2\left(x-y\right)\)

\(=\left(x-y\right)\left(x+y-2\right)\)

31 tháng 7 2021

\(1,x^2-y^2+4x-4y\)

\(\left(x-y\right)\left(x+y\right)+4\left(x-y\right)\)

\(\left(x-y\right)\left(x+y+4\right)\)

\(x^2+2x-4y^2-4y\)

\(\left(x-2y\right)\left(x+2y\right)+2\left(x-2y\right)\)

\(\left(x-2y\right)\left(x+2y+2\right)\)

\(3,3x^2-4y+4x-3y^2\)

\(3\left(x^2-y^2\right)-4\left(x-y\right)\)

\(3\left(x-y\right)\left(x+y\right)-4\left(x-y\right)\)

\(\left(x-y\right)\left(3x+3y-4\right)\)

\(x^4-6x^3+54x-81\)

\(x^4+3x^3-9x^3+27x^2-27x^2+81x-27x-81\)

\(\left(x^4+3x^3\right)-\left(9x^3+27x^2\right)+\left(27x^2+81x\right)-\left(27x+81\right)\)

\(x^3\left(x+3\right)-9x^2\left(x+3\right)+27x\left(x+3\right)-27\left(x+3\right)\)

\(\left(x+3\right)\left(x^3-9x^2+27x-27\right)\)

\(\left(x+3\right)\left(x-3\right)^3\)

18 tháng 10 2021

1.A

2.C

3.B

4.C

15 tháng 12 2021

a

c

b

c

13 tháng 10 2016

\(4x^2+8xy-3x-6y=4x\left(x+2y\right)-3\left(x+2y\right)=\left(4x-3\right)\left(x+2y\right)\)

\(x^4y-3x^3y^2+3x^2y^3-xy^4=xy\left(x^3-3x^2y+3xy^2-y^3\right)=xy\left(x-y\right)^3\)

\(x^3-5x^2-14x=x\left(x^2-5x-14\right)=x\left(x^2-7x+2x-14\right)=x\left[x\left(x-7\right)+2\left(x-7\right)\right]=x\left(x-7\right)\left(x+2\right)\)

\(x^4+4y^4=\left(x^2\right)^2+2\times x^2\times2y^2+\left(2y^2\right)^2-4x^2y^2=\left(x^2+2y^2\right)^2-\left(2xy\right)^2=\left(x^2-2xy+2y^2\right)\left(x^2+2xy+2y^2\right)\)

13 tháng 10 2016

thank bạn nhiều nha

9 tháng 10 2021

a) \(x^2-2x-4y^2-4y=\left(x^2-2x+1\right)-\left(4y^2+4y+1\right)\)

\(=\left(x-1\right)^2-\left(2y+1\right)^2=\left(x-1-2y-1\right)\left(x-1+2y+1\right)\)

\(=\left(x-2y-3\right)\left(x+2y\right)\)

b) \(x^2-4x^2y^2+y^2+2xy=\left(x^2+2xy+y^2\right)-4x^2y^2\)

\(=\left(x+y\right)^2-4x^2y^2=\left(x+y-2xy\right)\left(x+y+2xy\right)\)

c) \(x^6-x^4+2x^3+2x^2=\left(x^6+2x^3+1\right)-\left(x^4-2x^2+1\right)\)

\(=\left(x^3+1\right)^2-\left(x^2-1\right)^2=\left(x^3+1-x^2+1\right)\left(x^3+1+x^2-1\right)=x^2\left(x^3-x^2+2\right)\left(x+1\right)\)

d) \(x^3+3x^2+3x+1-8y^3=\left(x+1\right)^3-8y^3=\left(x+1-2y\right)\left(x^2+2x+1+2xy+2y+4y^2\right)\)

20 tháng 7 2018

a) 1/2(x3+8)=1/2(x+2)(x2-2x+4)

b) x4(x-y)+2x3(x-y)=x3(x+2)(x-y)

c) x2-(y2-6y+9)=x2-(y-3)2=(x-y+3)(x+y-3)

d) xy(x3+y3)=xy(x+y)(x2-xy+y2)

e)3x2(x2-25y2)=3x2(x-5y)(x+5y)

f) 4x4+4x2y2+y4-4x2y2= (2x2+y2)2-(2xy)2=(2x2-2xy+y2)(2x2+2xy+y2)

20 tháng 7 2018

a) \(\frac{1}{2}x^3+4=\frac{1}{2}\left(x^3+8\right)=\frac{1}{2}\left(x+2\right)\left(x^2-2x+4\right)\)

b) \(x^5-x^4y+2x^4-2x^3y=x^3\left(x^2-xy+2x-2y\right)=x^3\left[x\left(x-y\right)+2\left(x-y\right)\right]=x^2\left(x-y\right)\left(x+2\right)\)

c) \(x^2-y^2+6y-9=x^2-\left(y-3\right)^2=\left(x+y-3\right)\left(x-y+3\right)\)

d) \(x^4y+xy^4=xy\left(x^3+y^3\right)=xy\left(x+y\right)\left(x^2-xy+y^2\right)\)

e) \(3x^4-75x^2y^2=3x^2\left(x^2-25y^2\right)=3x^2\left(x+5y\right)\left(x-5y\right)\).

f) \(4x^4+y^4=\left(2x^2+y^2\right)^2-\left(2xy\right)^2=\left(2x^2+y^2+2xy\right)\left(2x^2-y^2-2xy\right)\)