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\(x^2+4x-9y^2+4\)
\(=\left(x^2+2.2x+2^2\right)-\left(3y\right)^2\)
\(=\left(x+2\right)^2-\left(3y\right)^2\)
\(=\left(x+2-3y\right)\left(x+2+3y\right)\)
\(x^2-9y^2-6y-1\)
\(=x^2-\left[\left(3y\right)^2+2.3y+1^2\right]\)
\(=x^2-\left(3y+1\right)^2\)
\(=\left(x-3y-1\right)\left(x+3y+1\right)\)
Tham khảo nhé~
a/Ta có:x2+4x-9y2+4
=x2+4x+4-(3y)2
=(x+2)2-(3y)2
=(x+2-3y)(x+2+3y)
b/Ta có:x2-9y2-6xy-1
=x2-6xy-(3y)2-1
=(x-3y-1)(x-3y+1)
a) = (4x2 +4x + 1) - (9y2 + 6y + 1) = (2x+ 1)2 - (3y + 1)2 = (2x+ 1+ 3y + 1).(2x + 1 - 3y - 1) = (2x+ 3y+ 2).(2x-3y)
b) = x2 - 2015x + 2014x - 2014.2015 = x.(x - 2015) + 2014. (x - 2015) = (x + 2014).(x - 2015)
4x^2+2xy-18xy-9y^2
=2x(2x+y)-9y(2x+y)
=(2x-9y)(2x+y)
Sorry bài trên mình làm sai
a: =x^2+5x-x-5
=(x+5)(x-1)
b: =4x^2-(y-3)^2
=(2x-y+3)(2x+y-3)
a: \(ab+a+b+1\)
\(=a\left(b+1\right)+\left(b+1\right)\)
\(=\left(b+1\right)\left(a+1\right)\)
c: \(4x^2-12xy+3x-9y\)
\(=4x\left(x-3y\right)+3\left(x-3y\right)\)
\(=\left(x-3y\right)\left(4x+3\right)\)
4x2 + 4x - 9y2 + 1
= (4x2 + 4x + 1) - 9y2
= (2x + 1)2 - 9y2
= (2x + 1 - 3y)(2x + 1 + 3y)
4x2 - 11xy + 6y2
= 4x2 - 8xy - 3xy + 6y2
= 4x( x - 2y ) - 3y( x - 2y )
= ( x - 2y )( 4x - 3y )
4x2 - 9y2 + 4x - 6y
= (2x - 3y)(2x + 3y) + 2(2x - 3y)
= (2x - 3y)(2x + 3y + 2)
\(4x^2-9y^2+4x-6y\)
\(=\left(4x^2+4x+1\right)-\left(9y^2+6y+1\right)\)
\(=\left(2x+1\right)^2-\left(3y+1\right)^2\)
\(=\left(2x+1-3y-1\right)\left(2x+1+3y+1\right)\)
\(=\left(2x-3y\right)\left(2x+3y+2\right)\)