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a, |- 5| . (-7) + 4 . (-9)
= 5 . (-7) + (-36)
= (-35) + (-36)
= -71
b, |-15 + 21|-|-4 - 11|
= 6 - 15
= -9
c, [(-27)+43] + (-7) . 3
= 16 + (-21)
= -5
d, - (- 526) + (- 350) + (- 150) + 74
= 526 + (- 350) + (- 150) + 74
= 526 + (- 500) + 74
= 26 + 74
= 100
e, 2145 - (174 - 2145) + (- 68 + 174)
= 2145 - 174 + 2145 + (- 68) + 174
= 2145 + 2145 - (174 - 174) + (- 68)
= 4290 - 0 + (- 68)
= 4290 + (- 68)
= 4222
a) = 5.(-7)+4.(-9)=-35-36=-71
b) =6-15=-11
c) =16-21=-5
d)=526-350-150+74= (526+74)-(350+150)= 600- 500=100
e) 2145-174+2145-68+174
=2145+2145-68
=4222
g) =25. (-72+21-49)
=25. (-100)=-2500
i, h) tương tự nhé
Câu 2:
a: \(=9\cdot8-72:4=72-18=54\)
b: \(=125\cdot26+125\cdot32+125\cdot42\)
\(=125\left(26+32+42\right)=125\cdot100=12500\)
c: \(=5871:\left(928-825\right)+1=5871:103+1=57+1=58\)
d: \(=2012+78-178-2012=-100\)
a) \(9\cdot2^3-72:2^2\)
\(=72-18=54\)
b) \(125\cdot26+5^3\cdot32+25\cdot42\cdot5\)
\(=125\cdot26+125\cdot32+125\cdot42\)
\(=125\cdot\left(26+32+42\right)=125\cdot100=12500\)
c) \(5871:\left[928-\left(247-82\right)\cdot5\right]+2012^0\)
\(=5871:\left[928-\left(247-82\right)\cdot5\right]+1\)
\(=5871:\left(928-165\cdot5\right)+1\)
\(=5871:103+1\)
\(=58\)
d) \(2012+78+\left(-178\right)+\left(-2012\right)\)
\(=\left[2012+\left(-2012\right)\right]+\left[78+\left(-178\right)\right]\)
\(=-100\)
a, \(9.2^3-\frac{72}{2^2}=9.8-\frac{72}{4}=72-18=54\)
b, \(125.26+5^3.32+25.42.5\)
\(=125.26+125.32+125.42\)
\(=125.\left(26+32+42\right)\)
\(=125.100\)
\(=12500\)
c, \(\frac{5871}{\left[928-\left(247-82\right).5\right]}+2012^0\)
\(=\frac{5871}{103}+1\)
\(=57+1\)
\(=58\)
d, \(2012+78+\left(-178\right)+\left(-2012\right)\)
\(=\left[2012+\left(-2012\right)\right]+\left[78+\left(-178\right)\right]\)
\(=0+100\)
\(=100\)
a, => 3^x.(6+4.3) = 100-72
=> 3^x.18 = 18
=> 3^x = 18:18 = 1
=> 3^x = 3^0
=> x=0
b, => 5^x.(5+4.5) = -12+175-38
=> 5^x.25 = 125
=> 5^x = 125:25 = 5
=> 5^x = 5^1
=> x=1
Tk mk nha
a) \(6\cdot3^x+4\cdot3^{x+1}=100+\left(-72\right)\)
\(\Leftrightarrow6\cdot3^x+4\cdot3^x\cdot3=100-72\)
\(\Leftrightarrow6\cdot3^x+12\cdot3^x=28\)
\(\Leftrightarrow18\cdot3^x=28\Leftrightarrow3^x=\frac{14}{9}\)
Phần a) bn xem lại đề bài nhé!!
b) \(5\cdot5^x+4\cdot5^{x+1}=\left(-12\right)+175+\left(-38\right)\)
\(\Leftrightarrow5^{x+1}+4\cdot5^{x+1}=175-12-38\)
\(\Leftrightarrow5\cdot5^{x+1}=125\Leftrightarrow5^{x+1}=25\)
\(\Leftrightarrow5^{x+1}=5^2\Leftrightarrow x+1=2\Leftrightarrow x=1\)
Vậy x=1
\(75-\left(3.5^2-4.2^3\right)\)
\(=75-3.25+4.8\)
\(=75-75+32\)
\(=32\)
\(72:\left[32+\left(100-2^2.17\right):8\right]\)
\(=72:\left[32+\left(100-4.17\right):8\right]\)
\(=72:\left[32+\left(100-68\right):8\right]\)
\(=72:\left(32+32:8\right)\)
\(=72:\left(32+4\right)\)
\(=72:36\)
\(=2\)