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44 + 45 + 46 + 47 + 48 + 49 + 50 + 51
= \(\left[\left(51-44\right):1+1\right].\left(\frac{51+44}{2}\right)\)
= \(8.\frac{95}{2}\)
= \(380\)
Vậy 44 + 45 + 46 + 47 + 48 + 49 + 50 + 51 = 380
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3P = 1.2.3 + 2.3.3 + 3.4.3 + ... + 49.50.3
= 1.2.3 + 2.3.( 4 - 1 ) + 3.4.( 5 - 2 ) + ... + 49.50.( 51 - 48 )
= 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ... + 49.50.51 - 48.49.50
= 49.50.51 => P = \(\frac{49.50.51}{3}=41650\)
\(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{49.50}\)
=\(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{49}-\frac{1}{50}\)
=\(\frac{1}{2}-\frac{1}{50}\)
=\(\frac{12}{25}\)
Dấu chấm là dấu nhân,bạn bít rồi đúng ko
\(\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{49\cdot50}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{49}-\frac{1}{50}\)
\(=\frac{1}{2}-\frac{1}{50}=\frac{25}{50}-\frac{1}{50}=\frac{24}{50}=\frac{12}{25}\)
Công thức : \(\frac{a}{b\left(b+a\right)}=\frac{1}{b}-\frac{1}{b+a}\)
\(\frac{2a}{b\left(b+a\right)\left(b+2a\right)}=\frac{1}{b\left(b+a\right)}-\frac{1}{\left(b+a\right)\left(b+2a\right)}\)
\(\frac{3a}{b\left(b+a\right)\left(b+2a\right)\left(b+3a\right)}=\frac{1}{b\left(b+a\right)\left(b+2a\right)}-\frac{1}{\left(b+a\right)\left(b+2a\right)\left(b+3a\right)}\)
a,(18+29)+(158-18-29)=18+29+158-18-29=158
b,(-13-135+49)-(13+49)=-13-135+49-13-49=-26-135=-161
c,(-25)+15=-10
d,(-99)+(-100)+(-101)+(-102)=-99-100-101-102=-402
e,34+(-11)+(-4)=34-4-11=19
f,134+45+(-14)+(-5)=(134-14)+(45-5)=120+40=160
g,21+(-50)+(-1)=(21-1)-50=20-50=-30
h,44+(-213)+/-156/=44+213+156=(44+156)+213=200+213=413
i,212+[37+(-312)+(-17)]=212+37-312-17=(212-312)+(37-17)=-100+20=-80
-420-{-50+[-70+65-(54-49)]}
=-420-{-50+[-70+65-54+49]}
=-420-(-50-70+65-54+49)
=-420+50+70-65+54-49
=-360
`24 xx ( 15 + 49) + 12 xx (50 + 42)`
`=24 xx 64 + 12 xx 92`
`=24 xx 64 + (12 xx2) xx 46`
`= 24 xx 64 + 24 xx 46`
`= 24 xx ( 64 + 46)`
`=24 xx 110`
`=24 xx 100 + 24 xx 10`
`=2400 + 24 xx 10`
`=2400 + 240`
`=2640`
`#LeMichael`
24.(15+49)+12(50+42)
=24.64+12.92
=24.64+24.46
=24.110=2640