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x+(x+1)+...+(x+30)=1240
\(\Rightarrow\left(x+x+...+x\right)+\left(1+2+...+30\right)=1240\)
\(\Rightarrow31x+465=1240\)
\(\Rightarrow31x=775\)
\(\Rightarrow x=25\)
\(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=1240\)
\(\Rightarrow\left(x+x+x+...+x\right)+\left(1+2+...+30\right)=1240\) ( 31 số x )
\(\Rightarrow31x+465=1240\)
\(\Rightarrow31x=775\)
\(\Rightarrow x=25\)
Vậy x = 25
Ta có:
\(2^x.4=128\Rightarrow2^x=128:4=32\Rightarrow2^x=2^5\Rightarrow x=5.\) |
\(x^{15}=x\Rightarrow x=\left\{0;1;-1\right\}\) |
\(\left(x-5\right)^5=\left(x-5\right)^6\) \(\Rightarrow x-5\in\left\{0;1;-1\right\}\) \(\Rightarrow x=\left\{5;6;4\right\}\) |
Trả lời:
\(\frac{112}{71}+\frac{-17}{-83}-\frac{-41}{-71}-\frac{-66}{83}\)
=\(\frac{112}{71}+\frac{17}{83}-\frac{41}{71}+\frac{66}{83}\)
\(=\frac{112}{71}-\frac{41}{71}+\frac{17}{83}+\frac{66}{83}\)
\(=1+1\)
\(=2\)
Tk mk nha!
C1: \(\frac{4}{7}+\frac{4}{7}=\frac{8}{7}\)
C2 \(\frac{6}{11}\div\frac{-3}{7}=\frac{6}{11}\times\frac{-7}{3}=\frac{-14}{11}\)
C3\(\frac{-1}{49}\times\frac{7}{11}=\frac{-7}{539}\)
C4 \(\frac{-201}{73}+\frac{55}{73}+\frac{-205}{79}+\frac{47}{79}=\frac{-2}{1}+\frac{-2}{1}=-4\)
góc cần tìm ..ou= 80/2=40< bị liệt phím rét>
/a-1/=0 s/ra :a-1=0 s/ra a=1
C10 bOc= 85 <25+[160-50)/2]>
201-[x-4]=103
x-4=201-103
x-4=98
x=98+4
x=102
201 - (x-4)=1751:17
201-(x-4)=103
x-4=201-103
x-4=98
x=98+4
x=102