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400 : { 5. [ 360 - ( 290 + 2.52 ) ] }
=400:{5.[360-(290+50)]}
=400:[5.(360-340)]
=400:(5.20)
=400:100
=4
TÍCH NHA
400: {5.[360-(290+2.52)]}
=400: {5.[360-(290+2.25)]}
=400: {5.[360-(290+50)]}
=400: {5.[360-340]}
=400: {5.20}
=400:100
=4
400 : { 5 . [ 360 - ( 290 + 2 . 55 )]}
= 400 : { 5 . [ 360 - ( 290 + 2 . 25 )]}
= 400 : { 5 . [ 360 - ( 290 + 50 )]}
= 400 : [ 5 . ( 360 - 340 )]
= 400 : ( 5 . 20 )
= 200 : 100 = 2
400/ {5.[360-(290+2.5 mũ 2)]} =400/ {5.[360-(290+2.25)]} =400/{5.[360-(290+50)]} =400/{5.[360-340]} =400/{5.20} =400/100 =4
5 x 23 + 711 : 79 - 12018
= 5 x 8 + 49 - 1
= 40 + 48
= 88
400 : { 5 x ( 290 + 2 x 52)}
= 400 : { 5 x ( 290 + 2 x 25 ) }
= 400 : { 5 x ( 290 + 50)}
= 400 : { 5 x 240 }
= 400 : 1000
= 2/5
còn câu 1 ko hiểu x là tìm x hay là dấu nhân??
\(5\cdot2^2+7^{11}:7^9-1^8\)
\(=20+2^2-1\)
\(=20+4-1\)
\(=23\)
\(400:\left\{5\cdot\left[360-\left(290+2\cdot5^2\right)\right]\right\}\)
\(=400:\left\{5\cdot\left[360-\left(290+50\right)\right]\right\}\)
\(=400:\left(5\cdot\left[360-340\right]\right)\)
\(=400:\left(5\cdot20\right)\)
\(=400:100\)
\(=4\)
Ta có \(5^x=125\)
\(\Rightarrow5^x=5^3\Rightarrow x=3\)
Vậy x = 3
b,\(3^{2x}=81\)
\(\Rightarrow3^{2x}=3^4\Rightarrow2x=4\Rightarrow x=2\)
Vậy x = 2
c,\(5^{2x-3}-2.5^2=5^2.3\)
\(\Rightarrow5^{2x-3}=5^2.3+5^2.2\Rightarrow5^{2x-3}=5^2.\left(2+3\right)\Rightarrow5^{2x-3}=5^3\)
\(\Rightarrow2x-3=3\Rightarrow2x=6\Rightarrow x=3\)
Vậy x = 3
2.25.9+{[2.125-(5x+4).5]:(4.3.5)}=453
50.9+{[350-(5x+4).5]:60}=453
450+{[350-(5x+4).5]:60}=453
[350-(5x+4).5]:60=453-450
[350-(5x+4).5]:60=3
350-(5x+4).5=3.60
350-(5x+4).5=180
350-(5x+4)=180:5
350-(5x+4)=36
5x+4=350-36
5x+4=314
5x=314-4
5x=310
x=310:5
x=62
2.25.9+{[2.125-25.x-20]:(4.3.5)}=453
450 +{[250-25.x -20]:60 }=453
450 +{[230-25.x] :60 }=453
450 +{23/6-13/30x }=453
23/6-5/12x =453-450
46/12-5/12x =3
(46-5x)/12 =3
46-5x =3.12=36
5x =46-36=10
x=2
Mình viết cách ra cho dễ hiểu đó
a, 52x - 3 - 2.52 = 52.3
=> 52x - 3 - 50 = 75
=> 52x - 3 = 125
=> 52x - 3 = 53
=> 2x - 3 = 3
=> 2x = 0
=> x = 0
vậy_
b, (x + 1) + (x + 2) + ....+ (x + 100) = 5750
=> x + 1 + x + 2 + ... + x + 100 = 5750
=> (x + x + x + ... + x) + (1 + 2 + 3 + ... + 100) = 5750
=> 100x + 5050 = 5750
=> 100x = 700
=> x = 7
vậy_
\(400\div\left\{5\left[360-\left(290+2.5^2\right)\right]\right\}\)
\(=400\div\left\{5\left[360-\left(290+50\right)\right]\right\}=400\div\left[5\left(360-340\right)\right]\)
\(=400\div\left(5.20\right)=400\div100=4\)
Bài giải
\(400\text{ : }\left[5\left\{360-\left(290+2\cdot5^2\right)\right\}\right]\)
\(=400\text{ : }\left[5\left\{360-\left(290+50\right)\right\}\right]\)
\(=400\text{ : }\left[5\left\{360-340\right\}\right]\)
\(=400\text{ : }\left[5\cdot20\right]\)
\(=400\text{ : }100\)
\(=4\)