Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) FexOy + yH2 → xFe + yH2O
b) 2CxHy +\(\frac{4x-y}{2}O_2\) → 2xCO2 + yH2O
c) 2CxHyOz + \(\frac{4x+y-2z}{2}\)O2 → 2xCO2 + yH2O
d) FexOy + 2yHCl → xFeCl2y/x + yH2O
đ) CnH2n+2 + \(\frac{3n+1}{2}\)O2 → nCO2 + (n+1)H2O
e) 2CnH2n + 3nO2 → 2nCO2 + 2nH2O
f) CnH2n - 2 + \(\frac{3n-1}{2}\)O2 → nCO2 + (n-1)H2O
CHÚC BẠN HỌC TỐT!!
(Theo mình pt số 3 sản phẩm là:\(FeCl_{\dfrac{2y}{x}}\))
\(2C_nH_{2n-2}+\left(3n-1\right)O_2\underrightarrow{o}2nCO_2+\left(2\left(n-1\right)\right)H_2O\)
\(2C_nH_{2n+2}+\left(3n+1\right)O_2\underrightarrow{o}2nCO_2+\left(2\left(n+1\right)\right)H_2O\)
\(Fe_xO_y+2yHCl\rightarrow xFeCl_{\dfrac{2y}{x}}+yH_2O\)
\(4C_xH_yN_t+\left(4x+y\right)O_2\underrightarrow{o}4xCO_2+2yH_2O+2tN_2\)
1) 2CnH2n + 3nO2 -> 2nCO2 + 2nH2O
2) 2CnH2n+2 + (3n+1)O2 -> 2nCO2 + (2n+2)H2O
3) 2CnH2n-2 + (3n-1)O2 -> 2nCO2 + (2n-2)H2O
4) 2CnH2n-6 + (3n-3)O2 -> 2nCO2 + (2n-6)H2O
5) 2CnH2n+2O + (3n+1)O2 -> 2nCO2 + (2n+2)H2O
6) 4CxHy + (4x+y)O2 -> 4xCO2 + 2yH2O
7) 4CxHyOz + (4x+y-2z)O2 -> 4xCO2 + 2yH2O
8)4CxHyOzNt +(4x+y-2z)O2 ->4xCO2 +2yH2O +2tN2
9) 4CHx + (2y+x)O2 -> 4COy + 2xH2O
10) 2FeClx + (3-x)Cl2 -> 2FeCl3
2)CnH2n+2+(3n+1)/2O2 -> nCO2+(n+1)H2O
3)CnH2n-2+(3n-1)/2O2->nCO2+(n-1)H2O
4)CnH2n-6+3/2(n-1)O2 -> nCO2+(n-3)H2O
1. \(C_nH_{2n+2}+\dfrac{3x+1}{2}O_2\rightarrow nCO_2+\left(n+1\right)H_2O\)
2. \(C_xH_yO_z+\left(x+\dfrac{y}{4}+\dfrac{z}{2}\right)O_2\rightarrow xCO_2+\dfrac{y}{2}H_2O\)
1) CxHyOz +\(\left(x+\frac{y}{4}-\frac{z}{2}\right)\)O2----> xCO2 +\(\frac{y}{2}\)H2O
2) CnH2n-6 + \(\left(n+\frac{n-3}{4}\right)\)O2 ----> nCO2 + \(\frac{y}{2}\)H2O
1) CxHyOz +\(\left(x+\frac{y}{4}-\frac{z}{2}\right)\) O2----> xCO2 + \(\frac{y}{2}\)H2O
CnH2n+2+ \(\frac{3n+1}{2}\)O2 \(\underrightarrow{t^o}\) n CO2 +n+1 H2O
kùn zì hun
a) 2CxHyOz + \(\dfrac{4x+y-2z}{2}\)O2 \(\rightarrow\) 2xCO2 + yH2O
b) CnH2n+2 + \(\dfrac{3n+1}{2}\)O2 \(\rightarrow\) nCO2 + (n+1)H2O
\(C_nH_{2n}+\dfrac{3n}{2}O_2\underrightarrow{^{^{t^0}}}nCO_2+nH_2O\)
\(C_nH_{2n+2}+\dfrac{3n+1}{2}O_2\underrightarrow{^{^{t^0}}}nCO_2+\left(n+1\right)H_2O\)
cảm ơn a