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a) \(\frac{5}{6}< \frac{6}{7}\)
b) \(\frac{5}{8}=\frac{50}{80}\)
c) \(\frac{3}{4}>\frac{5}{7}\)
d) \(\frac{9}{7}< \frac{8}{5}\)
1)
a) Do 5/5 = 1
=> 1/5 < 1
Do 6/6 = 1
=> 7/6 > 1
=> 7/6 > 1/5
b) Như trên ta có : 3/7 < 1
4/2 > 1
=> 4/2 > 3/7
2)
a ) <
b) >
c) =
\(a,4\frac{1}{2}< 4\frac{3}{4}\)
\(b,2\frac{4}{5}< 3\frac{1}{4}\)
\(c,7\frac{2}{9}>5\frac{2}{9}\)
\(d,13\frac{5}{6}< 13\frac{6}{7}\)
Nao Tomori
\(a,4\frac{1}{2}....4\frac{3}{4}\Rightarrow4\frac{1}{2}=\frac{13}{2};4\frac{3}{4}=\frac{19}{4}\)
\(=4\frac{1}{2}< 4\frac{3}{4}\)
\(b,2\frac{4}{5}....3\frac{1}{4}\Rightarrow2\frac{4}{5}=\frac{14}{5};3\frac{1}{4}=\frac{13}{12}\)
\(=2\frac{4}{5}>3\frac{1}{4}\)
\(c,7\frac{2}{9}....5\frac{2}{9}\Rightarrow7\frac{2}{9}=\frac{65}{9};5\frac{2}{9}=\frac{42}{9}\)
\(=7\frac{2}{9}>5\frac{2}{9}\)
\(d,13\frac{5}{6}....13\frac{6}{7}\Rightarrow13\frac{5}{6}=\frac{83}{6};13\frac{6}{7}=\frac{97}{7}\)
\(=13\frac{5}{6}< 13\frac{6}{7}\)
P/s: Quy đồng là bước trung gian nên mk ko ghi bước quy đồng nha
\(200+6+\frac{3}{100}\) \(27+\frac{4}{10}+\frac{6}{100}\)
= \(206+\frac{3}{100}\) = \(\frac{2700}{100}+\frac{40}{100}+\frac{6}{100}\)
= \(\frac{20600}{100}+\frac{3}{100}\) = \(\frac{2746}{100}\)
= \(\frac{20603}{100}\)
\(3\frac{2}{5}=3,4>3,25\) \(4\frac{1}{20}=4,05< 4,2\)
\(21,09< 21\frac{1}{10}=21,1\) \(8\frac{7}{20}=8,35\)
\(200+6+\frac{3}{100}=\frac{20603}{100}=206,03=206+\frac{3}{100}\)
\(27+\frac{4}{10}+\frac{6}{100}=27+\frac{23}{50}\)
Bài 2
\(3\frac{2}{5}=\frac{17}{5}=3,\: \: 4\: \: \) \(3,25=\frac{13}{4}\)
\(\Rightarrow3\frac{2}{5}>3,25\)
b)
\(4\frac{1}{20}< 4,2\)
c)
\(8\frac{7}{20}=8,35\)
\(6\frac{8}{2}..........\frac{20}{2}\)
\(6\frac{8}{2}=\frac{20}{2}=10\)
\(\frac{20}{2}=10\)
\(10=10\) nên \(6\frac{8}{2}=\frac{20}{2}\)
\(5\frac{3}{4}......6\frac{4}{2}\)
vì \(5< 6\) nên \(5\frac{3}{4}< 6\frac{4}{2}\)
k mình nha