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(1)
(x+1)(x-7)+17>0
<=>x^2-6x+9+1>0
<=>(x-3)^2+1>0(dpcm)
..
(7)
-y^2+4y-4-|x+1|≤0
<=>-(y-2)^2-|x+1|≤0
sum 2 so khong duong ko the la so (+)=>dpcm
2. \(-x^2+2x-2=-\left(x^2+2x+1\right)-1=-\left(x+1\right)^2-1\)
vì: \(-\left(x+1\right)^2\forall x\le0\Rightarrow-\left(x+1\right)^2-1\le-1< 0\left(đpcm\right)\)
6.
\(\left(x-2\right)\left(x-4\right)+3=x^2-6x+11=\left(x^2-6x+9\right)+2=\left(x-3\right)^2+2\)
vì: \(\left(x-3\right)^2\ge0\forall x\Rightarrow\left(x-3\right)^2+2\ge2>0\left(đpcm\right)\)
1. 4x2 + 4x + 2 = (4x2 + 4x + 1) + 1 = (2x + 1)2 + 1
Có: (2x+1)2 ≥ 0 ∀x => (2x+1)2 + 1 ≥ 1 > 0 (đpcm)
3. -x2 + 4x - 5 = -(x2 - 4x + 4) - 1 = -(x - 2)^2 - 1
Có: -(x-2)^2 ≤ 0 => -(x-2)^2 -1 ≤ - 1 < 0 (đpcm)
7. (x+2)(x-5) + 15 = x2 - 3x + 5 = (x2 - 2.x.\(\dfrac{3}{2}\)+ \(\dfrac{9}{4}\)) + \(\dfrac{11}{4}\)
= ( x - \(\dfrac{3}{2}\))^2 + \(\dfrac{11}{4}\) \(\ge\dfrac{11}{4}>0\left(đpcm\right)\)
1: \(=-\left(x^2+2x+2\right)=-\left(x^2+2x+1+1\right)=-\left(x+1\right)^2-1< =-1\)
Dấu '=' xảy ra khi x=-1
2: \(=-\left(4x^2-12x-10\right)\)
\(=-\left(4x^2-12x+9-19\right)\)
\(=-\left(2x-3\right)^2+19< =19\)
Dấu '=' xảy ra khi x=3/2
3: \(=-\left(x^2+4x+4-4\right)=-\left(x+2\right)^2+4< =4\)
Dấu '=' xảy ra khi x=-2
x^2 -6x +10 = x^2 -2.x.3 +3^2 +1 = (x-3)^2 +1
Ma (x-3)^2 >=0 <=> (x-3)^2 +1 >=1>0 (voi moi x)
b) 4x - x^2 -5 = -(x^2 -4x +5) =-[(x^2 -4x +4)+1] = -[(x-2)^2 +1]
Ma (x+2)^2 >=0 <=> (x-2)^2 +1 >=1 <=> -[(x-2)^2 +1] <=-1 => -[(x-2)^2 +1] <0
2) a) P= x^2 -2x +5 = x^2 -2x +1 +4 = (x-1)^2 +4
Ta co: (x-1)^2 >=0 <=> (x-1)^2 +4 >=4
Vay gia tri nho nhat P=4 khi x=1
b) Q= 2x^2 -6x = 2(x^2 -3x) = 2(x^2 - 2.x.3/2 + 9/4 -9/4)= 2[(x-3/2)^2 -9/4]
Ta co: (x-3/2)^2 >=0 <=>(x-3/2)^2 -9/4 >= -9/4 <=> 2[(x-3/2)^2 -9/4] >= -9/2
Vay gia tri nho nhat Q= -9/2 khi x= 3/2
c) M= x^2 +y^2 -x +6y +10 = (x^2 -2.x.1/2 + 1/4) +(y^2 +2.y.3+9)+3/4
= ( x-1/2)^2 + (y+3)^2 +3/4
M>= 3/4
Vay GTNN cua M = 3/4 khi x=1/2 va y=-3
3)a) A= 4x - x^2 +3 = -(x^2 -4x -3) = -( x^2 -4x+4 -7) =-[(x-2)^2 -7]
Ta co: (x-2)^2>=0 <=> (x-2)^2 -7 >=-7 <=> -[(x-2)^2 -7] <=7
Vay GTLN A=7 khi x=2
b) B= x-x^2 = -(x^2 -2.x.1/2+1/4-1/4) = -[(x-1/2)^2 -1/4]
GTLN B= 1/4 khi x=1/2
c) N= 2x - 2x^2 -5 =-2( x^2 -x+5/2) = -2(x^2 - 2.x.1/2 +1/4 +9/4)
= -2[(x-1/2)^2 +9/4]
GTLN N= -9/2 khi x=1/2
1.(x+1)(x-7)+17=(x-3)2+1>0
2.-20-(x-5)(x+3)=-34-(x-1)2<0
3.-2(x+3)-(x-2)(x+2)=-(x+1)2-1<0
4.x2+y2+2x+2y+3=(x+1)2+(y+1)2+1>0
5.2x2+2x+y2+2y+5=2(x+1/2)2+(y+1)2+2>0
6.2x2+2y2+2xy+2x+4y+6=(x+y)2+(x+1)2+(y+2)2+1>0
7.-y2+4y-4-/x+1/=-(y-2)2-/x+1/≤0