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Dạng 3 :

a) 3x - 10 = 2x + 13

=> 3x - 2x = 13 - 10

=> x = 3

b) x + 12 = -5 - x

=> x + x = -5 - 12

=> 2x = -17

=> x = -8,5

c) x + 5 = 10 - x 

=> x + x = 10 - 5

=> 2x = 5

=> x = 2,5

d) 6x + 23 = 2x - 12

=> 2x - 6x = 23 + 12

=> -4x = 35

=> x = -8,75

e) 12 - x = x + 1

=> x + x = 12 - 1

=> 2x = 11

=> x = 5,5

f) 14 + 4x = 3x + 20

=> 4x - 3x = 20 - 14

=> x = 6

a) \(3x-10=2x+13\Leftrightarrow x=13+10=23\)

b) \(x+12=-5-x\Leftrightarrow2x=-17\Leftrightarrow x=-\frac{17}{2}\)

c) \(x+5=10-x\Leftrightarrow2x=5\Leftrightarrow x=\frac{5}{2}\)

d) \(6x+23=2x-12\Leftrightarrow4x=-35\Leftrightarrow x=-\frac{35}{4}\)

e) \(12-x=x+1\Leftrightarrow2x=11\Leftrightarrow x=\frac{11}{2}\)

f) \(14+4x=3x+20\Leftrightarrow x=20-14=6\)

g) \(2\left(x-1\right)+3\left(x-2\right)=x-4\Leftrightarrow2x-2+3x-6=x-4\)

\(\Leftrightarrow5x-8=x-4\Leftrightarrow4x=4\Leftrightarrow x=1\)

h ) \(3\left(4-x\right)-2\left(x-1\right)=x+20\Leftrightarrow12-3x-2x+2=x+20\)

\(\Leftrightarrow14-5x=x+20\Leftrightarrow6x=-6\Leftrightarrow x=-1\)

i ) \(4\left(2x+7\right)-3\left(3x-2\right)=24\Leftrightarrow8x+28-9x+6=24\)

\(\Leftrightarrow34-x=24\Leftrightarrow x=34-24=10\)

k) \(3\left(x-2\right)+2x=10\Leftrightarrow3x-6+2x=5x-6=10\)

\(\Leftrightarrow5x=10+6=16\Leftrightarrow x=\frac{16}{5}\)

Tự KL cho các phần

28 tháng 3 2020

a. 3x-10=2x+13

    3x-2x=13+10

            x=23

28 tháng 3 2020

a) \(3x-10=2x+13\)

\(\Leftrightarrow3x-2x=13+10\)

\(\Leftrightarrow x=23\)

b) \(x+12=-5-x\)

\(\Leftrightarrow x+x=-5-12\)

\(\Leftrightarrow2x=-17\)

\(\Leftrightarrow x=-\frac{17}{2}\)

c) \(x+5=10-x\)

\(\Leftrightarrow x+x=10-5\)

\(\Leftrightarrow2x=5\)

\(\Leftrightarrow x=\frac{5}{2}\)

d) \(6x+2^3=2x-12\)

\(\Leftrightarrow6x+8=2x-12\)

\(\Leftrightarrow6x-2x=-12-8\)

\(\Leftrightarrow4x=-20\)

\(\Leftrightarrow x=-5\)

e) \(12-x=x+1\)

\(\Leftrightarrow-x-x=1-12\)

\(\Leftrightarrow-2x=-11\)

\(\Leftrightarrow x=\frac{11}{2}\)

g) \(2\left(x-1\right)+3\left(x-2\right)=x-4\)

\(\Leftrightarrow2x-2+3x-6=x-4\)

\(\Leftrightarrow2x+3x-x=-4+6+2\)

\(\Leftrightarrow4x=4\)

\(\Leftrightarrow x=1\)

h) \(14+4x=3x+20\)

\(\Leftrightarrow4x-3x=20-14\)

\(\Leftrightarrow x=6\)

i) \(4\left(2x+7\right)-3\left(3x-2\right)=24\)

\(\Leftrightarrow8x+28-9x+6=24\)

\(\Leftrightarrow8x-9x=24-6-28\)

\(\Leftrightarrow-x=-10\)

\(\Leftrightarrow x=10\)

k) \(3\left(4-x\right)-2\left(x-1\right)=x+20\)

\(\Leftrightarrow12-3x-2x+2=x+20\)

\(\Leftrightarrow-3x-2x-x=20-2-12\)

\(\Leftrightarrow-6x=6\)

\(x=-1\)

l) \(3\left(x-2\right)+2x=10\)

\(\Leftrightarrow3x-6+2x=10\)

\(\Leftrightarrow3x+2x=10+6\)

\(\Leftrightarrow5x=16\)

\(\Leftrightarrow x=\frac{16}{5}\)

Lần sau bạn chỉ nên đăng ít câu hỏi một thôi nhé, đăng nnay các bạn làm không xuể đâu

26 tháng 3 2020

a,3x-10=2x+13

\(\Rightarrow\)3x-2x=10+13

\(\Rightarrow\)x=23

b,x+12=-5-x

\(\Rightarrow\)x+x=-12-5

\(\Rightarrow\)2x=-17

\(\Rightarrow\)x=-8,5

c,x+5=10-x

\(\Rightarrow\)x+x=-5+10

\(\Rightarrow\)2x=5

\(\Rightarrow\)x=2,5

e,12-x=x+1

\(\Rightarrow\)-x-x=-12+1

\(\Rightarrow\)-2x=-11

\(\Rightarrow\)x=5,5

f,14+4x=3x+20

\(\Rightarrow\)4x-3x=-14+20

\(\Rightarrow\)x=6

g,2.(x-1)+3(x-2)=x-4

\(\Rightarrow\)2x-2+3x-6=x-4

\(\Rightarrow\)2x-2+3x-6-x+4=0

\(\Rightarrow\)4x-4=0

\(\Rightarrow\)4x=4

\(\Rightarrow\)x=1

h,3(4-x)-2(x-1)=x+20

\(\Rightarrow\)12-3x-2x+2-x-20=0

\(\Rightarrow\)-6x-6=0

\(\Rightarrow\)-6x=6

\(\Rightarrow\)x=-1

i,4(2x+7)-3(3x-2)=24

\(\Rightarrow\)8x+28-9x+6=24

\(\Rightarrow\)-x+34=24

\(\Rightarrow\)-x=-10

\(\Rightarrow\)x=10

k,3(x-2)+2x=10

\(\Rightarrow\)3x-6+2x=10

\(\Rightarrow\)5x-6=10

\(\Rightarrow\)5x=16

\(\Rightarrow\)x=3,2

Phần d, tớ không biết làm!!!!

26 tháng 3 2020

Nhưng bn cũng đã giúp tớ rùi . Thank kiu bạn

19 tháng 4 2019

Câu a \(\left|2x-\frac{1}{3}\right|+\frac{5}{6}=1\)

19 tháng 4 2019

g) \(\left(x+\frac{1}{2}\right)\left(\frac{2}{3}-2x\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x+\frac{1}{2}=0\\\frac{2}{3}-2x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{-1}{2}\\x=\frac{1}{3}\end{cases}}\)

Vây \(x\in\left\{\frac{-1}{2};\frac{1}{3}\right\}\)

\(\left(3x-1\right)⋮\left(x+1\right)\)

\(\Rightarrow\left(3x+3-4\right)⋮\left(x+1\right)\)

\(\Rightarrow\left(-4\right)⋮\left(x+1\right)\)

\(\Rightarrow x+1\inƯ\left(-4\right)=\left\{-4;-1;1;4\right\}\)

\(\Rightarrow x\in\left\{-5;-2;0;3\right\}\)

27 tháng 12 2018

a, ĐỂ \(\frac{24}{2n+5}\)là số nguyên 

\(\Rightarrow24⋮2n+5\Rightarrow2n+5\inƯ\left(24\right)=\left\{\pm1;\pm2;\pm3;\pm4;\pm6;\pm8;\pm12;\pm24\right\}\)

2n + 5 = 1 => 2n = -4 => n = -2 

2n + 5 = -1 => n = -3 

... tương tự thay vào nhé ! 

30 tháng 5 2016

a.

\(\frac{2}{3}x-\frac{3}{2}x=\frac{5}{12}\)

\(\left(\frac{2}{3}-\frac{3}{2}\right)\times x=\frac{5}{2}\)

\(\left(\frac{4-9}{6}\right)\times x=\frac{5}{2}\)

\(-\frac{5}{6}\times x=\frac{5}{2}\)

\(x=\frac{5}{2}\div\left(-\frac{5}{6}\right)\)

\(x=\frac{5}{2}\times\left(-\frac{6}{5}\right)\)

\(x=-3\)

b.

\(\frac{2}{5}+\frac{3}{5}\times\left(3x-3,7\right)=-\frac{53}{10}\)

\(\frac{3}{5}\times\left(3x-3,7\right)=-\frac{53}{10}-\frac{2}{5}\)

\(\frac{3}{5}\times\left(3x-3,7\right)=\frac{-53-4}{10}\)

\(\frac{3}{5}\times\left(3x-3,7\right)=-\frac{57}{10}\)

\(3x-3,7=-\frac{57}{10}\div\frac{3}{5}\)

\(3x-3,7=-\frac{57}{10}\times\frac{5}{3}\)

\(3x-\frac{37}{10}=-\frac{19}{2}\)

\(3x=-\frac{19}{2}+\frac{37}{10}\)

\(3x=\frac{-95+37}{10}\)

\(3x=-\frac{58}{10}\)

\(3x=-\frac{29}{5}\)

\(x=-\frac{29}{5}\div3\)

\(x=-\frac{29}{5}\times\frac{1}{3}\)

\(x=-\frac{29}{15}\)

c.

\(\frac{7}{9}\div\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)

\(\frac{7}{9}\div\left(2+\frac{3}{4}x\right)=\frac{23}{27}-\frac{5}{9}\)

\(\frac{7}{9}\div\left(2+\frac{3}{4}x\right)=\frac{23-15}{27}\)

\(\frac{7}{9}\div\left(2+\frac{3}{4}x\right)=\frac{8}{27}\)

\(2+\frac{3}{4}x=\frac{7}{9}\div\frac{8}{27}\)

\(2+\frac{3}{4}x=\frac{7}{9}\times\frac{27}{8}\)

\(2+\frac{3}{4}x=\frac{21}{8}\)

\(\frac{3}{4}x=\frac{21}{8}-2\)

\(\frac{3}{4}x=\frac{21-16}{8}\)

\(\frac{3}{4}x=\frac{5}{8}\)

\(x=\frac{5}{8}\div\frac{3}{4}\)

\(x=\frac{5}{8}\times\frac{4}{3}\)

\(x=\frac{5}{6}\)

d.

\(-\frac{2}{3}\times x+\frac{1}{5}=\frac{3}{10}\)

\(-\frac{2}{3}\times x=\frac{3}{10}-\frac{1}{5}\)

\(-\frac{2}{3}\times x=\frac{3-2}{10}\)

\(-\frac{2}{3}\times x=\frac{1}{10}\)

\(x=\frac{1}{10}\div\left(-\frac{2}{3}\right)\)

\(x=\frac{1}{10}\times\left(-\frac{3}{2}\right)\)

\(x=-\frac{3}{20}\)

e.

\(\left|x\right|-\frac{3}{4}=\frac{5}{3}\)

\(\left|x\right|=\frac{5}{3}+\frac{3}{4}\)

\(\left|x\right|=\frac{20+9}{12}\)

\(\left|x\right|=\frac{29}{12}\)

\(x=\pm\frac{29}{12}\)

Vậy \(x=\frac{29}{12}\) hoặc \(x=-\frac{29}{12}\)

f.

\(\left|2x-\frac{1}{3}\right|+\frac{5}{6}=1\)

\(\left|2x-\frac{1}{3}\right|=1-\frac{5}{6}\)

\(\left|2x-\frac{1}{3}\right|=\frac{6-5}{6}\)

\(\left|2x-\frac{1}{3}\right|=\frac{1}{6}\)

\(2x-\frac{1}{3}=\pm\frac{1}{6}\)

  • \(2x-\frac{1}{3}=\frac{1}{6}\)

                \(2x=\frac{1}{6}+\frac{1}{3}\)

                \(2x=\frac{1+2}{6}\)

                \(2x=\frac{3}{6}\)

                \(2x=\frac{1}{2}\)

                  \(x=\frac{1}{2}\div2\)

                  \(x=\frac{1}{2}\times\frac{1}{2}\)

                  \(x=\frac{1}{4}\)

  • \(2x-\frac{1}{3}=-\frac{1}{6}\)

                \(2x=-\frac{1}{6}+\frac{1}{3}\)

                \(2x=\frac{-1+2}{6}\)

                \(2x=\frac{1}{6}\)

                 \(x=\frac{1}{6}\div2\)

                 \(x=\frac{1}{6}\times\frac{1}{2}\)

                 \(x=\frac{1}{12}\)

Vậy x = 1/4 hoặc x = 1/12.

Chúc bạn học tốtok

30 tháng 5 2016

Sorry nha, mik chép lộn đềbucminhLàm lại câu a nhavui

a.

\(\frac{2}{3}x-\frac{3}{2}x=\frac{5}{12}\)

\(\left(\frac{2}{3}-\frac{3}{2}\right)\times x=\frac{5}{12}\)

\(\left(\frac{4-9}{6}\right)\times x=\frac{5}{12}\)

\(-\frac{5}{6}\times x=\frac{5}{12}\)

\(x=\frac{5}{12}\div\left(-\frac{5}{6}\right)\)

\(x=\frac{5}{12}\times\left(-\frac{6}{5}\right)\)

\(x=-\frac{1}{2}\)

Chúc bạn học tốtok

Bài 1: 

a: =>13x+8=9x+20

=>4x=12

hay x=3

b: \(\Leftrightarrow5x-7=-8-11-3x\)

=>5x-7=-3x-19

=>8x=-12

hay x=-3/2

c: \(\Leftrightarrow\left[{}\begin{matrix}12x-7=5\\12x-7=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{1}{6}\end{matrix}\right.\)

e: =>3x+1=-5

=>3x=-6

hay x=-2