Question

[Đỗ Thái Tuấn]

cho P=1/2.3/4.5/6.7/8.....9/100

CMR:1/15<P<1/10

Answer 1

[evermore Mathematics]

\(P>\frac{1}{2}\cdot\frac{3}{4}\cdot\frac{5}{6}\cdot\frac{7}{8}\cdot\cdot\cdot\frac{99}{100}\cdot\left(\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{4}{5}\cdot\frac{6}{7}\cdot...\cdot\frac{98}{99}\right)\)

\(P>\frac{49}{50}>\frac{1}{15}\)

\(P^2<\left(\frac{1}{2}\cdot\frac{3}{4}\cdot\frac{5}{6}\cdot\frac{7}{8}\cdot...\cdot\frac{99}{100}\right)\cdot\left(\frac{2}{3}\cdot\frac{4}{5}\cdot\frac{6}{7}\cdot\frac{8}{9}\cdot....\cdot\frac{100}{101}\right)\)

\(P^2<\frac{1}{101}<\frac{1}{10}\)

\(\Rightarrow\frac{1}{15}