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Cho sơ đồ phản ứng hóa học sau:
Cacbon+ O2 -------> X + CuO ------> Y+ z ------> T +nung ------> CaO + Y
=> Chọn C. CO, CO2, Ca(OH)2, CaCO3.
\(2C+O_2-^{t^o}\rightarrow2CO\)
\(CuO+CO-^{t^o}\rightarrow Cu+CO_2\)
\(CO_2+Ca\left(OH\right)_2\rightarrow CaCO_3+H_2O\)
\(CaCO_3-^{nung}\rightarrow CaO+CO_2\)
a)
\(C_6H_{12}O_6\underrightarrow{men}2C_2H_5OH+2CO_2\)
\(C_2H_5OH+CH_3COOH⇌CH_3COOC_2H_5+H_2O\)
\(2CH_3COOH+Mg\rightarrow\left(CH_3COO\right)_2Mg+H_2\)
b)
\(CH_2=CH_2+H_2O\rightarrow C_2H_5OH\)
\(C_2H_5OH+O_2\underrightarrow{men}CH_3COOH+2H_2O\)
\(2CH_3COOH+2Na\rightarrow2CH_3COONa+H_2\)
\(CH_3COONa+NaOH\xrightarrow[CaO]{t^o}CH_4+Na_2CO_3\)
C6H12O6 => (men rượu,to) 2CO2 + 2C2H5OH
C2H5OH + CH3COOH => (pứ hai chiều, to,H2SO4đ) CH3COOC2H5 + H2O
CH3COOC2H5 + NaOH => CH3COONa + C2H5OH
CH3COONa + NaOH => (to,CaO) Na2CO3 + CH4
4CxHy + (4x+y)O2 \(^{to}\rightarrow\) 4xCO2 \(\uparrow\) + 2yH2O
4CxHyOz +(4x+y-2z) O2 \(^{to}\rightarrow\) 4xCO2 \(\uparrow\) + 2yH2O
2CxHyNtOz + (2x-\(\dfrac{y}{2}\)-z)O2 \(^{to}\rightarrow\) 2xCO2 + yH2O + N2
1) 2Cu + O2 -to-➢ 2CuO
CuO + 2HCl → CuCl2 + H2O
CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl
2) S + H2 -to-➢ H2S
3) S + O2 -to-➢ SO2
2SO2 + O2 -to-➢ 2SO3
SO3 + H2O → H2SO4
H2SO4 + 2KOH → K2SO4 + 2H2O
4) S + Fe -to-➢ FeS
C2H4 + H2O \(\xrightarrow[Axit]{xt}\) C2H5OH (X: C2H4)
C2H5OH + O2 \(\xrightarrow[giấm]{men}\) CH3COOH + H2O (Y: CH3COOH)
2CH3COOH + Na2O → 2CH3COONa + H2O
CH3COONa + NaOH \(\xrightarrow[CaO]{to}\) CH4 + Na2CO3 (Z: CH4)
2CH4 \(\underrightarrow{to}\) C2H2 + 3H2