Question

[Đỗ Linh Hương]

cho biểu thức

\(P=\left[\left(\dfrac{1}{x^2}+1\right)\cdot\dfrac{1}{x^2+2x+1}+\dfrac{2}{\left(x+1\right)^3}\cdot\left(\dfrac{1}{x}+1\right)\right]\cdot\dfrac{x-1}{x^3}\)

a. Rút gọn P

\(\)b. tìm \(x\) để \(P=4\)

c. tìm \(x\) để \(P>0\)

d. tìm \(x\in z\) để \(P\in z\)

Answer 1

[Trần Nguyễn Bảo Quyên]

\(a.\)

\(P=\left[\left(\dfrac{1}{x^2}+1\right).\dfrac{1}{x^2+2x+1}+\dfrac{2}{\left(x+1\right)^3}.\left(\dfrac{1}{x}+1\right)\right].\dfrac{x-1}{x^3}\)

\(P=\left[\left(\dfrac{1}{x^2}+\dfrac{x^2}{x^2}\right).\dfrac{1}{x^2+2x+1}+\dfrac{2}{\left(x+1\right)^3}.\left(\dfrac{1}{x}+\dfrac{x}{x}\right)\right].\dfrac{x-1}{x^3}\)

\(P=\left[\dfrac{x^2+1}{x^2}.\dfrac{1}{x^2+2x+1}+\dfrac{2}{\left(x+1\right)^3}.\left(\dfrac{x+1}{x}\right)\right].\dfrac{x-1}{x^3}\)

\(P=\left[\dfrac{x^2+1}{x^2\left(x^2+2x+1\right)}+\dfrac{2}{x\left(x+1\right)^2}\right].\dfrac{x-1}{x^3}\)

\(P=\left[\dfrac{x^2+1}{x^4+2x^3+x^2}+\dfrac{2}{x^3+2x^2+x}\right].\dfrac{x-1}{x^3}\)

\(P=\left[\dfrac{x^2+1}{x^4+2x^3+x^2}+\dfrac{2x}{x\left(x^3+2x^2+x\right)}\right].\dfrac{x-1}{x^3}\)

\(P=\left[\dfrac{x^2+1}{x^4+2x^3+x^2}+\dfrac{2x}{x^4+2x^3+x^2}\right].\dfrac{x-1}{x^3}\)

\(P=\dfrac{x^2+1+2x}{x^4+2x^3+x^2}.\dfrac{x-1}{x^3}\)

\(P=\dfrac{x^2+2x+1}{x^2\left(x^2+2x+1\right)}.\dfrac{x-1}{x^3}\)

\(P=\dfrac{1}{x^2}.\dfrac{x-1}{x^3}\)

\(P=\dfrac{x-1}{x^5}\)

Answer 2

[DƯƠNG PHAN KHÁNH DƯƠNG]

Làm nốt đi cậu ! Bạn ko làm là tớ làm đó @@