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\(2^{x+2}-2^x=96\)
\(\Rightarrow2^x\cdot2^2-2^x=96\)
\(\Rightarrow2^x\left(2^2-1\right)=96\)
\(\Rightarrow2^x\left(4-1\right)=96\)
\(\Rightarrow2^x\cdot3=96\)
\(\Rightarrow2^x=96:3\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
\(5^x+5^{x+1}=750\)
\(\Rightarrow5^x+5^x\cdot5=750\)
\(\Rightarrow5^x\left(1+5\right)=750\)
\(\Rightarrow5^x\cdot6=750\)
\(\Rightarrow5^x=750:6\)
\(\Rightarrow5^x=125\)
\(\Rightarrow5^x=5^3\)
\(\Rightarrow x=3\)
\(2^{x+3}+2^x=144\)
\(\Rightarrow2^x\cdot2^3+2^x=144\)
\(\Rightarrow2^x\left(2^3+1\right)=144\)
\(\Rightarrow2^x\cdot9=144\)
\(\Rightarrow2^x=144:9\)
\(\Rightarrow2^x=16\)
\(\Rightarrow2^x=2^4\)
\(\Rightarrow x=4\)
{x2-[36(64-63)3-35]-15}3=1
{x2-[36.13-35]-15}3=1
{x2-[36.1-35]-15}3=1
{x2-[36-35]-15}3=1
{x2-1-15}3=1
{x2-1-15}3=13
=>x2-1-15=1
x2=1+1+15
x2=17
x2=căn của 7
=>x=căn 7
Vậy x=căn 7
tk nha
\(=>2\cdot4^x+64\cdot4^x=1056\)
\(=>4^x\cdot\left(2+64\right)=1056\)
\(=>4^x=1056:66=16\)
\(=>4^x=4^2\)
\(=>x=2\)
ti ck nha
2.22x + 43.4x = 1056
=> 2.4x + 43.4x = 1056
=> (2 + 64).4x = 1056
=> 66.4x = 1056
=> 4x = 1056 : 66
=> 4x = 16
=> 4x = 42
=> x = 2
7.4x - 1 + 4x + 1 = 23
=> 7.4x.1/4 + 4x.4 = 23
=> (7/4 + 4).4x = 23
=> 23/4.4x = 23
=> 4x = 23 : 23/4
=> 4x = 4
=> x = 1
3x + 2 - 5.3x = 36
=> 3x.9 - 5.3x = 36
=> 3x.(9 - 5) = 36
=> 3x.4 = 36
=> 3x = 36 : 4
=> 3x = 9 = 32
=> 3x = 2
a. \(4^{x+5}=32^{40}\)
\(\left(2^2\right)^{x+5}=\left(2^5\right)^{40}\)
\(2^{2x+10}=2^{200}\)
\(2x+10=200\)
2x = 190
x = 95.
b. \(3^{6-3x}=81^3\)
\(3^{6-3x}=\left(3^4\right)^3\)
6 - 3x = 12
3x = 6 - 12
3x = -6
x = -2
c. \(4^{x+3}-3.4^{x+7}=13.4^{11}\)
\(4^{x+3}.1-3.4^{x+3}.4^4=13.4^{11}\)
\(4^{x+3}\left(1-3.4^4\right)=13.4^{11}\)
Bài này sai đề rồi em.
d. \(5.3^{x+6}=2.3^5+3.3^5\)
\(5.3^{x+6}=3^5\left(2+3\right)\)
\(5.3^{x+6}=3^5.5\)
\(3^{x+6}=3^5\)
x + 6 = 5
x = 5 - 6
x = -1.
a) \(4^{x+5}=32^{40}\)
\(\Rightarrow\left(2^2\right)^{x+5}=\left(2^5\right)^{40}\)
\(\Rightarrow2^{2x+10}=2^{200}\)
\(\Rightarrow2x+10=200\)
\(\Rightarrow2x=200-10=190\)
\(\Rightarrow x=190:2=95\)
b) \(3^{6-3x}=81^3\)
\(\Rightarrow3^{6-3x}=\left(3^4\right)^3\)
\(\Rightarrow3^{6-3x}=3^{12}\)
\(\Rightarrow6-3x=12\)
\(\Rightarrow3x=6-12=-6\)
\(\Rightarrow x=\left(-6\right):3=-2\)
c) \(4^{x+3}-3.4^{x+7}=13.4^{11}\)
Sai đề nha
d) \(5.3^{x+6}=2.3^5+3.3^5\)
\(\Rightarrow5.3^{x+6}=\left(2+3\right).3^5\)
\(\Rightarrow5.3^{x+6}=5.3^5\)
\(\Rightarrow x+6=5\)
\(\Rightarrow x=5-6=-1\)
Chúc em học tốt nhé!
1 ) <=> 5.3x = 405
<=> 3x = 81 = 34
=> x = 4
2 ) <=> 2x ( 7.23 - 5.22 + 1 ) = 1184
<=> 2x ( 7.8 - 5.4 + 1 ) = 1184
<=> 2x ( 56 - 20 + 1 ) = 1184
<=> 2x . 37 = 1184
<=> 2x = 32 = 25
=> x = 5
1 ) <=> 5.3x = 405
<=> 3x = 81 = 34
=> x = 4
2 ) <=> 2x ( 7.23 - 5.22 + 1 ) = 1184
<=> 2x ( 7.8 - 5.4 + 1 ) = 1184
<=> 2x ( 56 - 20 + 1 ) = 1184
<=> 2x . 37 = 1184
<=> 2x = 32 = 25
=> x = 5
mk để mk đc trong 290đ đc ko!?