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12 tháng 12 2017

\(\dfrac{6^6+6^3.3^3+3^6}{-73}\)

\(=\dfrac{\left(2.3\right)^6+\left(2.3\right)^3.3^3+3^6}{-73}\)

\(=\dfrac{2^6.3^6+2^3.3^6+3^6}{-73}\)

\(=\dfrac{3^6\left(2^6+2^3+1\right)}{-73}\)

\(=\dfrac{3^6.73}{-73}=-1.3^6=-3^6\)

30 tháng 8 2017

\(B=\dfrac{6^6+6^3.3^3+3^6}{-73}\)

\(B=\dfrac{46656+5832+729}{-73}\)

\(B=\dfrac{52488+729}{-73}\)

\(B=\dfrac{53217}{-73}=-729\)

30 tháng 8 2017

\(\dfrac{6^6+6^3\cdot3^3+3^6}{-7^3}\)

\(=\dfrac{46656+46656\cdot27+729}{-343}\)

\(=\dfrac{46656+1259712+729}{-343}\)

\(=\dfrac{1306368+729}{-343}\)

\(=\dfrac{1307097}{-343}\)

11 tháng 12 2017

a)\(\dfrac{6^6+6^3.3^3+3^6}{-73}\)\(=\dfrac{2^6.3^6+2^3.3^3.3^3+3^6}{-73}=\dfrac{2^6.3^6+2^3.3^6+3^6.1}{-73}\)

\(=\dfrac{3^6.\left(2^6+2^3+1\right)}{-73}=\dfrac{3^6\left(64+8+1\right)}{-73}=^{ }\)\(\dfrac{3^6.73}{-73}=\dfrac{3^6}{-1}=-3^6\)

b)\(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}.\left(2^{20}+1\right)}{2^{30}.\left(2^{20}+1\right)}=\dfrac{2^{40}}{2^{30}}=2^{10}=1024\)

c)\(\dfrac{45^{10}.5^{20}}{75^{15}}=\dfrac{\left(3^2\right)^{10}.5^{10}.5^{20}}{\left(5^2\right)^{15}.3^{15}}=\dfrac{3^{20}.5^{30}}{5^{30}.3^{15}}=3^5=243\)

9 tháng 11 2017

\(\dfrac{6^6+6^3.3^3+3^6}{-73}\)

\(\dfrac{3^6.2^6+3^6.2^3+3^6.1}{-73}\)

\(\dfrac{3^6.\left(2^6+2^3+1\right)}{-73}\)

\(=\dfrac{3^6.73}{-73}=-729\)

23 tháng 5 2019

Ta có: \(\frac{6^6+6^3.3^3+3^6}{-73}=\frac{3^6\left(2^6+2^3+1\right)}{-73}=\frac{3^6.73}{-73}=-3^6=-729\)

9 tháng 12 2017

\(\dfrac{6^6+6^3.3^3+3^6}{-73}=\dfrac{3^6.2^6+3^3.2^3.3^3+3^6}{-73}=\dfrac{3^6.64+3^6.8+3^6}{-73}=\dfrac{3^6.\left(64+8+1\right)}{-73}=-3^6=-729\)

9 tháng 12 2017

Giải:

\(\dfrac{6^6+6^3.3^3+3^6}{-73}=\dfrac{2^6.3^6+2^3.3^3.3^3+3^6}{-73}\)

\(=\dfrac{2^6.3^6+2^3.3^6+3^6}{-73}=\dfrac{3^6\left(2^6+2^3+1\right)}{-73}\)

\(=\dfrac{3^6\left(64+8+1\right)}{-73}=\dfrac{3^6.73}{-73}=-3^6=-729.\)

Vậy.....

15 tháng 9 2017

\(\dfrac{6^6+6^3.3+6^3}{-73}=\dfrac{2^6.3^6+2^3.3^3.3+2^6.3^6}{-73}=\dfrac{2^6.3^6+2^3.3^4+2^6.3^6}{-73}=\dfrac{2^3.3^4.\left(2^{3^{ }}.3^2+1+2^{3^{ }}.3^{2^{ }}\right)}{-73}=\dfrac{93960}{-73}\)

9 tháng 12 2017

Vương Hạ Di chép sai đề => kq sai :w

\(=\dfrac{3^6\cdot2^6+3^3\cdot3^3\cdot2^3+3^6}{-73}=\dfrac{3^6\left(2^6+2^3+1\right)}{-73}=-3^6=-729\)

15 tháng 9 2017

\(\dfrac{6^6+6^3.3^3+3^6}{-73}=\dfrac{46656+\left(6.3\right)^3+729}{-73}=\dfrac{46656+18^3+729}{-73}=\dfrac{46656+5832+729}{-73}=\dfrac{53217}{-73}=-729\)