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25x2(y-1)-5x3(1-y)
=25x2(y-1)+5x3(y-1)
=5x2(y-1)(5+x)
xy+2x+5y+10
=(xy+2x)+(5y+10)
=x(y+2)+5(y+2)
=(y+2)(x+5)
1; \(25x^2\left(y-1\right)-5x^3\left(1-y\right)=25x^2\left(y-1\right)+5x^3\left(y-1\right)=5x^2\left(y-1\right)\left(5+x\right)\)
2; \(xy+2x+5y+10=x\left(y+2\right)+5\left(y+2\right)=\left(x+5\right)\left(y+2\right)\)
1, 25x^2 ( y - 1) - 5x^3 ( 1-y)
= 25x^2 ( y - 1) + 5x^3 ( y - 1)
= 5x^2 ( y - 1)( 1 + x)
2, xy + 2x + 5y + 10
= x( y + 2) + 5( y + 2)
= ( x + 5)( y+2)
\(1)6x^2+7x-3\\=6x^2+9x-2x-3\\=3x(2x+3)-(2x+3)\\=(2x+3)(3x-1)\\2)5x^2+14x-3\\=5x^2+15x-x-3\\=5x(x+3)-(x+3)\\=(x+3)(5x-1)\)
1) \(6x^2+7x-3=6x^2+9x-2x-3=3x\left(x+3\right)-\left(2x+3\right)=\left(2x+3\right).\left(3x-1\right)\)
2) \(5x^2+14x-3=5x^2+15x-x-3=5x\left(x+3\right)-\left(x+3\right)=\left(x+3\right).\left(5x-1\right)\)
\(1,\)
\(x^2+x-12\)
\(=x^2-3x+4x-12\)
\(=x\left(x-3\right)+4\left(x-3\right)\)
\(=\left(x+4\right)\left(x-3\right)\)
\(2,\)
\(x^2-9x+20\)
\(=x^2-4x-5x+20\)
\(=x\left(x-4\right)-5\left(x-4\right)\)
\(=\left(x-5\right)\left(x-4\right)\)
\(3,\)
\(x^2+x-20\)
\(=x^2-4x+5x-20\)
\(=x\left(x-4\right)+5\left(x-4\right)\)
\(=\left(x+5\right)\left(x-4\right)\)
b, ( x + 4) ^2 - 25 = ( x + 4)^2 - 5^2 = ( x + 4 - 5)( x + 4 + 5) = ( x - 1)( x+9)
a, \(\left(x+1\right)^2-25=\left(x+1-5\right)\left(x+1+5\right)=\left(x-4\right)\left(x+6\right)\)
b, \(\left(xy+4\right)^2-4\left(x+y\right)^2=\left(xy+4\right)^2-\left(2x+2y\right)^2=\left(xy+4-2x-2y\right)\left(xy+4+2x+2y\right)\)
c, xem lại đề nhé
\(\left(y-5\right).\left(y^2+5y+25\right)=y^3-5^3=y^3-125\)