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a) Phép tính =
\(2^2.3-\left(1+1\right):2\)
\(=4.3-2:2\)
\(=12-1=11\)
b) Phép tính =
\(\left\{47-\left[736:\left(5-3\right)^4\right]\right\}.2013\)
\(=\left\{47-\left[736:16\right]\right\}.2013\)
\(=\left(47-46\right).2013\)
\(=1.2013=2013\)
a) 22 . 31 - ( 12012 + 20120 ) . |-2|
= 4 . 3 - ( 1 + 1 ) . 2
= 12 - 2 . 2
= 10 . 2
= 20.
b) { 47 . [ 736 . ( 5 - 3 )4]} . 203
= { 47 . [ 736 . 24 ]} . 203
= { 47 . [ 736 . 16 ]} . 203
= { 47 . 11 776 } . 203
= 553 472 . 203
= 112 354 816
a,
=4.3 - (1+1).2
=12-2.2
=12-4=8
b {47 . [736-2^4]}.203
={47. [736-16]} . 203
={47 . 720} . 203
=33840. 203
=6869520
\(Q=\frac{2010+2011+2012}{2011+2012+2013}\)
\(Q=\frac{2010}{2011+2012+2013}+\frac{2011}{2011+2012+2013}+\frac{2012}{2011+2012+2013}\)
Ta có :
\(\hept{\begin{cases}\frac{2010}{2011}>\frac{2010}{2011+2012+2013}\\\frac{2011}{2012}>\frac{2011}{2011+2012+2013}\\\frac{2012}{2013}>\frac{2012}{2011+2012+2013}\end{cases}}\)
\(\Rightarrow P>Q\)
\(\dfrac{5.4^2+16}{2^3}=\dfrac{16\left(5+1\right)}{2^3}=2.6=12\)
\(\dfrac{5^{16}}{5^{14}}+2^2.2^3=5^2+2^5=25+32=57\)
\(\dfrac{7^{2012}}{7^{2010}}-6^2=7^2-6^2=49-36=13\)
\(2^2.3+\dfrac{250}{5^2}=12+10=22\)
\(2.9.50-2012^0=9.100-1=899\)
\(\dfrac{123}{3}-\dfrac{4^3}{2^4}=41-\dfrac{4^2.4}{2^4}41-4=37\)
f: =-46-64-91+220
=220-110-91
=110-91=19
g: =4-2:2=3
h: ={47-736:2^4}*2013
=2013(47-184)
=-137*2013=-275781