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11 tháng 10 2020

a) \(x^4-2x^2+1=\left(x^2-1\right)^2=\left(x-1\right)^2\left(x+1\right)^2\)

b) \(x^2-y^2-5x+5y=\left(x-y\right)\left(x+y\right)-5\left(x-y\right)=\left(x-y\right)\left(x+y-5\right)\)

c) \(2x^3-x^2-8x+4\)

\(=x^2\left(2x-1\right)-4\left(2x-1\right)\)

\(=\left(x-1\right)\left(x+1\right)\left(2x-1\right)\)

d) \(x\left(x-y\right)^2+y\left(x-y\right)^2-xy+x^2\)

\(=\left(x+y\right)\left(x-y\right)^2+x\left(x-y\right)\)

\(=\left(x-y\right)\left(x^2-y^2+x\right)\)

e) \(2x^2-5x+2\)

\(=\left(2x^2-x\right)-\left(4x-2\right)\)

\(=x\left(2x-1\right)-2\left(2x-1\right)\)

\(=\left(x-2\right)\left(2x-1\right)\)

12 tháng 7 2019

a,\(xy+3x-7y-21\)

\(=x\left(y+3\right)-7\left(y+3\right)\)

\(=\left(y+3\right)\left(x-7\right)\)

12 tháng 7 2019

\(b,2xy-15-6x+5y\)

\(=\left(2xy-6x\right)+\left(-15+5y\right)\)

\(=2x\left(y-3\right)-5\left(3-y\right)\)

\(=2x\left(y-3\right)+5\left(y-3\right)\)

\(=\left(y-3\right)\left(2x+5\right)\)

30 tháng 10 2016

\(B=7x^2-7xy-5x+5y\)

\(=7x\left(x-y\right)-5\left(x-y\right)\)

\(=\left(x-y\right)\left(7x-5\right)\)

\(E=x^2+7x+12\)

\(=x^2+3x+4x+12\)

\(=x\left(x+3\right)+4\left(x+3\right)\)

\(=\left(x+3\right)\left(x+4\right)\)

\(F=x^2-9x+18\)

\(=x^2-3x-6x+18\)

\(=x\left(x-3\right)-6\left(x-3\right)\)

\(=\left(x-3\right)\left(x-6\right)\)

\(H=8x^2-2x-1\)

\(=8x^2-4x+2x-1\)

\(=4x\left(2x-1\right)+\left(2x-1\right)\)

\(=\left(2x-1\right)\left(4x+1\right)\)

 

13 tháng 11 2017

3)

\(A=\dfrac{5}{x^2-2x+5}\)

ta có x2-2x+5

=x2-2x+1+4

=(x2-2x+1)+4

=(x-1)2+4

=> A=\(\dfrac{5}{\left(x-1\right)^2+4}\)

do \(\left(x-1\right)^2\ge0\forall x\)

=> \(\left(x-1\right)^2+4\ge4\)

=> \(\dfrac{5}{\left(x-1\right)^2+4}\le\dfrac{5}{4}\)

=> A\(\le\dfrac{5}{4}\)

GTLN của A =\(\dfrac{5}{4}\)

khi x-1=0

=> x=1

vậy GTLN của A=\(\dfrac{5}{4}\) khi x=1

23 tháng 11 2017

a) \(x^2-y^2-5x-5y\)

\(=\left(x^2-y^2\right)-\left(5x+5y\right)\)

\(=\left(x-y\right)\left(x+y\right)-5\left(x+y\right)\)

\(=\left(x+y\right)\left(x-y-5\right)\)

b) \(5x^3-5x^2y-10x^2+10xy\)

\(=\left(5x^3-5x^2y\right)-\left(10x^2-10xy\right)\)

\(=5x^2\left(x-y\right)-10x\left(x-y\right)\)

\(=\left(x-y\right)\left(5x^2-10x\right)\)

\(=5x\left(x-y\right)\left(x-2\right)\)

c) \(x^3-2x^2-x+2\)

\(=\left(x^3-2x^2\right)-\left(x-2\right)\)

\(=x^2\left(x-2\right)-\left(x-2\right)\)

\(=\left(x-2\right)\left(x^2-1\right)\)

\(=\left(x-2\right)\left(x-1\right)\left(x+1\right)\)

d) \(-y^2+2xy-x^2+3x-3y\)

\(=-\left(y^2-2xy+x^2\right)+\left(3x-3y\right)\)

\(=-\left(y-x\right)^2+3\left(x-y\right)\)

\(=-\left(x-y\right)^2+3\left(x-y\right)\)

\(=\left(x-y\right)\left[-\left(x-y\right)+3\right]\)

\(=\left(x-y\right)\left(-x+y+3\right)\)

g) \(4x^2-8x+3\)

\(=4x^2-6x-2x+3\)

\(=\left(4x^2-6x\right)-\left(2x-3\right)\)

\(=2x\left(2x-3\right)-\left(2x-3\right)\)

\(=\left(2x-3\right)\left(2x-1\right)\)

h) \(2x^2-5x-7\)

\(=2x^2+2x-7x-7\)

\(=\left(2x^2+2x\right)-\left(7x+7\right)\)

\(=2x\left(x+1\right)-7\left(x+1\right)\)

\(=\left(x+1\right)\left(2x-7\right)\)

k) \(x^4+4\)

\(=x^4+4x^2+4-4x^2\)

\(=\left[\left(x^2\right)^2+2.x^2.2+2^2\right]-4x^2\)

\(=\left(x^2+2\right)^2-\left(2x\right)^2\)

\(=\left(x^2+2-2x\right)\left(x^2+2+2x\right)\)