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\(2x^2+3x-27=2x^2-6x+9x-27=2x\left(x-3\right)+9\left(x-3\right)=\left(2x+9\right)\left(x-3\right)\)
\(x^3-7x+6=x^3-x-6x+6=x\left(x^2-1\right)-6\left(x-1\right)=x\left(x-1\right)\left(x+1\right)-6\left(x-1\right)=\left(x-1\right)\left(x^2+x-6\right)\)
\(x^3+5x^2+8x+4=x^3+x^2+4x^2+8x+4=x^2\left(x+1\right)+4\left(x^2+2x+1\right)=x^2\left(x+1\right)+4\left(x+1\right)^2\)
\(=\left(x+1\right)\left(x^2+4x+4\right)=\left(x+1\right)\left(x+2\right)^2\)
\(27x^3-27x^2+18x-4=27x^3-9x^2-18x^2+6x+12x-4\)
\(=9x^2\left(3x-1\right)-6x\left(3x-1\right)+4\left(3x-1\right)=\left(3x-1\right)\left(9x^2-6x+4\right)\)
b)3x^2-18x+27=3x^2-9x-9x+27=3x*(x-3)-9*(x-3)=(x-3)*(3x-9)=(x-3)*3*(x-3)=3*(x-3)^2
c)x^3-4x^2-12x+27=(x+3)*(x^2-3x+9-4)=(x+3)*(x^2-3x+5)
d)27x^3-1/27=(3x-1/3)*(9x^2-x+1/9) (hang dt)
con a) voi e) mk chiu
\(x^8+x+1\)
\(=x^8+x^7+x^6-x^7-x^6-x^5+x^5+x^4+x^3-x^4-x^3-x^2+x^2+x+1\)
\(=x^6\left(x^2+x+1\right)-x^5\left(x^2+x+1\right)+x^3\left(x^2+x+1\right)-x^2\left(x^2+x+1\right)+x^2+x+1\)
\(=\left(x^2+x+1\right)\left(x^6-x^5+x^3-x^2+1\right)\)
a)\(2x^3-x^2+5x+3=2x^3-2x^2+x^2+6x-x+3\)
\(=\left(2x^3-2x^2+6x\right)+\left(x^2-x+3\right)\)
\(=2x\left(x^2-x+3\right)+\left(x^2-x+3\right)\)
\(=\left(x^2-x+3\right)\left(2x+1\right)\)
b)\(27x^3-27x^2+18x-4=27x^3-18x^2-9x^2+12x+6x-4\)
\(=3x\left(9x^2-6x+4\right)-\left(9x^2-6x+4\right)\)
\(=\left(9x^2-6x+4\right)\left(3x-1\right)\)
c)\(4x^4-32x^2+1=4x^4+4x^2-36x^2+1\)
\(=\left(4x^4+4x^2+1\right)-36x^2\)
\(=\left(2x^2+1\right)^2-\left(6x\right)^2\)
\(=\left(2x^2+1+6x\right)\left(2x^2+1-6x\right)\)
Mình viết xuôi theo dạng ax2 + bx + c nhé ;-; cho dễ làm
a) 2x2 + 7x + 3 = 2x2 + x + 6x + 3 = x( 2x + 1 ) + 3( 2x + 1 ) = ( 2x + 1 )( x + 3 )
b) 3x2 - 8x + 4 = 3x2 - 6x - 2x + 4 = 3x( x - 2 ) - 2( x - 2 ) = ( x - 2 )( 3x - 2 )
c) 3x2 - 7x + 2 = 3x2 - 6x - x + 2 = 3x( x - 2 ) - ( x - 2 ) = ( x - 2 )( 3x - 1 )
d) -6x2 + 7x - 2 = -6x2 + 3x + 4x - 2 = -3x( 2x - 1 ) + 2( 2x - 1 ) = ( 2x - 1 )( 2 - 3x )
e) -3x2 + 7x - 2 = -3x2 + 6x + x - 2 = -3x( x - 2 ) + ( x - 2 ) = ( x - 2 )( 1 - 3x )
f) 2x2 - 5x + 2 = 2x2 - 4x - x + 2 = 2x( x - 2 ) - ( x - 2 ) = ( x - 2 )( 2x - 1 )
g) 3x2 - 8x + 4 = 3x2 - 6x - 2x + 4 = 3x( x - 2 ) - 2( x - 2 ) = ( x - 2 )( 3x - 2 )
h) 6x2 - 11x + 3 = 6x2 - 2x - 9x + 3 = 2x( 3x - 1 ) - 3( 3x - 1 ) = ( 3x - 1 )( 2x - 3 )
i) 2x2 + 3x - 27 = 2x2 - 6x + 9x - 27 = 2x( x - 3 ) + 9( x - 3 ) = ( x - 3 )( 2x + 9 )
j) 4x2 - 5x + 1 = 4x2 - 4x - x + 1 = 4x( x - 1 ) - ( x - 1 ) = ( x - 1 )( 4x - 1 )
a) \(x^3+3x^2y-9xy^2+5y^3\)
\(=x^3-3x^2y+3xy^2-y^3+6x^2y-12xy^2+6y^3\)
\(=\left(x-y\right)^3+6y\left(x^2-2xy+y^2\right)\)
\(=\left(x-y\right)^3+6y\left(x-y\right)^2\)
\(=\left(x-y\right)^2\left(x+5y\right)\)
b) \(27x^3-27x^2+18x-4\)
\(=27x^3-9x^2-18x^2+6x+12x-4\)
\(=9x^2\left(3x-1\right)-6x\left(3x-1\right)+4\left(3x-1\right)\)
\(=\left(3x-1\right)\left(9x^2-6x+4\right)\)
c) \(2x^3-x^2+5x+3\)
\(=2x^3+x^2-2x^2-x+6x+3\)
\(=x^2\left(2x+1\right)-x\left(2x+1\right)+3\left(2x+1\right)\)
\(=\left(2x+1\right)\left(x^2-x+3\right)\)
a. x3+5x2+3x-9
= x3-x2+6x2-6x+9x-9
= x2(x-1)+6x(x-1)+9(x-1)
= (x2+6x+9)(x-1)
= (x+3)2(x-1)
b. x3+9x2+11x-21
= x3-x2+10x2-10x+21x-21
= x2(x-1)+10x(x-1)+21(x-1)
= (x2+10x+21)(x-1)
= (x+7)(x+3)(x-1)
c. x3-7x+6
= x3-x2+x2-x-6x+6
= x2(x-1)+x(x-1)-6(x-1)
= (x2+x-6)(x-1)
= (x+3)(x-2)(x-1)
d. x3-5x2+8x-4
= x3-x2-4x2+4x+4x-4
= x2(x-1)-4x(x-1)+4(x-1)
= (x2-4x+4)(x-1)
= (x-2)2(x-1)
e. x3-3x+2
= x3+2x2-2x2-4x+x+2
= x2(x+2)-2x(x+2)+(x+2)
= (x2-2x+1)(x+2)
= (x-1)2(x+2)
f. x3+8x2+17x+10
= x3+5x2+3x2+15x+2x+10
= x2(x+5)+3x(x+5)+2(x+5)
= (x2+3x+2)(x+5)
= (x+1)(x+2)(x+5)
g. x3+3x2+6x+4
= x3+x2+2x2+2x+4x+4
= x2(x+1)+2x(x+1)+4(x+1)
= (x2+2x+4)(x+1)
h. x3-2x-4
= x3-2x2+2x2-4x+2x-4
= x2(x-2)+2x(x-2)+2(x-2)
= (x2+2x+2)(x-2)
k. x3+x2+4
= x3+2x2-x2-2x+2x+4
= x2(x+2)-x(x+2)+2(x+2)
= (x2-x+2)(x+2)
l. x3-12x+7x-2
= x3+2x2-2x2-4x-x-2
= x2(x+2)-2x(x+2)-(x+2)
= (x2-2x-1)(x+2)
\(a.x^3-6x=x^3-4^3=\left(x-4\right)\left(x^2+4x+16\right)\)
\(b.x^4+6x^3+11x^2+6x+1=x^4+6x^3+9x^2+2x^2+6x+1\)
\(=\left(x^2+3x+1\right)^2\)
\(c.x^2+3x+2=x^2+x+2x+2=x\left(x+1\right)+2\left(x+1\right)=\left(x+1\right)\left(x+2\right)\)
\(d.x\left(x+1\right)\left(x+2\right)\left(x+3\right)+1\)
\(=x\left(x+3\right)\left(x+1\right)\left(x+2\right)+1=\left(x^2+3x\right)\left(x^2+3x+2\right)+1\)
Đặt \(x^2+3x=y\Rightarrow y\left(y+2\right)+1=y^2+2y+1=\left(y+1\right)^2\)
Thay \(y=x^2+3x\) ta được: \(\left(y+1\right)^2=\left(x^2+3x+1\right)^2\)
\(e.x^3+9x^2+27x+27=\left(x+3\right)^3\)
\(f.\left(x+1\right)\left(x+7\right)\left(x^2+8x+15\right)+15=\left(x^2+8x+7\right)\left(x^2+8x+15\right)+15\)
Đặt \(a=x^2+8x+11\Rightarrow\left(a-4\right)\left(a+4\right)+15=a^2-16+15=a^2-1=\left(a+1\right)\left(a-1\right)\)
Thay \(a=x^2+8x+11\) ta được: \(\left(a+1\right)\left(a-1\right)=\left(x^2+8x+12\right)\left(x^2+8x+10\right)\)
e, \(x^3+5x^2+8x+4=x^3+x^2+4x^2+4x+4x+4\)
\(=x^2\left(x+1\right)+4x\left(x+1\right)+4\left(x+1\right)\)
\(=\left(x+1\right)\left(x^2+4x+4\right)=\left(x+1\right)\left(x+2\right)^2\)
d, \(27x^3-27x^2+18x-4=27x^3-9x^2-18x^2+6x+12x-4\)
\(=9x^2\left(3x-1\right)-6x\left(3x-1\right)+4\left(3x-1\right)\)
\(=\left(3x-1\right)\left(9x^2-6x+4\right)\)