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Bài 1:
a: \(\left(2x-1\right)^4=16\)
=>2x-1=2 hoặc 2x-1=-2
=>2x=3 hoặc 2x=-1
=>x=3/2 hoặc x=-1/2
b: \(\left(2x-y+7\right)^{2012}+\left|x-3\right|^{2013}< =0\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x-y+7=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=3\\y=2x+7=y=2\cdot3+7=13\end{matrix}\right.\)
c: \(10800=2^4\cdot3^3\cdot5^2\)
mà \(2^{x+2}\cdot3^{x+1}\cdot5^x=10800\)
nên \(\left\{{}\begin{matrix}x+2=4\\x+1=3\\x=2\end{matrix}\right.\Leftrightarrow x=2\)
a) \(\left(3,5\right)^3=42,875\)
b) \(\left(-\dfrac{4}{11}\right)^2=\dfrac{16}{121}\)
c) \(\left(0,5\right)^4\cdot6^4=\left(0,5\cdot6\right)^4=3^4=81\)
d) \(\left(\dfrac{-1}{3}\right)^5:\left(\dfrac{1}{6}\right)^5=\left(\dfrac{-1}{3}:\dfrac{1}{6}\right)^5=\left(-2\right)^5=-32\)
\(a)\left(3,5\right)^3=42,875\)
\(b)\left(-\dfrac{4}{11}\right)^2=\dfrac{16}{121}\)
\(c)\left(0,5\right)^4.6^4=\left(0,5.6\right)^4=3^4=81\)
\(d)\left(-\dfrac{1}{3}\right)^5:\left(\dfrac{1}{6}\right)^5=\left(\dfrac{-1}{3}:\dfrac{1}{6}\right)^5=\left(-2\right)^5=-32\)
Chúc bn học tốt !
a: (x-3)2=49
=>x-3=7 hoặc x-3=-7
=>x=10 hoặc x=-4
b: \(\left(x^4\right)^2=\dfrac{x^{12}}{x^5}\)
\(\Leftrightarrow x^8-x^7=0\)
\(\Leftrightarrow x^7\left(x-1\right)=0\)
=>x=0 hoặc x=1
c: \(\Leftrightarrow x^{10}-25x^8=0\)
\(\Leftrightarrow x^8\left(x^2-25\right)=0\)
\(\Leftrightarrow x^8\left(x-5\right)\left(x+5\right)=0\)
hay \(x\in\left\{0;5;-5\right\}\)
Bài 1:
a) Đề ko rõ, coi lại
b) \(75^{20}=45^{10}.5^{30}\)
\(\Leftrightarrow\left(75^2\right)^{10}=45^{10}.\left(5^3\right)^{10}\)
\(\Leftrightarrow5625^{10}=45^{10}.125^{10}\)
\(\Leftrightarrow5625^{10}=\left(45.125\right)^{10}\)
\(\Leftrightarrow5625^{10}=5625^{10}\)
\(\Rightarrow75^{20}=45^{10}.5^{30}\left(đpcm\right)\)
Bài 2:
a) \(\frac{x}{-4}=\frac{-3}{5}\)
\(\Rightarrow x.5=-4.\left(-3\right)\)
\(\Rightarrow x.5=12\)
\(\Rightarrow x=\frac{12}{5}=2,4\)
b) c) d) Làm tương tự câu a. Bn tự lm cho nhớ
e) \(30.5x=4.12\)
\(\Rightarrow150x=48\)
\(\Rightarrow x=\frac{48}{150}=0,32\)
f) g) Làm tương tự câu e. Bn tự lm cho nhớ
\(5^{x+4}-3.5^{x+3}=2.5^{11}\)
\(\Leftrightarrow5^{x+3+1}-3.5^{x+3}=2.5^{11}\)
\(\Leftrightarrow5^{x+3}.5-3.5^{x+3}=2.5^{11}\)
\(\Leftrightarrow5^{x+3}.\left(5-3\right)=5^{11}.2\)
\(\Leftrightarrow5^{x+3}.2=5^{11}.2\)
\(\Leftrightarrow5^{x+3}=5^{11}\)
\(\Leftrightarrow x+3=11\)
\(\Leftrightarrow x=8\)
Vậy \(x=8\)