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2, tính vế trc
\(\frac{1}{2}\left(\frac{2}{3.5}+\frac{2}{5.7}+......+\frac{2}{19.21}\right)=\frac{1}{2}\left(\frac{1}{3}-\frac{1}{5}+.....+\frac{1}{19}-\frac{1}{21}\right)=\frac{1}{2}\left(\frac{1}{3}-\frac{1}{21}\right)=\frac{1}{2}.\frac{2}{7}=\frac{1}{7}\)
=> 1/7 . x = 9/7
x = 9/7 . 7
x = 9
5) 327 - 48 - 152 + 173 =(327+173)-(48+152)=500-200=300
6) A = \(\frac{154+919+146+781}{823-217+533-139}=\frac{\left(154+146\right)+\left(919+781\right)}{1000}\)
=\(\frac{300+1700}{1000}=\frac{2000}{1000}=2\)
7) ( 1354 - 356 : 6 ) + 13,2=(1354\(-\frac{178}{3}\))+13,2=\(\frac{3884}{3}+13,2=\frac{19618}{15}\)
8) 784 . 0,5 : 0,28 - 196 : 28 + 2003=392:0,28-7+2003
=1400-7+2003=3396
\(\frac{768}{697}\); \(\frac{588}{533}\); \(\frac{245}{221}\); \(\frac{513}{255}\)
~~ tk nha, đg âm ~~
~~~~~~~~~Xiumin~~~~~~~~
~~ Mơn ~~ ^^
Tk mình đi mọi người mình bị âm nè!
Ai tk mình mình tk lại cho
1, A=\(\left(1+1+1+1\right)\)-\(\left(\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}\right)\)
=4-\(\left(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}\right)\)
= 4-\(\left(\frac{1}{1}-\frac{1}{3}+...+\frac{1}{7}-\frac{1}{9}\right)\)
=4-\(\left(1-\frac{1}{9}\right)\)
= 4-\(\frac{8}{9}\)
= \(\frac{7}{9}\)
\(A=\frac{3}{3}.\left(\frac{1}{2.5}+\frac{1}{5.8}+\frac{1}{8.11}+\frac{1}{11.14}+\frac{1}{14.17}+\frac{1}{17.20}\right)\)
\(A=\frac{1}{3}.\left(\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+\frac{3}{11.14}+\frac{3}{14.17}+\frac{3}{17.20}\right)\)
\(A=\frac{1}{3}.\left(\frac{1}{2}-\frac{1}{20}\right)\)
\(A=\frac{1}{3}.\frac{9}{20}\)
\(A=\frac{3}{20}\)
\(A=\frac{1}{2\times5}+\frac{1}{5\times8}+...+\frac{1}{17\times20}\)
\(A\times3=\frac{3}{2\times5}+\frac{3}{5\times8}+...+\frac{3}{17\times20}\)
\(A\times3=\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+...+\frac{1}{17}-\frac{1}{20}\)
\(A\times3=\frac{1}{2}-\frac{1}{20}\)
\(A\times3=\frac{9}{20}\)
\(A=\frac{3}{20}\)
bằng hai đó bn k nha^_^