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\(\frac{22}{21}\): ( \(\frac{63}{4}\)\(-\frac{61}{4}\)) \(+\) \(\frac{25}{12}\): ( \(\frac{31}{4}\)\(-\)\(\frac{29}{4}\))
= \(\frac{22}{21}\): \(\frac{1}{2}\)+ \(\frac{25}{12}\): \(\frac{1}{2}\)
= ( \(\frac{22}{21}\)+ \(\frac{25}{12}\) ) : \(\frac{1}{2}\)
= \(\frac{263}{84}\) : \(\frac{1}{2}\)
=\(\frac{263}{42}\)
\(1\frac{1}{21}:\left(15,75-15\frac{1}{4}\right)+2\frac{1}{12}:\left(7\frac{3}{4}-7,25\right)\)
=\(\frac{22}{21}:\left(\frac{63}{4}-\frac{61}{4}\right)+\frac{25}{12}:\left(\frac{31}{4}-\frac{29}{4}\right)\)
=\(\frac{22}{21}:\frac{1}{2}+\frac{25}{12}:\frac{1}{2}=\frac{22x2}{21}+\frac{25x2}{12}\)
=\(\frac{44}{21}+\frac{25}{6}=\frac{88+175}{42}=\frac{263}{42}\)
Câu b:
\(\frac{21}{8}:\frac{5}{6}+\frac{1}{2}:\frac{5}{6}\)
= \(\frac{63}{20}+\frac{3}{5}\)
= \(\frac{15}{4}\)
\(\left(\frac{21}{8}+\frac{1}{2}\right):\frac{5}{6}\)
\(\frac{25}{8}:\frac{5}{6}\)
\(\frac{25}{8}.\frac{6}{5}\)
\(\frac{30}{8}\)
\(\frac{18}{11}+\left(\frac{7}{4}-\frac{3}{5}\right):\frac{1}{2}\)
\(\frac{18}{11}+\frac{23}{20}:\frac{1}{2}\)
\(\frac{18}{11}+\frac{23}{20}\times\frac{2}{1}\)
\(\frac{18}{11}+\frac{23}{10}\)
\(\frac{433}{110}\)
a= (\(\frac{2}{5}\)+\(\frac{2}{9}\)+\(\frac{2}{11}\)\(\times\)\(\frac{5}{7}\)\(+\frac{7}{9}\)\(+\frac{7}{11}\)\()\)
\(\frac{11}{9}+\frac{35}{18}\)
\(=\frac{19}{6}\)
\(\frac{22}{21}:\frac{1}{2}+\frac{25}{12}:\frac{1}{2}\)
\(\frac{44}{21}+\frac{25}{6}\)
\(\frac{263}{42}\)
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