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\(\dfrac{2}{1^2}.\dfrac{6}{2^2}.\dfrac{12}{3^2}.\dfrac{20}{4^2}.....\dfrac{110}{10^2}.x=-20\)
\(\dfrac{1.2}{1^2}.\dfrac{2.3}{2^2}.\dfrac{3.4}{3^2}.\dfrac{4.5}{4^2}.....\dfrac{10.11}{10^2}.x=-20\)
\(\dfrac{1.2.2.3.3.4.4.5.5.....10.10.11}{1.1.2.2.3.3.4.4.5.5.....10.10}.x=-20\)
\(11.x=-20\)
\(x=-20:11=-\dfrac{20}{11}\)
\(\dfrac{2}{1^2}\cdot\dfrac{6}{2^2}\cdot\dfrac{12}{3^2}\cdot\dfrac{20}{4^2}\cdot...\cdot\dfrac{110}{10^2}\cdot x=-20\)
\(\Leftrightarrow\dfrac{1\cdot2}{1\cdot1}\cdot\dfrac{2\cdot3}{2\cdot2}\cdot\dfrac{3\cdot4}{3\cdot3}\cdot\dfrac{4\cdot5}{4\cdot4}\cdot...\cdot\dfrac{10\cdot11}{10\cdot10}\cdot x=-20\)
\(\Leftrightarrow\dfrac{1\cdot2\cdot2\cdot3\cdot3\cdot4\cdot4\cdot5\cdot...\cdot10\cdot11}{1\cdot1\cdot2\cdot2\cdot3\cdot3\cdot4\cdot4\cdot...\cdot10\cdot10}\cdot x=-20\)
\(\Rightarrow11\cdot x=-20\)
\(\Rightarrow x=\dfrac{-20}{11}\)
Vậy \(x=\dfrac{-20}{11}\).
\(\frac{2}{1^2}.\frac{6}{2^2}.\frac{12}{3^2}.\frac{20}{4^2}...\frac{110}{10^2}.x=-20\)
\(\Leftrightarrow\frac{1.2}{1^2}.\frac{2.3}{2^2}.\frac{3.4}{3^2}.\frac{4.5}{4^2}...\frac{10.11}{10^2}.x=-20\)
\(\Leftrightarrow\frac{2}{1}.\frac{3}{2}.\frac{4}{3}.\frac{5}{4}...\frac{11}{10}.x=-20\)
\(\Leftrightarrow11.x=-20\)
\(\Leftrightarrow x=\frac{-20}{11}\)
2)n=20
3)26.33=(22)3.33=43.33=(4.3)3=123=1728
4)Ta có:AM=AB+BM
=>AM=4cm+6cm
=>AM=10cm
=3^2.5+[110+17^2]
=3^2.5+[110+289]
=3^2.5+399
=9.5+399
=45+399=444
a) 45
b) 11099
a) 45
b) 11199