Question

[트란 투안 듀옹]

a)1/1*3+1/3*5+......+1/x*(x+2)

b)x=1*2+2*3+3*4+......+89*90

ai trả lời mình tk cho

Answer 1

[☆MĭηɦღAηɦ❄]

a, 

\(=\frac{1}{2}\left(\frac{2}{1.3}+\frac{2}{3.5}+...+\frac{2}{x.\left(x+2\right)}\right)\)

\(=\frac{1}{2}\left(\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{x}-\frac{1}{x+2}\right)\)

\(=\frac{1}{2}\left(1-\frac{1}{x+2}\right)\)

\(=\frac{1}{2}\times\frac{x+1}{x+2}\)

\(=\frac{2x+2}{x+2}\)

Hơ hơ =v

Làm đại phần a đúng sai mặc kệ ~~

Answer 2

[Nguyễn Phương Uyên]

a,

\(\frac{1}{1\cdot3}+\frac{1}{3\cdot5}+\frac{1}{5\cdot7}+...+\frac{1}{x\left(x+2\right)}\)

\(=\frac{1}{2}\left(\frac{2}{1\cdot3}+\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+...+\frac{2}{x\left(x+2\right)}\right)\)

\(=\frac{1}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{x}-\frac{1}{x+2}\right)\)

\(=\frac{1}{2}\left(1-\frac{1}{x+2}\right)\)

\(=\frac{1}{2}\cdot\frac{x+1}{x+2}\)

\(=\frac{2x+2}{x+2}\)

b,

x = 1.2 + 2.3 + 3.4 + ....+ 89.90

3x = 1.2.3 + 2.3.3 + 3.4.3 + .... + 89.90

3x = 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 89.90.(91 - 88)

3x = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ... + 89.90.91 - 88.89.90

3x = 89.90.91

x = \(\frac{89\cdot90\cdot91}{3}=242970\)