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a: 2x^2y-50xy=2xy(x-25)
b: 5x^2-10x=5x(x-2)
c: 5x^3-5x=5x(x^2-1)=5x(x-1)(x+1)
d: \(x^2-xy+x=x\left(x-y+1\right)\)
e: x(x-y)-2(y-x)
=x(x-y)+2(x-y)
=(x-y)(x+2)
f: 4x^2-4xy-8y^2
=4(x^2-xy-2y^2)
=4(x^2-2xy+xy-2y^2)
=4[x(x-2y)+y(x-2y)]
=4(x-2y)(x+y)
f1: x^2ỹ-y^2+y
=(x-y)(x+y)+(x+y)
=(x+y)(x-y+1)
mk ghi đáp án, ko phân tích đc thì IB mk
a) \(x^2+6xy+9y^2=\left(x+3y\right)^2\)
b) \(4a^4-4a^2b^2+b^4=\left(2a^2-b^2\right)^2\)
c) \(x^6+y^2-2x^3y=\left(x^3-y\right)^2\)
d) \(\left(x+y\right)^3-\left(x-y\right)^3=2y\left(3x^2+y^2\right)\)
e) \(25x^4-10x^2y^2+y^4=\left(5x^2-y^2\right)^2\)
f) \(-a^2-2a-1=-\left(a+1\right)^2\)
g) \(27b^3-8a^3=\left(3b-2a\right)\left(9b^2+6ab+4a^2\right)\)
h) \(x^3+9x^2y+27xy^2+27y^3=\left(x+3y\right)^3\)
i) \(16x^2-9\left(x+y\right)^2=\left(x-3y\right)\left(7x+3y\right)\)
Đề câu g có vấn đề aa :>>>
Câu còn lại tương tự như trên mà
a) Ta có: \(\left(3-xy^2\right)^2-\left(2+xy^2\right)^2\)
\(=\left[\left(3-xy^2\right)-\left(2+xy^2\right)\right]\cdot\left[\left(3-xy^2\right)+\left(2+xy^2\right)\right]\)
\(=\left(3-xy^2-2-xy^2\right)\cdot\left(3-xy^2+2+xy^2\right)\)
\(=5\cdot\left(1-2xy^2\right)\)
\(=5-10xy^2\)
b) Ta có: \(9x^2-\left(3x-4\right)^2\)
\(=\left[3x-\left(3x-4\right)\right]\left[3x+\left(3x-4\right)\right]\)
\(=\left(3x-3x+4\right)\cdot\left(3x+3x-4\right)\)
\(=4\cdot\left(6x-4\right)\)
\(=24x-16\)
c) Ta có: \(\left(a-b^2\right)\left(a+b^2\right)\)
\(=a^2-b^4\)
d) Ta có: \(\left(a^2+2a+3\right)\left(a^2+2a-3\right)\)
\(=\left(a^2+2a\right)^2-9\)
\(=a^4+4a^3+4a^2-9\)
e) Ta có: \(\left(x-y+6\right)\left(x+y-6\right)\)
\(=x^2+xy-6x-yx-y^2+6y+6x+6y-36\)
\(=x^2-y^2+12y-36\)
f) Ta có: \(\left(y+2z-3\right)\left(y-2z-3\right)\)
\(=\left(y-3\right)^2-\left(2z\right)^2\)
\(=y^2-6y+9-4z^2\)
g) Ta có: \(\left(2y-5\right)\left(4y^2+10y+25\right)\)
\(=\left(2y\right)^3-5^3\)
\(=8y^3-125\)
h) Ta có: \(\left(3y+4\right)\left(9y^2-12y+16\right)\)
\(=\left(3y\right)^3+4^3\)
\(=27y^3+64\)
i) Ta có: \(\left(x-3\right)^3+\left(2-x\right)^3\)
\(=\left(x-3\right)^3-\left(x-2\right)^3\)
\(=x^3-9x^2+27x-27-\left(x^3-6x^2+12x-8\right)\)
\(=x^3-9x^2+27x-27-x^3+6x^2-12x+8\)
\(=-3x^2+15x-19\)
j) Ta có: \(\left(x+y\right)^3-\left(x-y\right)^3\)
\(=\left[\left(x+y\right)-\left(x-y\right)\right]\cdot\left[\left(x+y\right)^2+\left(x+y\right)\left(x-y\right)+\left(x-y\right)^2\right]\)
\(=\left(x+y-x+y\right)\left(x^2+2xy+y^2+x^2-y^2+x^2-2xy+y^2\right)\)
\(=2y\cdot\left(3x^2+y^2\right)\)
\(=6x^2y+2y^3\)
a)x^2-(a+b)x+ab
= x^2 - ax - bx + ab
= (x^2 - ax) - (bx - ab)
= x(x-a) - b(x-a)
= (x-b)(x-a)
b)7x^3-3xyz-21x^2+9z
=
c)4x+4y-x^2(x+y)
= 4(x + y) - x^2(x+y)
= (4-x^2) (x+y)
= (2-x)(2+x)(x+y)
d) y^2+y-x^2+x
= (y^2 - x^2) + (x+y)
= (y-x)(y+x)+ (x+y)
= (y-x+1) (x+y)
e)4x^2-2x-y^2-y
= [(2x)^2 - y^2] - (2x +y)
= (2x-y)(2x+y) - (2x+y)
= (2x -y -1)(2x+y)
f)9x^2-25y^2-6x+10y
=
Một năm trôi qua ~ . Giờ làm tiếp câu 1 :v
Câu a : \(x\left(x-y\right)+y\left(x-y\right)=x^2-xy+xy-y^2=x^2-y^2\)
Câu b : \(\left(x^2-xy+y^2\right)\left(x+y\right)-\left(x-y\right)\left(x^2+xy+y^2\right)\)
\(=\left(x^3+y^3\right)-\left(x^3-y^3\right)=x^3+y^3-x^3+y^3=2y^3\)
Câu c : \(7x\left(4y-x\right)+4y\left(y-7x\right)-\left(4y^2-7x\right)\)
\(=28xy-7x^2+4y^2-28xy-4y^2+7x^2=0\)
Câu d : \(\left(2x+y\right)\left(2z+y\right)+\left(x-y\right)\left(y-z\right)\)
\(=4xz+2xy+2yz+y^2+xy-xz-y^2+yz\)
\(3xy+3yz+3xz=3\left(xy+yz+xz\right)\)
Lười làm câu 1 :
Câu 2 :
\(3x\left(12x-4\right)-9x\left(4x-3\right)=30\)
\(\Leftrightarrow36x^2-12x-36x^2+27x=30\)
\(\Leftrightarrow15x=30\)
\(\Rightarrow x=2\)
Bài 1:
b: =x^2-10x+x-10
=(x-10)(x+1)
c: \(=2x^2-5x+2x-5=\left(2x-5\right)\left(x+1\right)\)
d: \(=3x^2+5x-3x-5=\left(3x+5\right)\left(x-1\right)\)
e: \(=\left(2x+y\right)^3\)