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\(a,2x-6< 0\Leftrightarrow2x>6\Leftrightarrow x>3\)
\(b,5x+2x< 4+25\Leftrightarrow7x< 29\Leftrightarrow x< \frac{29}{7}\)
\(c,-5x+6>8-10+8x\Leftrightarrow-5x-8x>8-10-6\)
\(-13x>-8\Leftrightarrow x< \frac{8}{13}\)
\(d,3x-12\le2-4x\Leftrightarrow3x+4x\le2+12\)
\(\Leftrightarrow7x\le14\Leftrightarrow x\le2\)
\(e,\frac{3\left(x-3\right)}{6}>\frac{2\left(2x-5\right)}{6}+\frac{6}{6}\Rightarrow3x-9>4x-10+6\)
\(\Leftrightarrow3x-4x>-4+9\Leftrightarrow x>-5\)
\(f,3\left(2x-3\right)>1+2\left(2+2x\right)\Leftrightarrow6x-9>1+4+4x\)
\(6x-4x>14\Leftrightarrow2x>14\Leftrightarrow x>7\)
Tự biểu diễn nha!
nhiều thế
a) \(\frac{5x-2}{2}\ge\frac{3-x}{3}\Leftrightarrow\frac{3\left(5x-2\right)}{6}\ge\frac{2\left(3-x\right)}{6}\Leftrightarrow15x-6\ge6-2x\Leftrightarrow x\ge\frac{12}{17}\)
0 [ 12/17
a) 4x - 5 >0
\(\Leftrightarrow\)4x>5
\(\Leftrightarrow\)x>\(\frac{5}{4}\)
vậy s={x/x>\(\frac{5}{4}\)}
b) −23x−4>0
\(\Leftrightarrow\)-23x>4
\(\Leftrightarrow\)x<\(\frac{4}{23}\)
vậy s={x/x<\(\frac{4}{23}\)}
tối rồi nên lúc khác làm tiếp
a) 7x - 35 = 0
<=> 7x = 0 + 35
<=> 7x = 35
<=> x = 5
b) 4x - x - 18 = 0
<=> 3x - 18 = 0
<=> 3x = 0 + 18
<=> 3x = 18
<=> x = 5
c) x - 6 = 8 - x
<=> x - 6 + x = 8
<=> 2x - 6 = 8
<=> 2x = 8 + 6
<=> 2x = 14
<=> x = 7
d) 48 - 5x = 39 - 2x
<=> 48 - 5x + 2x = 39
<=> 48 - 3x = 39
<=> -3x = 39 - 48
<=> -3x = -9
<=> x = 3
a, \(2+\frac{2\left(x+3\right)}{6}\le2-\frac{x-3}{5}\)
\(\Leftrightarrow\frac{60+10\left(x+3\right)}{30}\le\frac{60-6\left(x-3\right)}{30}\Leftrightarrow60+10x+30\le60-6x+18\)
\(\Leftrightarrow90+10x\le78-6x\Leftrightarrow12\le-16x\Leftrightarrow x\ge-\frac{12}{16}=-\frac{3}{4}\)
b, \(\frac{3-5x}{-4}\le0\Leftrightarrow3-5x\le0\left(-4\le0\right)\Leftrightarrow x\ge\frac{3}{5}\)
c, \(\frac{2x+1}{2}+3\ge\frac{3-5x}{3}-\frac{4x+1}{4}\)
\(\Leftrightarrow\frac{12x+6-36}{12}\ge\frac{12-20x-12x-3}{12}\Leftrightarrow12x-30\ge-32x+9\)
\(\Leftrightarrow44x\le39\Leftrightarrow x\le\frac{39}{44}\)
d, MTC là 18 quy đồng lên nhé