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a,\(\left(3x-4\right).2^3=64\)
(=) \(\left(3x-4\right)=64:8\)
(=) \(3x-4=8\)
(=) \(3x=8+4\)
(=) \(3x=12\)
(=) \(x=12:3\)
(=) \(x=4\)
b, Ta có \(2^3.3^2-4x=4^3\)
(=) \(8.9-4x=64\)
(=) \(72-4x=64\)
(=) \(4x=72-64\)
(=) \(4x=8\)
(=) \(x=8:4\)
(=) \(x=2\)
a) ( 3x - 4 ) . 23 = 64
=> ( 3x - 4 ) = 64 : 23
=> ( 3x - 4 ) = 26 : 23
=> ( 3x - 4 ) = 23
=> 3x - 4 = 8
=> 3x = 12
=> x = 4
b) 23 . 32 - 4x = 43
=> 8 . 9 - 4x = 64
=> 72 - 4x = 64
=> 4x = 8
=> x = 2
a: \(\Leftrightarrow\left(x-1\right)\left(x-2\right)\cdot x=0\)
hay \(x\in\left\{0;1;2\right\}\)
b: =>3x-1=11 hoặc 3x-1=-11
=>3x=12 hoặc 3x=-10
=>x=4 hoặc x=-10/3
c: =>2x+1=3
=>2x=2
hay x=1
d: =>x-2=2
hay x=4
e: =>x+2=7
hay x=5
a)(x-1)5=(-32)=(-2)5
=>x-1=-2
x=-2+1
x=-1
b)(23/4)*2x+1=64
(8/4)*2x+1=64
2*2x+1=64
2x+1+1=26
=>x+2=6
x=6-2
x=4
b) \(2^x=32^5\cdot64^6\)
\(2^x=32^5\cdot\left(2\cdot32\right)^6\)
\(2^x=32^5\cdot2^6\cdot32^6\)
\(2^x=32^{11}\cdot2^6\)
\(2^x=32^{11}\cdot32\cdot2\)
\(2^x=32^{12}\cdot2\)
\(2^x=\left(2^5\right)^{12}\)
\(2^x=2^{60}\)
\(=>x=60\)
\(2^{10}.2^{x+4}=64^5\)
\(\Leftrightarrow2^{x+14}=2^{30}\)
\(\Leftrightarrow x+14=30\)
\(\Leftrightarrow x=16\)
\(5^x+5^{x+3}=630\)
\(\Rightarrow5^x.1+5^x.125=630\)
\(\Rightarrow5^x.126=630\)
\(\Rightarrow5^x=5\)
\(\Rightarrow x=1\)
\(x+\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+..............+\left(x+100\right)=7450\)
\(\Rightarrow\left(x+x+x+x+.........+x\right)+\left(1+2+3+..........+100\right)=7450\)
\(101x+5050=7450\)
Đến đây tự tính
Tìm x
a, ( 3x - 6 ) : 2 = 34
( 3x - 6 ) : 2 = 81
( 3x - 6 ) =162
3x =168
x =56
b,35 - 1 x = 5 . ( 2 3 - 4 )
35 - x =5 . ( 8 - 4 )
35 - x = 5 . 4
35 - x =20
x =15
Tính
a, 64 : ( 75 - 3 . 52 - 4 . 32 )
=64 : ( 75 - 75 - 36 )
=64 : ( -36 )
=\(\frac{-16}{9}\)
b,18 : 32 + 5 . 2 3
=18 : 9 + 5 . 8
=2 + 40
=42
d , ( x : 7 + 15 ) . 23 + 391 => Đề thiếu
e , ( 19 . x + 2 . 52 ) : 14 = ( 13 - 8 ) 2 - 42
=> ( 19 . x + 2 . 52 ) : 14 = 52 - 16
=> ( 19 . x + 2 . 52 ) : 14 = 25 - 16 = 9
=> 19 . x + 2 . 52 = 9 x 14 = 126
=> 19 . x + 2 . 25 = 126
=> 19 . x + 50 = 126
=> 19 . x = 126 - 50 = 76
=> x = 76 : 19 = 4
a. ( 3x - 4 ) . 23 = 64
( 3x - 4 ) . 2 = 4
3x - 4 = 2
3x = 6
x= 2
b. 2x = 32
2x = 25
x = 5
a, => (3x-4).23=43
=>(3x-4)=23
=> 3x= 8-4
=> 3x =4
=> 3/4