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a) => y+42+2y= -12-14+2y
y+2y-2y = -12-14-42
y= -68
b) => 15+y-5-5y= -12-5y
y-5y+5y= -12-15+5
y = -22
c) => 2y+5-8y+21= -3-5y-2
2y-8y+5y= -3-2-5-21
-y= -31=>y=31
d)=> -13+3y+23= -120+y
3y-y= -120+13-23
2y= -130=>y= -65
e) => -21+32+5y= 16+4y
5y-4y= 16+21-32
y= 5
bài 1
a)y-(-42-2y) = (-12) - 14 +2y
y +42 + 2y = -12 -14 +2y
3y + 42 = -26 +2y
y = -68
b)15-(-y+5)-5y=-(12+5y+2)
15+y-5-5y=-12-5y-2
10-4y=-14-5y
-4y+5y=-14-10=-24
c)2y-(-5+8y-21)=-3-(5y+2)
2y+5-8y+21=-3y-5y-2
-6y+26=-8y-2
-6y+8y=-2-26
2y=-28
y=-28/2=-14
Bài 2:
a: =6(15-5)=6*10=60
b: =9(-3+23)=9*20=180
c: =11(-10+210)=11*200=2200
d: =125*4+125*4=125*8=1000
1)
a/ \(12\left(x-5\right)+7\left(3-x\right)=15\)
\(\Rightarrow12x-12.5+7.3-7x=15\)
\(\Rightarrow12x-60+21-7x=15\)
\(\Rightarrow12x-7x=15+60-21\)
\(\Rightarrow5x=54\)
\(\Rightarrow x=\frac{54}{5}=10,8\)
b/ \(30\left(x+2\right)-6\left(x-5\right)-24x=100\)
\(\Rightarrow30x+30.2-6x-6.5-24x=100\)
\(\Rightarrow30x+60-6x+30-24x=100\)
\(\Rightarrow30x-6x-24x=100-60-30\)
\(\Rightarrow0x=10\)
\(\Rightarrow\) k có giá trị \(x\) nào thỏa mãn đề bài
\(12\left(x-5\right)+7\left(3-x\right)=15\)
\(12x-60+21-7x=15\)
\(12x-\left(60-21+7x\right)=15\)
\(12x-\left(39+7x=15\right)\)
\(12x-39-7x=15\)
\(5x=15+39\)
\(5x=54\)
\(x=10,8\)
Bài 1:
a) x.x.y.y.x.y.x = \(x^4.y^3\)
b) 1000.10.10= 1000. \(10^2\)
c) \(3^{15}:3^5=3^{15-5}=3^{10}\)
d) \(9^8:3=3^{16}:3=3^{15}\)
e) \(125:5^3=\dfrac{125}{5^3}=\dfrac{5^3}{5^3}=1\)
B2:
bài 1:
a) 1/3x=-5/3
x=-5
b) x+12/5=37/15
x=1/15
c) x-1/7=-36/7
x=-5
d) 3x-1/2=0
3x=1/2
x=1/6
e) 2/5+x=1/4
x=-3/20
a) 15 - x = 1 - ( -9 )
15 - x = 10
x = 15 - 10
x = 5 thuộc Z
vậy____
b) -2 | x | + 15 = 1
-2 | x | = 1 - 15
-2 | x | = - 14
| x | = -14 : (-2)
| x | = 7
\(\Rightarrow x=\pm7\) thuộc Z
vậy_____
c) -3 . | x + 4 | = -18
| x + 4 | = -18 : (-3)
| x + 4 | = 6
\(\Rightarrow\orbr{\begin{cases}x+4=6\\x+4=-6\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=2\in Z\\x=-10\in Z\end{cases}}\)
Vậy_____
d) ( x - 3 ) . ( x2 + 1 ) = 0
\(\Rightarrow\orbr{\begin{cases}x-3=0\\x^2+1=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=3\in Z\\x\in\varnothing\end{cases}}\)
vậy x = 3
e) 12 - ( 9 - 3x) = - 2 . ( x + 5 )
=> 12 - 9 + 3x = -2x + (-2).5
=> 3 + 3x = -2x + (-10)
=> 3x + 2x = (-10) - 3
=> 5x = -13
=> x = -13 : 5
=> x = \(\frac{-13}{5}\notin Z\)
=> \(x\in\varnothing\)
f) ( x - 2 )3 = - 125
\(\Rightarrow\left(x-2\right)^3=\left(-5\right)^3\)
\(\Rightarrow x-2=5\)
\(\Rightarrow x=7\in Z\)
vậy____
g) ( x + 6 ) = 81
=> x = 81 - 6
=> x = 75 thuộc Z
vậy_____
h) -12 : | x - 4 | = - 4
=> |x-4| = -12 : (-4)
=> |x-4| = 3
\(\Rightarrow\orbr{\begin{cases}x-4=3\\x-4=-3\end{cases}}\Rightarrow\orbr{\begin{cases}x=7\in Z\\x=1\in Z\end{cases}}\)
vậy_____
a) 15 - x = 1 - ( -9 )
15 - x = 10
x = 15 - 10
x = 5
b) -2 | x | + 15 = 1
-2 x = 1 -15
- 2 x = -14
x = -14 : ( -2 )
x = 7
c) -3 . | x + 4| = -18
| x + 4 | = ( - 18 ) : ( - 3 )
| x + 4 | = 6
=> \(\orbr{\begin{cases}x+4=6\\x+4=-6\end{cases}\Rightarrow\orbr{\begin{cases}x=6-4\\x=-6-4\end{cases}\Rightarrow}\orbr{\begin{cases}x=2\\x=-8\end{cases}}}\)
Vậy x = 2 hoặc -8
d) ( x - 3 ) . ( x2 + 1 ) = 0
=> \(\orbr{\begin{cases}x-3=0\\x^2+1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0+3\\x^2=0-1\end{cases}\Rightarrow}\orbr{\begin{cases}x=3\\x^2=-1\end{cases}\Rightarrow}\orbr{\begin{cases}x=3\\x=-1\end{cases}}}\)
Vậy x = 3 hoặc -1
c) \(2^5:x^5=2^{15}\)
\(x^5=2^5-2^{15}\)
\(x^5=2^{-10}\)
\(x^5=\frac{1}{1024}\)
\(x^5=\left(\frac{1}{4}\right)^5\)
\(\Rightarrow x=\frac{1}{4}=0,25\)
b) \(3x^2-15=12\)
\(3x^2=12+15\)
\(3x^2=27\)
\(x^2=27:3=9\)
\(\Rightarrow x^2=3^2\) hoặc \(x^2=\left(-3\right)^2\)
\(\Rightarrow x=3\) hoặc \(x=-3\)