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30 tháng 8 2022
a: =>2/3-1/3x+1/2-x-1/2=5
=>-4/3x+2/3=5
=>-4/3x=13/3
=>x=-13/4
b: \(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\x-\dfrac{3}{4}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{3}{4}\end{matrix}\right.\)
c: =>1/3x+3/5x+3/5=0
=>14/15x=-3/5
=>x=-3/5:14/15=-3/5x15/14=-45/70=-9/14
d: =>x>8/2
e: =>x:1/45=1/2
=>x=1/90
g: =>1/2:x=-2/15
=>x=-1/2:2/15=-15/4
TU
0
20 tháng 11 2022
a: =>|x+3/5|=|x-7/3|
=>x-7/3=x+3/5 hoặc x-7/3=-x-3/5
=>2x=-3/5+7/3=26/15
=>x=13/15
b: \(\Leftrightarrow\left|6x-1\right|=\left|3x-\dfrac{3}{2}\right|\)
=>6x-1=3x-3/2 hoặc 6x-1=3/2-3x
=>3x=-3/2+1=-1/2 hoặc 9x=5/2
=>x=-1/6 hoặc x=5/18
c: \(\Leftrightarrow\left|\dfrac{3}{2}x-3\right|=\left|\dfrac{15}{2}x+5\right|\)
=>3/2x-3=15/2x+5 hoặc 3/2x-3=-15/2x-5
=>-6x=8 hoặc 9x=-2
=>x=-2/9 hoặc x=-4/3
BV
5 tháng 9 2018
a, \((\frac{3}{7}-\frac{2}{3})\) .x =\(\frac{10}{21}\)
\(\frac{-5}{21}\).x=\(\frac{10}{21}\)
x= -2
Mk chỉ làm 1 phần các phằn còn lại tương tự
8 tháng 9 2019
a) -4/5 + 5/2x = -3/10
5/2x = -3/10 + 4/5
5/2x = 1/5
5/2x = 1/2
x = 1/2 : 5/2
x = 1/5
b) 4/3 + 5/8 : x = 1/12
5/8x = 1/12 - 4/3
5/8x = -5/4
5 = -5/4.8x
5 = -10x
5/-10 = x
-1/2 = x
x = -1/2
c) (x - 1/3)(x - 2/5) = 0
x - 1/3 = 0 hoặc x - 2/5 = 0
x = 0 + 1/3 x = 0 + 2/5
x = 1/3 x = 2/5
TT
1 tháng 10 2017
a. \(5.\left(x-2\right)+3.\left(x-2\right)=0\)
\(\Rightarrow8.\left(x-2\right)=0\)
\(\Rightarrow x-2=0:8\)
\(\Rightarrow x-2=0\)
\(\Rightarrow x=2\)
Vậy...
b. \(\dfrac{2}{3}+\dfrac{5}{2}:x=\dfrac{2}{4}\)
\(\Rightarrow\dfrac{5}{2}:x=\dfrac{2}{4}-\dfrac{2}{3}\)
\(\Rightarrow\dfrac{5}{2}:x=\dfrac{-1}{6}\)
\(\Rightarrow x=\dfrac{5}{2}:\dfrac{-1}{6}=-15\)
Vậy...
c. \(2.\left(x-\dfrac{1}{7}\right)=0\)
\(\Rightarrow x-\dfrac{1}{7}=0:2\)
\(\Rightarrow x-\dfrac{1}{7}=0\)
\(\Rightarrow x=\dfrac{1}{7}\)
Vậy...
d. \(\dfrac{11}{20}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\)
\(\Rightarrow\dfrac{2}{5}+x=\dfrac{11}{12}:\dfrac{2}{3}\)
\(\Rightarrow\dfrac{2}{5}+x=\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{1}{4}-\dfrac{2}{5}=\dfrac{-3}{20}\)
Vậy...
e. \(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
\(\Rightarrow\dfrac{1}{4}:x=\dfrac{2}{5}-\dfrac{3}{4}\)
\(\Rightarrow\dfrac{1}{4}:x=\dfrac{-7}{20}\)
\(\Rightarrow x=\dfrac{1}{4}:\dfrac{-7}{20}=\dfrac{-5}{7}\)
Vậy...
g. \(\dfrac{2}{3}x+\dfrac{5}{7}=\dfrac{3}{10}\)
\(\Rightarrow\dfrac{2}{3}x=\dfrac{3}{10}-\dfrac{5}{7}\)
\(\Rightarrow\dfrac{2}{3}x=\dfrac{-29}{70}\)
\(\Rightarrow x=\dfrac{-29}{70}:\dfrac{2}{3}=\dfrac{-87}{140}\)
Vậy...
a) \(\frac{2}{3}-\frac{1}{3}\left(x-\frac{3}{2}\right)-\frac{1}{2}\left(2x+1\right)=5\)
\(\Leftrightarrow-\frac{1}{3}\left(x-\frac{3}{2}\right)-\frac{1}{2}\left(2x+1\right)=5-\frac{2}{3}\)
\(\Leftrightarrow-\frac{1}{3}\left(x-\frac{3}{2}\right)-\frac{1}{2}\left(2x+1\right)=\frac{13}{3}\)
\(\Leftrightarrow-\frac{1}{3}\left(x-\frac{3}{2}\right).6-\frac{1}{2}\left(2x-1\right).6=\frac{13}{3}.6\)
\(\Leftrightarrow-2\left(x-\frac{3}{2}\right)-2\left(2x+1\right)=26\)
\(\Leftrightarrow-8x=26\)
\(\Leftrightarrow x=\frac{26}{-8}=\frac{13}{-4}\)
\(\Rightarrow x=-\frac{13}{4}\)
b) \(\left(x+\frac{1}{2}\right)\left(x-\frac{3}{4}\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+\frac{1}{2}=0\\x-\frac{3}{4}=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-\frac{1}{2}\\x=\frac{3}{4}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-\frac{1}{2}\\x=\frac{3}{4}\end{cases}}\)
c) \(\frac{1}{3}.x+\frac{2}{5}-\left(x+1\right)=0\)
\(\Leftrightarrow\frac{1}{3}.x+\frac{2}{5}-x-1=0\)
\(\Leftrightarrow\frac{x}{3}+\frac{2}{5}-x-1=0\)
\(\Leftrightarrow-\frac{2x}{3}=\frac{3}{5}\)
\(\Leftrightarrow x=\frac{3}{5}:-\frac{2}{3}\)
\(\Leftrightarrow x=-\frac{9}{10}\)
\(\Rightarrow x=-\frac{9}{10}\)