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Theo bài ra ta có: x+10=20,5
x=20,5-10=10,5
vì 10,5 không phải là số tự nhiên nên => A là tập hợp rỗng
chúc bạn học tốt nha
a) \(x\times x+372=472\)
\(x^2=100\)
\(x=10;-10\)
b) \(69,5-x\times x=20,5\)
\(69,5-x^2=20,5\)
\(-x^2+69,5=20,5\)
\(-x^2=-49\)
\(x^2=49\)
\(x=-7;7\)
c) \(x\times x-\dfrac{1}{6}=\dfrac{5}{18}\)
\(x^2=\dfrac{4}{9}\)
\(x=\dfrac{2}{3};-\dfrac{2}{3}\)
a,=11/12 x 8/15 - 1/6:2
= 22/45-1/2
= 73/180
b, =9/4:0.01
= 225
K nha
Bài 2:
a: =>|x-3|=x-3
=>x-3>=0
hay x>=3
b: =>-|x+3|<2-7=-5
=>|x+3|>5
=>x+3>5 hoặc x+3<-5
=>x>2 hoặc x<-8
c: \(\Leftrightarrow\left\{{}\begin{matrix}x>=-1\\\left(3x-2-x-1\right)\left(3x-2+x+1\right)=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x>=-1\\\left(2x-3\right)\left(4x-1\right)=0\end{matrix}\right.\Leftrightarrow x\in\left\{\dfrac{3}{2};\dfrac{1}{4}\right\}\)
d: \(\Leftrightarrow\left\{{}\begin{matrix}x< =7\\\left(x-3-7+x\right)\left(x-3+7-x\right)=0\end{matrix}\right.\)
=>x=5
a, \(\left(x-158\right):6=20\)
\(x-158=20.6\)
\(x-158=120\)
\(x=120+158\)
\(x=278\)
~~~Hok tốt~~~
a) \(\left(x-158\right):6=20\)
\(\Leftrightarrow x-158=\frac{20}{6}=\frac{10}{3}\)
\(\Leftrightarrow x=\frac{10}{3}+158\)
\(\Leftrightarrow x=\frac{484}{3}\)
Vậy : \(x=\frac{484}{3}\)
b) \(x-1,25.4=2,5\)
\(\Leftrightarrow x-5=2,5\)
\(\Leftrightarrow x=2,5+5\)
\(\Leftrightarrow x=7,5\)
Vậy : \(x=7,5\)
c) \(x+0,25=\frac{43}{4}-\frac{18}{5}\)
\(\Leftrightarrow x+\frac{1}{4}=\frac{143}{20}\)
\(\Leftrightarrow x=\frac{143}{20}-\frac{1}{4}\)
\(\Leftrightarrow x=\frac{69}{10}\)
Vậy : \(x=\frac{69}{10}\)
a, 0,25 - x = -0,75
x = 0,25 - -0,75
x = 1
b,x:(-3)= -\(\frac{2}{3}\)
x = -\(\frac{2}{3}\) >< -3
x = -2
c,(1,1.x-9).\(\frac{2}{5}\)=80%
1,1 >< x -9 = \(\frac{80}{100}\) : \(\frac{2}{5}\)
1,1 >< x -9 = 2
1,1 >< x = 2 + 9
1,1 >< x = 11
x =11 : 1,1
x = 10
d,2.x-30%.x=-1,7
x >< (2-0,3)=1,7
x >< 0,7 = 1,7
x = 1,7 : 0,7
x = 2.42857142857
\(\frac{3}{4}+\frac{1}{4}\cdot x+x-\frac{7}{6}\cdot x=\frac{5}{12}\)
\(\frac{3}{4}+\frac{1}{4}\cdot x-\frac{7}{6}\cdot x+x\cdot1=\frac{5}{12}\)
\(\frac{3}{4}+x\left(\frac{1}{4}-\frac{7}{6}+1\right)=\frac{5}{12}\)
\(\frac{3}{4}+x\cdot\frac{1}{12}=\frac{5}{12}\)
\(x\cdot\frac{1}{12}=\frac{5}{12}-\frac{3}{4}\)
\(x\cdot\frac{1}{12}=\frac{5}{12}-\frac{9}{12}\)
\(x\cdot\frac{1}{12}=\frac{-1}{3}\)
\(x=\frac{-1}{3}\text{ : }\frac{1}{12}\)
\(x=\frac{-1}{3}\cdot12\)
\(x=\frac{-12}{3}\)
\(x=-4\)
\(\text{b, }0,25\cdot x-\frac{2}{3}\cdot x=-1\frac{1}{6}\)
\(\frac{1}{4}\cdot x-\frac{2}{3}\cdot x=\frac{-7}{6}\)
\(x\cdot\left(\frac{1}{4}-\frac{2}{3}\right)=\frac{-7}{6}\)
\(x\cdot\frac{-5}{12}=\frac{-7}{6}\)
\(x=\frac{-7}{6}\text{ : }\frac{-5}{12}\)
\(x=\frac{-7}{6}\cdot\frac{12}{-5}\)
\(x=\frac{-14}{-5}\)
5 x X + X : 0,25 + X : 0,125 = 170
<=> 5 x X + X x 4 + X x 8 = 170
=> X x (5 + 4 + 8) = 170
=> X x 17 = 170
=> X = 170 : 17
=> X = 10
\(5x+x:0,25+x:0,125=170\)
\(5x+x.4+x.8=170\)
\(x\left(5+4+8\right)=170\)
\(17x=170\)
\(\Rightarrow x=10\)
a.
\(1,25\times4-x=2,5\)
\(5-x=2,5\)
\(x=5-2,5\)
\(x=2,5\)
b.
\(\left(158-x\right)\div7=20\)
\(158-x=20\times7\)
\(158-x=140\)
\(x=158-140\)
\(x=18\)
c.
\(x-0,25=\frac{43}{4}-\frac{18}{5}\)
\(x-\frac{1}{4}=\frac{43}{4}-\frac{18}{5}\)
\(x=\frac{43}{4}-\frac{18}{5}+\frac{1}{4}\)
\(x=\left(\frac{43}{4}+\frac{1}{4}\right)-\frac{18}{5}\)
\(x=\frac{44}{4}-\frac{18}{5}\)
\(x=11-\frac{18}{5}\)
\(x=\frac{37}{5}\)
a. 1,25 × 4 - x = 2,5
5- x= 2,5
x= 5-2,5
x=2,5
b.(158- x) :7= 20
158- x= 20x7
158 -x= 140
x=158- 140
x=18
c. x- 0,25= \(\frac{43}{4}+\frac{18}{5}\)
x- 0,25=14,35
x= 14,35+ 0,25
x=14,6
A=(20,5x0,25+18,225x5):0,05
=96,25:0,05
=1925
Ủng hộ mk nkoa!!!^_^
A = (20,5 x 0,25 + 18,225 x 5) : 0,05
A = ( 5,125 + 91,125 ) : 0,05
A = 96,25 : 0,05
A = 1925