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18/5 + 1 = 18/5 + 5/5 = 23/5 = 161/7
1 + 30/7 = 7/7 + 30/7 = 37/7 = 185/7
vậy ta có: \(\frac{161}{7}\)< x < \(\frac{185}{7}\)
x = \(\frac{162}{7};\frac{163}{7};....;\frac{184}{7}\)
18/5 + 1 = 18/5 + 5/5 = 23/5 = 161/7
1 + 30/7 = 7/7 + 30/7 = 37/7 = 185/7
vậy ta có: $\frac{161}{7}$1617 < x < $\frac{185}{7}$1857
x = $\frac{162}{7};\frac{163}{7};....;\frac{184}{7}$1627 ;1637 ;....;1847
\(\frac{18}{5}+1=\frac{23}{5}=\frac{23\cdot7}{5\cdot7}=\frac{161}{35}\)
\(\frac{30}{7}+1=\frac{37}{7}=\frac{37\cdot5}{7\cdot5}=\frac{185}{35}\)
=>161/35<x<185/35
=>x=162/35 ;163/35 ;..............184/35
18/5 + 1=23/5
1+30/7=37/7
Quy đòng tử 23/5 và 37/7 được 851/185 và 851/161
Vậy x = 851/184;851/183;.....;851/162
\(\frac{x}{7}< \frac{5}{7}\)
\(\Rightarrow x=4,3,2,1,0\)
\(\frac{15}{8}>\frac{x}{8}\)
\(\Rightarrow x=14;13;12;11;10;9;8;7;6;5;4;3;2;1;0\)
\(1< \frac{x}{9}< \frac{16}{9}\)
\(\Rightarrow x=10;11;12;13;14;15\)
học tốt
\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)\)= \(\frac{2-1}{2}.\frac{3-1}{3}.\frac{4-1}{4}\)= \(\frac{1}{2}.\frac{2}{3}.\frac{3}{4}\)= \(\frac{1.2.3}{2.3.4}=\frac{1}{4}\)
\(\left(1+\frac{1}{2}\right):\left(1+\frac{1}{3}\right):\left(1+\frac{1}{4}\right)\)= \(\frac{2+1}{2}:\frac{3+1}{3}:\frac{4+1}{4}\)= \(\frac{3}{2}:\frac{4}{3}:\frac{5}{4}=\frac{3}{2}.\frac{3}{4}.\frac{4}{5}=\frac{3.3.4}{2.4.5}=\frac{3.3}{2.5}=\frac{9}{10}\)
\(\frac{6}{5}-\frac{4}{5}.\frac{4}{8}+1=\frac{6}{5}+1-\frac{4.4}{5.8}=\frac{6+5}{5}-\frac{4}{5.2}=\frac{11}{5}-\frac{2}{5}=\frac{9}{5}\)
x < \(\frac{3}{4}+\frac{4}{5}=\frac{15}{20}+\frac{16}{20}=\frac{31}{20}=\frac{20}{20}+\frac{11}{20}=1\frac{11}{20}\)=> x = 0 ; 1
\(\frac{1}{2}+\frac{2}{3}< x< 4-\frac{5}{4}\)<=> \(\frac{3}{6}+\frac{4}{6}< x< \frac{16}{4}-\frac{5}{4}\)<=> \(\frac{7}{6}< x< \frac{11}{4}\)=> \(\frac{14}{12}< \frac{12x}{12}< \frac{33}{12}\)
=> 14 < 12x < 33 => 12x = 24 => x = 24 : 12 = 2
mìn chưa học