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(3.x)^2 : 3^3=243
9.x^2 : 27=243
9.x^2=243.27
9.x^2=6561
x^2=6561:9
x^2=729
X=27
=>3x=((32)8/(33)3).(34)2
=>3x=(316/39).38
=>3x=37.38
=>3x=315
=>x=15
\(10.3^x=81\)
\(3^x=80:10\)
\(3^x=8\)
\(\Rightarrow3^x=\varnothing\)
\(20-\left(x-1\right)^3=\frac{1}{16}\)
\(\left(x-1\right)^3=20-\frac{1}{16}\)
\(\left(x-1\right)^3=\frac{320}{16}-\frac{1}{16}\)
\(\left(x-1\right)^3=\frac{319}{16}\)
\(\Rightarrow\left(x-1\right)^3=\varnothing\Leftrightarrow x=\varnothing\)
a,<=>\(x=\left(\frac{3}{5}\right)^2\)
<=>\(x=\frac{9}{25}\)
b,<=>\(x=-\frac{1}{3}\)
\(a,\left(\frac{3}{5}\right)^5.x=\left(\frac{3}{5}\right)^7\)
\(\Leftrightarrow x=\left(\frac{3}{5}\right)^7:\left(\frac{3}{5}\right)^5\)
\(\Leftrightarrow x=\left(\frac{3}{5}\right)^2=\frac{9}{25}\)
\(b,\left(-\frac{1}{3}\right)^3.x=\frac{1}{81}\)
\(\Leftrightarrow x=-\left[\left(\frac{1}{3}\right)^4:\left(\frac{1}{3}\right)^3\right]\)
\(\Leftrightarrow x=-\frac{1}{3}\)
3x*3x-2=81
\(\Rightarrow3^{x+x-2}=81\)
\(\Rightarrow3^{2x-2}=3^4\)
\(\Rightarrow2x-2=4\)
\(\Rightarrow2x=6\Rightarrow x=3\)
\(3^x.3^{x-2}=81\)
\(\Rightarrow3^x.3^x:3^2=81\)
\(\Rightarrow3^{2x}=729\)
\(\Rightarrow3^{2x}=3^6\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
Vậy x = 3
81 = x³
x = ∛81
x = 3∛3