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\(7,5x:\left(9-\frac{139}{21}\right)=\frac{63}{25}\)
\(7,5x:\left(\frac{189}{21}-\frac{139}{21}\right)=\frac{63}{25}\)
\(7,5x:\left(\frac{50}{21}\right)=\frac{63}{25}\)
\(7,5x=\frac{63}{25}.\frac{50}{21}\)
\(7,5x=6\)
\(x=6:7,5\)
\(x=\frac{4}{5}\)
vậy \(x=\frac{4}{5}\)
k mk nha vì mk đang âm điểm
Giải:
\(7,5x:\left(9-6\dfrac{13}{21}\right)=2\dfrac{13}{25}\)
\(\Leftrightarrow7,5x:\left(9-\dfrac{139}{21}\right)=\dfrac{43}{25}\)
\(\Leftrightarrow7,5x:\dfrac{50}{21}=\dfrac{43}{25}\)
\(\Leftrightarrow7,5x=\dfrac{43}{25}.\dfrac{50}{21}\)
\(\Leftrightarrow7,5x=\dfrac{86}{21}\)
\(\Leftrightarrow x=\dfrac{86}{21}:7,5\)
\(\Leftrightarrow x=\dfrac{172}{315}\)
Vậy ...
7,5x:\(\frac{50}{21}\)=\(\frac{64}{25}\)
7,5x = \(\frac{64}{25}.\frac{50}{21}\)
7,5x = \(\frac{128}{21}\)
x = \(\frac{128}{21}:7,5\)
x = \(\frac{256}{315}\)
\(7,5x:\left[9-6\frac{13}{21}\right]=2\frac{13}{25}\)
\(\Leftrightarrow7,5x:\left[9-\frac{139}{21}\right]=\frac{63}{25}\)
\(\Leftrightarrow7,5x:\frac{50}{21}=\frac{63}{25}\)
\(\Leftrightarrow7,5x=\frac{63}{25}.\frac{50}{21}\)
\(\Leftrightarrow7,5x=6\)
\(\Leftrightarrow x=6:7,5\)
\(\Leftrightarrow x=\frac{4}{5}=0,8\)
(Chúc bạn học tốt và tíck cho mìk vs nha!)
\(a,2\frac{x}{7}=\frac{75}{35}\)
\(\frac{75}{35}=2\frac{5}{35}=2\frac{1}{7}\)
\(\Rightarrow x=1\)
\(b,47:4=...\left(+3\right)\)
\(\Rightarrow\left(47-3\right):4=11\)
\(\Rightarrow x=11\)
\(c,\frac{112}{5}=\frac{336}{15}=22\left(+6\right)\)
\(\Rightarrow x=22\frac{x=6}{15}\)
\(d,7,5x=\frac{75x}{100}:\left(9-6\frac{13}{21}\right)=2\frac{13}{25}\)
\(\frac{75x}{100}:\left(9-\frac{139}{21}\right)=\frac{63}{25}\)
\(\frac{75x}{100}:\frac{50}{21}=\frac{63}{25}\)
\(\Rightarrow\frac{63^3}{25^{\left(1\right)}}\cdot\frac{50^{\left(2\right)}}{21^1}=6=\frac{6}{1}\)
\(\Rightarrow\frac{6}{1}=\frac{600}{100}\)
Con d sai đề
a: Đề sai rồi bạn
b: \(\dfrac{\left(1.16-x\right)\cdot5.25}{\left(10+\dfrac{5}{9}-7-\dfrac{1}{4}\right)\cdot\dfrac{36}{17}}=\dfrac{3}{4}\)
\(\Leftrightarrow21\left(1.16-x\right)=3\cdot\dfrac{36}{17}\cdot\left(3+\dfrac{5}{9}-\dfrac{1}{4}\right)\)
\(\Leftrightarrow21\left(1.16-x\right)=\dfrac{108}{17}\cdot\dfrac{108+20-9}{36}\)
\(\Leftrightarrow21\cdot\left(1.16-x\right)=21\)
=>1,16-x=1
hay x=0,16
\(x:(3\frac{1}{2}-5\frac{1}{6})=4\frac{1}{5}-6\frac{2}{3}\) b,\((2\frac{1}{3}+3\frac{1}{2})\cdot x=-4\frac{1}{4}+3\frac{1}{7}\)
\(x:\frac{-5}{3}\)=\(\frac{-37}{15}\) \(\frac{35}{6}\cdot x=\)\(\frac{-31}{28}\)
\(x=\frac{-37}{15}\cdot\frac{-5}{3}\) \(x=\frac{-31}{28}:\)\(\frac{35}{6}\)
\(x=\frac{37}{9}\) \(x=\frac{-93}{490}\)
Vậy x=\(\frac{37}{9}\) Vậy x=\(\frac{-93}{490}\)
7,5x:\((9-6\frac{13}{21})=2\frac{13}{25}\)
7,5x:\(\frac{50}{21}\)=\(\frac{63}{25}\)
7,5x=\(\frac{63}{25}:\frac{50}{21}=\frac{1323}{1250}\)
x=\(\frac{1323}{1250}:7,5\)
x=\(\frac{441}{3125}\)
Vậy x=\(\frac{441}{3125}\)
lấy máy tính tính cho nhanh dùng cái lệnh solve đó