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\(\left(792,81\cdot0,25+792,81\cdot0,75\right)\cdot\left(11\cdot9-900\cdot0,1-9\right)\)
\(=792,81\cdot\left(0,25+0,75\right)\cdot\left(11\cdot9-9\cdot10-9\right)\)
\(=792,81\cdot1\cdot9\cdot\left(11-10-1\right)\)
\(=792,81\cdot9\cdot0\\ =0\)
\(=\left(2012x\frac{1}{4}+2012x\frac{3}{4}\right)x\left(11x9-90-9\right)\)
\(=2012x\left(\frac{1}{4}+\frac{3}{4}\right)x\left(11x9-10x9-9x1\right)\)
\(=2012x9x\left(11-10-1\right)\)
=\(2012x9x0\)
=0
Chúc bn học giỏi, k cho mình nhé!!!
= (2012 x 0,25 + 2012 x 0,75) x (99 - 90 - 9 )
= (2012 x 0,25 + 2012 x 0,75) x ( 9 - 9)
=(2012 x 0,25 + 2012 x 0,75) x 0
= 0
(3721 x 1,3 + 3570 : 35) x (11 x 9 - 900 x 0,1 - 9)
= (3721 x 1,3 + 3570 : 35) x ( 99 - 90 - 9)
= ( 3721 x 1,3 + 3570 : 35) x 0
= 0
(3721X1,3+3570:35)X(11X9-900X0,1-9)=(4837,3+102)X(99-90-9)
=> Vế trước nhân 0 vậy kết quả bằng 0
(792,81x0,25+792,81x0,75)x(11x9-900x0,1-9)
=792,81x(0,25+0,75)x(999-81)
=792,81x100x918
=79281x918
=72779958
tk minh nha
\(\left(123\text{ ×}0,25+123\text{ ×}0,75\right)\text{ ×}\left(11\text{ ×}9-900\text{ ×}0,1-9\right)\)
\(=\left(123\text{×}0,25+123\text{×}0,75\right)\text{ ×}\left(11\text{×}9-9\text{×}100\text{×}0,1-9\text{×}1\right)\)
\(=\left(123\text{×}0,25+123\text{×}0,75\right)\text{ ×}\left(11\text{×}9-9\text{×}10-9\text{×}1\right)\)
\(=\left[123\left(0,25+0,75\right)\right]\text{×}\left[9\text{×}\left(11-10-1\right)\right]\)
\(=\left(123\text{×}1\right)\text{×}\left(9\text{×}0\right)=123\text{×}0=0\)
(123 ×0,25+123 ×0,75) ×(11 ×9−900 ×0,1−9)
=\left(123\text{×}0,25+123\text{×}0,75\right)\text{ ×}\left(11\text{×}9-9\text{×}100\text{×}0,1-9\text{×}1\right)=(123×0,25+123×0,75) ×(11×9−9×100×0,1−9×1)
=\left(123\text{×}0,25+123\text{×}0,75\right)\text{ ×}\left(11\text{×}9-9\text{×}10-9\text{×}1\right)=(123×0,25+123×0,75) ×(11×9−9×10−9×1)
=\left[123\left(0,25+0,75\right)\right]\text{×}\left[9\text{×}\left(11-10-1\right)\right]=[123(0,25+0,75)]×[9×(11−10−1)]
=\left(123\text{×}1\right)\text{×}\left(9\text{×}0\right)=123\text{×}0=0=(123×1)×(9×0)
=123×0
=0
\(\left(\frac{9}{10}+\frac{1}{10}\div\frac{4}{5}\right)\times\left(\frac{3}{15}-\frac{2}{15}\times\frac{4}{3}\times\frac{9}{8}\right)\)
\(=\left(1\div\frac{4}{5}\right)\times\left(\frac{3}{15}-\frac{1}{5}\right)\)
\(=\frac{5}{4}\times0\)
\(=0\)
\(\frac{3}{4}\)x \(2\frac{3}{9}\)+ 45,8 x 0,07
= 0,75 x \(\frac{21}{9}\)+ 45,8 x 0,07
= 1,75 + 3,206
= 4,956
\(\frac{3}{4}\)x \(2\frac{3}{9}\)+ 45, 8 x 0, 07
= \(\frac{3}{4}\)x \(\frac{7}{3}\)+ 45, 8 x 0, 07
= 1, 75 + 0, 206
= 4, 956
4-\(\frac{4}{9}\)- [\(2\frac{1}{4}\)+1\(\frac{4}{9}\)]
=\(4-\frac{4}{9}-2\frac{1}{4}-1\frac{4}{9}\)
=\(\left(4-2\frac{1}{4}\right)-\left(\frac{4}{9}-1\frac{4}{9}\right)\)
=\(1\frac{3}{4}-\left(-1\right)\)
=\(2\frac{3}{4}\)