Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
* Trả lời:
\(\left(1\right)\) \(-3\left(1-2x\right)-4\left(1+3x\right)=-5x+5\)
\(\Leftrightarrow-3+6x-4-12x=-5x+5\)
\(\Leftrightarrow6x-12x+5x=3+4+5\)
\(\Leftrightarrow x=12\)
\(\left(2\right)\) \(3\left(2x-5\right)-6\left(1-4x\right)=-3x+7\)
\(\Leftrightarrow6x-15-6+24x=-3x+7\)
\(\Leftrightarrow6x+24x+3x=15+6+7\)
\(\Leftrightarrow33x=28\)
\(\Leftrightarrow x=\dfrac{28}{33}\)
\(\left(3\right)\) \(\left(1-3x\right)-2\left(3x-6\right)=-4x-5\)
\(\Leftrightarrow1-3x-6x+12=-4x-5\)
\(\Leftrightarrow-3x-6x+4x=-1-12-5\)
\(\Leftrightarrow-5x=-18\)
\(\Leftrightarrow x=\dfrac{18}{5}\)
\(\left(4\right)\) \(x\left(4x-3\right)-2x\left(2x-1\right)=5x-7\)
\(\Leftrightarrow4x^2-3x-4x^2+2x=5x-7\)
\(\Leftrightarrow-x-5x=-7\)
\(\Leftrightarrow-6x=-7\)
\(\Leftrightarrow x=\dfrac{7}{6}\)
\(\left(5\right)\) \(3x\left(2x-1\right)-6x\left(x+2\right)=-3x+4\)
\(\Leftrightarrow6x^2-3x-6x^2-12x=-3x+4\)
\(\Leftrightarrow-15x+3x=4\)
\(\Leftrightarrow-12x=4\)
\(\Leftrightarrow x=-\dfrac{1}{3}\)
7) | 1/4x - 3/4| = 4/ 5 x- 2/5
Th1:
1/4x - 3/4 = 4/ 5 x- 2/5
1/4x - 4/5x = -2/5 + 3/4
-11/20x = 7/20
x= -7/11
Th2:
1/4x - 3/4 = -(4/ 5 x- 2/5)
1/4x + 4/5x = 3/4 + 2/5
21/20x = 23/20
x= 23/21
Vậy...
8) | 2x-1| =x
Th1:
2x -1 = x
x= 1
Th2:
2x -1 = -x
3x = 1
x= 1/3
Vậy...
9) | x+ 2| = 2x
Th1:
x+2 = 2x
x= 2
Th2:
x+2 = -2x
3x =2
x= 2/3
Vậy...
7) | 1/4x - 3/4| = 4/ 5 x- 2/5
Th1:
1/4x -3/4 = 4/5x -2/5
1/4x - 4/5x = -2/5 + 3/4
(1/4 - 4/5)x = 7/20
-11/20x = 7/20
x= 7/20 : (-11/20)
x= -7/11
Th2:
1/4x - 3/4 = -(4/5x - 2/5)
1/4x - 3/4 = -4/5x + 2/5
1/4x + 4/5x = 2/5 + 3/4
(1/4 + 4/5)x = 23/20
21/20x = 23/20
x= 23/20 : 21/20
x= 23/21
8) | 2x-1| =x
Th1:
2x -1 = x
2x - x= 1
(2-1)x=1
x= 1
Th2:
2x -1 = -x
2x +x = 1
(2+1)x =1
3x =1
x= 1:3
x= 1/3
Vậy...
Còn câu 9 chiều gửi cho
7) \(| \frac{1}{4}x - \frac{3}{4}| = \frac{4}{5}x- \frac{2}{5}\)
\(\Rightarrow\orbr{\begin{cases}\frac{1}{4}x-\frac{3}{4}=\frac{4}{5}x-\frac{2}{5}\\-\frac{1}{4}x+\frac{3}{4}=\frac{4}{5}x-\frac{2}{5}\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}\frac{21}{20}x=\frac{23}{20}\\\frac{11}{20}x=-\frac{7}{20}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{23}{21}\\x=-\frac{7}{11}\end{cases}}\) Vậy: \(x=\frac{23}{21};-\frac{7}{11}\)
8) \(| 2x-1| =x\)
\(\Rightarrow\orbr{\begin{cases}2x-1=x\\-2x+1=x\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=1\\-3x=-1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=1\\x=\frac{1}{3}\end{cases}}\) Vậy : \(x=1;\frac{1}{3}\)
9)\(| x+ 2| = 2x\)
\(\Rightarrow\orbr{\begin{cases}x+2=2x\\-x-2=2x\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}-x=-2\\-3x=2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=2\\x=-\frac{2}{3}\end{cases}}\) Vậy: \(x=2;-\frac{2}{3}\)
Noob ơi, bạn phải đưa vào máy tính ý solve cái là ra x luôn, chỉ tội là đợi hơi lâu
a, 4.(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14)
=> 72 - 20x - 36x + 84 = 30x - 240 - 6x - 84
=> (72 + 84) + (-20x - 36x) = (30x - 6x) + (-240 - 84)
=> 156 - 56x = 24x - 324
=> 24x + 56x = 324 + 156
=> 80x = 480
=> x = 480 : 80 = 6
Vậy x = 6
Căng, sự thật là nó rất căng
Nhg dù sao thì.....
1) \(A\left(x\right)=\left(x-4\right)^2-\left(2x+1\right)^2\)
Xét \(A\left(x\right)=0\)
\(\Rightarrow\left(x-4\right)^2-\left(2x+1\right)^2=0\)
\(\Rightarrow x^2-8x+16-4x^2-4x-1=0\)
\(\Rightarrow-3x^2-12x+15=0\)
\(\Rightarrow-3x^2+3x-15x+15=0\)
\(\Rightarrow-3x\left(x-1\right)-15\left(x-1\right)=0\)
\(\Rightarrow\left(x-1\right)\left(-3x-15\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-1=0\\-3x-15=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=1\\x=-5\end{matrix}\right.\)
2)(Sửa đề nha, sai cmnr) \(B\left(x\right)=x^3+x^2-4x-4\)
Xét \(B\left(x\right)=0\)
\(\Rightarrow x^3+x^2-4x-4=0\)
\(\Rightarrow x^2\left(x+1\right)-4\left(x+1\right)=0\)
\(\Rightarrow\left(x^2-4\right)\left(x+1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x^2-4=0\\x+1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\pm2\\x=-1\end{matrix}\right.\)
Đó là những j mình biết
1, \(\left(x-4\right)^2-\left(2x+1\right)^2=\left(x-4-2x-1\right)\left(x-4+2x+1\right)=-3\left(x+5\right)\left(x-1\right).\)
\(\orbr{\begin{cases}x+5=0\\x-1=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-5\\x=1\end{cases}}}\)(mấy cái này áp dụng hàng đẳng thức lớp 8 mới hok)
2,\(x^3+x^2-4x-4=\left(x-2\right)\left(x^2+3x+2\right)=\left(x-2\right)\left(x+1\right)\left(x+2\right)\)
\(\orbr{\begin{cases}x=\mp2\\\end{cases}}x=-1\)
tương tụ lm tiếp nhe buồn ngủ quá rồi !
câu 7 viết v k hiểu
câu 8: |2x-1|=x<=> \(\left[\begin{array}{nghiempt}2x-1=x\\2x-1=-x\end{array}\right.\)=> x=1 hoặc x=1/3
câu 9 |x+2|=2x<=> \(\left[\begin{array}{nghiempt}x+2=-2x\\x+2=2x\end{array}\right.\)=> x=-2/3 hặc x=-1/2
Câu 7 :
\(\left|\frac{1}{4}x-\frac{3}{4}\right|=\frac{4}{5}x-\frac{2}{5}\)
\(\Rightarrow\) \(\left[\begin{array}{nghiempt}-\frac{1}{4}x+\frac{3}{4}=\frac{4}{5}x-\frac{2}{5}\\\frac{1}{4}x-\frac{3}{4}=\frac{4}{5}x-\frac{2}{5}\end{array}\right.\) \(\Leftrightarrow\) \(\left[\begin{array}{nghiempt}\frac{21}{20}x=\frac{23}{20}\\\frac{11}{20}x=-\frac{7}{20}\end{array}\right.\)
\(\Leftrightarrow\) \(\left[\begin{array}{nghiempt}x=\frac{23}{21}\\x=-\frac{7}{11}\end{array}\right.\)
Cây 8) 9) dễ hơn, bạn làm tương tự