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\(\frac{5^4.20^4}{25^5.4^5}=\frac{5^4.5^4.4^4}{\left(5^2\right)^5.4^5}=\frac{5^8.4^4}{5^{10}.4^5}=\frac{1}{25.4}=\frac{1}{100}\)
\(\left(-\frac{10}{3}\right)^5.\left(-\frac{6}{5}\right)^4=\frac{-\left(2.5\right)^5}{3^5}.\frac{\left(3.2\right)^4}{5^4}=\frac{-2^5.5^5.3^4.2^4}{3^5.5^4}=\frac{-2^9.5}{3}\)
Ta có: \(\left(-\frac{10}{3}\right)^5.\left(-\frac{6}{5}\right)^4=\frac{\left(-10\right)^5}{3^5}.\frac{\left(-6\right)^4}{5^4}=\frac{\left(-2.5\right)^5}{3^5}.\frac{\left(-2.3\right)^4}{5^4}=\frac{\left(-2\right)^5.5^5}{3^5}.\frac{\left(-2\right)^5.3^4}{5^4}=\frac{\left(-2\right)^5.5^5.\left(-2\right)^4.3^4}{3^5.5^4}\)\(=\frac{\left[\left(-2\right)^5.\left(-2\right)^4\right].5^5.3^4}{3^5.5^4}=\frac{\left(-2\right)^9.5}{3}=\frac{-512.5}{3}=-\frac{2560}{3}\)
Chuk bn hk tốt!
54 . 204/255 . 45
TL:
\(\frac{5^4.20^4}{25^5.4^5}=\frac{5^4.5^4.4^4}{(5^2)^5.4^5}=\frac{5^85^4}{5^{10}.4^5}=\frac{1}{25.4}=\frac{1}{100}\)
Sửa đề:
\(\frac{5^4.20^4}{25^5.4^5}\)
\(=\)\(\frac{5^4.5^4.4^4}{\left(5^2\right)^5.4^5}\)
\(=\)\(\frac{5^8.4^4}{5^{10}.4^5}\)
\(=\)\(\frac{1}{25.4}\)
\(=\)\(\frac{1}{100}\)
\(\frac{5^4\times20^4}{25^5\times4^5}=\frac{100^4}{100^5}=0.01\)
Đúng ko bn
\(A=\frac{2^{19}3^9+5.2^{18}3^9}{3^9.2^9.2^{10}+3^{10}4^{10}}=\frac{3^9\left(2^{19}+5.2^{18}\right)}{3^92^{19}+3^{10}2^{20}}=\frac{3^9\left(2^{19}+5.2^{18}\right)}{3^9\left(2^{19}+3.2^{20}\right)}=\frac{2^{19}+5.2^{18}}{2^{19}+3.2^{20}}=\frac{2^{18}\left(2+5\right)}{2^{18}\left(2+3.2^2\right)}\)
\(=\frac{2+5}{2+3.2^2}=\frac{7}{14}=\frac{1}{2}\)
\(\frac{25^4\cdot7^2+5^8\cdot49}{5^8\cdot2^3-25^4}=\frac{5^8\cdot7^2+5^8\cdot7^2}{5^8\cdot2^3-5^8}=\frac{5^8\cdot7^2\cdot\left(1+1\right)}{5^8\cdot\left(2^3-1\right)}=\frac{2\cdot5^8\cdot7^2}{5^8\cdot7}=2\cdot7=14\)
\(\frac{5^4.20^4}{25^5.4^5}=\frac{5^4.5^4.4^4}{5^{10}.4^5}=\frac{5^8.4^4}{5^{10}.4^5}=\frac{1}{5^2.4}=\frac{1}{25.4}=\frac{1}{100}\)
\(\frac{5^4.20^4}{25^5.4^5}=\frac{5^4.4^4.5^4}{\left(5^2\right)^5.4^4.4}=\frac{5^4.4^4.5^4}{5^{10}.4^4.4}=\frac{5^4.4^4.5^4}{5^4.5^4.5^2.4^4.4}=\frac{1}{5^2.4}=\frac{1}{100}\)